EP PHYSICS F/SCI.+ENGR.W/MOD..-MOD MAST
4th Edition
ISBN: 9780133899634
Author: GIANCOLI
Publisher: PEARSON CO
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 37, Problem 48P
(a)
To determine
The wavelength of an electron of energy
(b)
To determine
The wavelength of an electron of energy
(c)
To determine
The wavelength of an electron of energy
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
(II) Show that the energy E (in electron volts) of a photon
whose wavelength is A (nm) is given by
1.240 x 10° eV·nm
E =
λ (nm)
Use at least 4 significant figures for values of h, c, e (see
inside front cover).
(c) The energy of an ultraviolet light is 3.28 eV.
(i) What is its wavelength? (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C).
(ii) Based on the de Broglie's hypothesis, determine the velocity of the electron. (Given: h=6.63✕10-34 Js ; me=9.11✕10-31 kg)
(i) How does one explain the emission of electrons from a photosensitive surface with the help of Einstein’s photoelectric equation?
(ii) The work function of the following metals is given : Na = 2.75 eV, K = 2.3 eV, Mo = 4.17 eV and Ni 5.15 eV. Which of these metals will not cause photoelectric emission for radiation of wavelength 3300 A from a laser source placed 1 m away from these metals? What happens if the laser source is brought nearer and placed 50 cm away?
Chapter 37 Solutions
EP PHYSICS F/SCI.+ENGR.W/MOD..-MOD MAST
Ch. 37.2 - Prob. 1AECh. 37.2 - Prob. 1BECh. 37.4 - Prob. 1CECh. 37.7 - Prob. 1DECh. 37.7 - Prob. 1EECh. 37.11 - Prob. 1FECh. 37 - Prob. 1QCh. 37 - Prob. 2QCh. 37 - Prob. 3QCh. 37 - Prob. 4Q
Ch. 37 - Prob. 5QCh. 37 - Prob. 6QCh. 37 - Prob. 7QCh. 37 - Prob. 8QCh. 37 - Prob. 9QCh. 37 - Prob. 10QCh. 37 - Prob. 11QCh. 37 - Prob. 12QCh. 37 - Prob. 13QCh. 37 - Prob. 14QCh. 37 - Prob. 15QCh. 37 - Prob. 16QCh. 37 - Prob. 17QCh. 37 - Prob. 18QCh. 37 - Prob. 19QCh. 37 - Prob. 20QCh. 37 - Prob. 21QCh. 37 - Prob. 22QCh. 37 - Prob. 23QCh. 37 - Prob. 24QCh. 37 - Prob. 25QCh. 37 - Prob. 26QCh. 37 - Prob. 27QCh. 37 - Prob. 28QCh. 37 - Prob. 1PCh. 37 - Prob. 2PCh. 37 - Prob. 3PCh. 37 - Prob. 4PCh. 37 - Prob. 5PCh. 37 - Prob. 6PCh. 37 - Prob. 7PCh. 37 - Prob. 8PCh. 37 - Prob. 9PCh. 37 - Prob. 10PCh. 37 - Prob. 11PCh. 37 - Prob. 12PCh. 37 - Prob. 13PCh. 37 - Prob. 14PCh. 37 - Prob. 15PCh. 37 - Prob. 16PCh. 37 - Prob. 17PCh. 37 - Prob. 18PCh. 37 - Prob. 19PCh. 37 - Prob. 20PCh. 37 - Prob. 21PCh. 37 - Prob. 22PCh. 37 - Prob. 23PCh. 37 - Prob. 24PCh. 37 - Prob. 25PCh. 37 - Prob. 26PCh. 37 - Prob. 27PCh. 37 - Prob. 28PCh. 37 - Prob. 29PCh. 37 - Prob. 30PCh. 37 - Prob. 31PCh. 37 - Prob. 32PCh. 37 - Prob. 33PCh. 37 - Prob. 34PCh. 37 - Prob. 35PCh. 37 - Prob. 36PCh. 37 - Prob. 37PCh. 37 - Prob. 38PCh. 37 - Prob. 39PCh. 37 - Prob. 40PCh. 37 - Prob. 41PCh. 37 - Prob. 42PCh. 37 - Prob. 43PCh. 37 - Prob. 44PCh. 37 - Prob. 45PCh. 37 - Prob. 46PCh. 37 - Prob. 47PCh. 37 - Prob. 48PCh. 37 - Prob. 49PCh. 37 - Prob. 50PCh. 37 - Prob. 51PCh. 37 - Prob. 52PCh. 37 - Prob. 53PCh. 37 - Prob. 54PCh. 37 - Prob. 55PCh. 37 - Prob. 56PCh. 37 - Prob. 57PCh. 37 - Prob. 58PCh. 37 - Prob. 59PCh. 37 - Prob. 60PCh. 37 - Prob. 61PCh. 37 - Prob. 62PCh. 37 - Prob. 63PCh. 37 - Prob. 64PCh. 37 - Prob. 65PCh. 37 - Prob. 66PCh. 37 - Prob. 67PCh. 37 - Prob. 68PCh. 37 - Prob. 69PCh. 37 - Prob. 70PCh. 37 - Prob. 71PCh. 37 - Prob. 72GPCh. 37 - Prob. 73GPCh. 37 - Prob. 74GPCh. 37 - Prob. 75GPCh. 37 - Prob. 76GPCh. 37 - Prob. 77GPCh. 37 - Prob. 78GPCh. 37 - Prob. 79GPCh. 