Computer Systems: A Programmer's Perspective (3rd Edition)
3rd Edition
ISBN: 9780134092669
Author: Bryant, Randal E. Bryant, David R. O'Hallaron, David R., Randal E.; O'Hallaron, Bryant/O'hallaron
Publisher: PEARSON
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Expert Solution & Answer
Chapter 3.7, Problem 3.34PP
A.
Explanation of Solution
Data movement instructions:
- The different instructions are been grouped as “instruction classes”.
- The instructions in a class performs same operation but with different sizes of operand.
- The “Mov” class denotes data movement instructions that copy data from a source location to a destination.
- The class has 4 instructions that includes:
- movb:
- It copies data from a source location to a destination.
- It denotes an instruction that operates on 1 byte data size.
- movw:
- It copies data from a source location to a destination.
- It denotes an instruction that operates on 2 bytes data size.
- movl:
- It copies data from a source location to a destination.
- It denotes an instruction that operates on 4 bytes data size.
- movq:
- It copies data from a source location to a destination.
- It denotes an instruction that operates on 8 bytes data size.
- movb:
Unary and Binary Operations:
- The details of unary operations includes:
- The single operand functions as both source as well as destination.
- It can either be a memory location or a register.
- The instruction “incq” causes 8 byte element on stack top to be incremented.
- The instruction “decq” causes 8 byte element on stack top to be decremented.
- The details of binary operations includes:
- The first operand denotes the source.
- The second operand works as both source as well as destination.
- The first operand can either be an immediate value, memory location or register.
- The second operand can either be a register or a memory location.
Jump Instruction:
- The “jump” instruction causes execution to switch to an entirely new position in program.
- The “label” indicates jump destinations in assembly code.
- The “je” instruction denotes “jump if equal” or “jump if zero”.
- The comparison operation is performed...
B.
Explanation of Solution
Local values stored on stack:
- The instruction “movq %rax, (%rsp)” moves value of register “%rax” into stack location “%rsp”...
C.
Explanation of Solution
Program cannot store all local values in callee-saved registers:
- The supply of callee-saved registers has been used up after saving six local variables...
Expert Solution & Answer
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Students have asked these similar questions
4.1.1
Complete solution and answer only no need explanation
Given three data points (1,6), (3,28), and (10, 231), What is the value of y at x = 2 if the function y = 2x2 + 3x + 1 passes through the three data points.
li $t2, 2
L1:
add $t1, $t1, $t2
sub $t1, $t1, $t3
bne $t1, $t4, L1
sub $t4, $s0, $t3
Given the modified single-cycle processor shown below, what are the values (in binary) of instruction[31-26], instruction[25-21], instruction[20-16], instruction[15-11], instruction[5-0], Read data 1, Read data 2, ALU zero, PCSrc, and all the main control decoded output signals when the time is at 1950 ns. The below single-cycle processor diagram can be used for your reference.
Note: A new decoded signal output “Tzero” is added for executing “bne” instruction. The signal definition is described below:
Instruction
Opcode
New Main Control Output Signal
beq
00100b (4d)
Tzero = 0
bne
00101b (5d)
Tzero = 1
At the moment of 1950 ns, the below values (0, 1 or X) are:instruction[31-26] = instruction[25-21] = instruction[20-16] =instruction[15-0] =
Read data 1 output =
Read data 2 output =
RegDst =
ALUSrc =
MemtoReg =
RegWrite =…
1.BL=00, after instruction DEC BL is executed, CF =?
2.CH=80H; after ROL CH, 1; CH=?
Chapter 3 Solutions
Computer Systems: A Programmer's Perspective (3rd Edition)
Ch. 3.4 - Prob. 3.1PPCh. 3.4 - Prob. 3.2PPCh. 3.4 - Prob. 3.3PPCh. 3.4 - Prob. 3.4PPCh. 3.4 - Prob. 3.5PPCh. 3.5 - Prob. 3.6PPCh. 3.5 - Prob. 3.7PPCh. 3.5 - Prob. 3.8PPCh. 3.5 - Prob. 3.9PPCh. 3.5 - Prob. 3.10PP
Ch. 3.5 - Prob. 3.11PPCh. 3.5 - Prob. 3.12PPCh. 3.6 - Prob. 3.13PPCh. 3.6 - Prob. 3.14PPCh. 3.6 - Prob. 3.15PPCh. 3.6 - Prob. 3.16PPCh. 3.6 - Practice Problem 3.17 (solution page 331) An...Ch. 3.6 - Practice Problem 3.18 (solution page 332) Starting...Ch. 3.6 - Prob. 3.19PPCh. 3.6 - Prob. 3.20PPCh. 3.6 - Prob. 3.21PPCh. 3.6 - Prob. 3.22PPCh. 3.6 - Prob. 3.23PPCh. 3.6 - Practice Problem 3.24 (solution page 335) For C...Ch. 3.6 - Prob. 3.25PPCh. 3.6 - Prob. 3.26PPCh. 3.6 - Practice Problem 3.27 (solution page 336) Write...Ch. 3.6 - Prob. 3.28PPCh. 3.6 - Prob. 3.29PPCh. 3.6 - Practice Problem 3.30 (solution page 338) In the C...Ch. 3.6 - Prob. 3.31PPCh. 3.7 - Prob. 3.32PPCh. 3.7 - Prob. 3.33PPCh. 3.7 - Prob. 3.34PPCh. 3.7 - Prob. 3.35PPCh. 3.8 - Prob. 3.36PPCh. 3.8 - Prob. 3.37PPCh. 3.8 - Prob. 3.38PPCh. 3.8 - Prob. 3.39PPCh. 3.8 - Prob. 3.40PPCh. 3.9 - Prob. 3.41PPCh. 3.9 - Prob. 3.42PPCh. 3.9 - Practice Problem 3.43 (solution page 344) Suppose...Ch. 3.9 - Prob. 3.44PPCh. 3.9 - Prob. 3.45PPCh. 3.10 - Prob. 3.46PPCh. 3.10 - Prob. 3.47PPCh. 3.10 - Prob. 3.48PPCh. 3.10 - Prob. 3.49PPCh. 3.11 - Practice Problem 3.50 (solution page 347) For the...Ch. 3.11 - Prob. 3.51PPCh. 3.11 - Prob. 3.52PPCh. 3.11 - Practice Problem 3.52 (solution page 348) For the...Ch. 3.11 - Practice Problem 3.54 (solution page 349) Function...Ch. 3.11 - Prob. 3.55PPCh. 3.11 - Prob. 3.56PPCh. 3.11 - Practice Problem 3.57 (solution page 350) Function...Ch. 3 - For a function with prototype long decoda2(long x,...Ch. 3 - The following code computes the 128-bit product of...Ch. 3 - Prob. 3.60HWCh. 3 - In Section 3.6.6, we examined the following code...Ch. 3 - The code that follows shows an example of...Ch. 3 - This problem will give you a chance to reverb...Ch. 3 - Consider the following source code, where R, S,...Ch. 3 - The following code transposes the elements of an M...Ch. 3 - Prob. 3.66HWCh. 3 - For this exercise, we will examine the code...Ch. 3 - Prob. 3.68HWCh. 3 - Prob. 3.69HWCh. 3 - Consider the following union declaration: This...Ch. 3 - Prob. 3.71HWCh. 3 - Prob. 3.72HWCh. 3 - Prob. 3.73HWCh. 3 - Prob. 3.74HWCh. 3 - Prob. 3.75HW
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