37 - Prob. 80GPCh. 37 - Prob. 81GPCh. 37 - Prob. 82GPCh. 37 - Prob. 83GPCh. 37 - Prob. 84GPCh. 37 - Prob. 85GPCh. 37 - Prob. 86GPCh. 37 - Prob. 87GPCh. 37 - Prob. 88GPCh. 37 - Prob. 89GPCh. 37 - Prob. 90GPCh. 37 - Prob. 91GPCh. 37 - Prob. 92GPCh. 37 - Prob. 93GPCh. 37 - Show that the wavelength of a particle of mass m...Ch. 37 - Prob. 95GPCh. 37 - Prob. 96GPCh. 37 - Prob. 97GPCh. 37 - Prob. 98GPCh. 37 - Prob. 99GPCh. 37 - Prob. 100GP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- (b) (i) Calculate the de Broglie wavelength of an electron having a mass of 9.11 x 1031 kg and a charge of 1.602 x 10-19 J with a Kinetic energy of 135 eV. The value of the Planck's constant is equal to 6.63 * 10-34 Js. (ii) Assume that an electron is moving along the x-axis with a speed of 3.66 x 106 m/s and with a precision of 0.50%. Calculate the minimum uncertainty (as allowed by the uncertainty principle in quantum theory) with which the position of the electron along the X-axis simultaneously can be measured with the speed?arrow_forward7) White light has wavelengths that range from 380 nm to 750 nm. This light strikes a metal that has a work function of 2.28 eV. (a) What is the maximum kinetic energy (in joules) of the electrons that are emitted from the metal? (b) For what wavelengths will no electrons be emitted? range ofarrow_forwardThe energy of an ultraviolet light is 3.28 eV. (i) What is its wavelength? (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C). (ii) Based on the de Broglie's hypothesis, determine the velocity of the electron. (Given: h=6.63✕10-34 Js ; me=9.11✕10-31 kg).arrow_forward
- An electron is orbiting around a nucleus in a hydrogen atom in Bohr 's model with kinetic energy of 8.64✕10-20 J. Determine the allowed orbit in this atom. (Given: Mass of electron, me=9.1✕10-31 kg)arrow_forward(ii) The longest wavelength of light emitted by hydrogen in the Balmer series is 2, = 725 nm. In light from a distant galaxy, this wavelength is measured to be 2, = 1358 nm. Find the speed at which the distant galaxy is receding from the earth. %3Darrow_forward(b) Calculate the de Broglie wavelength of an electron having a mass of 9.11 x 10-31 kg and a charge of 1.602 x 10-19 J with a Kinetic energy of 110 eV. The value of the Planck’s constant is equal to 6.63 * 10-34 Js.arrow_forward
- (a) If the wavelength of an electron is 4.60 ✕ 10−7 m, how fast is it moving? km/s(b) If the electron has a speed equal to 8.40 ✕ 106 m/s, what is its wavelength? marrow_forwardII) What is the maximum kinetic energy of electronsejected from barium(Wo = 2.48eV) when illuminated bywhite light,λ =400 to 750 nm?arrow_forwardAn atom in an excited state 1.95 eV above the ground state remains in that excited state 1.15 us before moving to the ground state. (a) Find the frequency of the emitted photon. THz (b) Find the wavelength of the emitted photon. nm (c) Find the approximate uncertainty in energy of the photon. ΔΕΣ peVarrow_forward
- Using the Bohr model, calculate the speed of the electron when it is in the first excited state, n = 2. The Bohr radius ₁ 5.29 x 10-11 m. Assume the electron is non-relativistic.arrow_forward(b) Evaluate the ratio of the de Broglie wavelength of electron to that of proton when (m₂=9.11 × 10-3¹ kg, mp=1.67 × 10-27 kg) (i) both have the same kinetic energy. (ii) The electron kinetic energy is 1000 eV, and the proton kineticarrow_forward(a) If the wavelength of an electron is 4.81 x 10¬' m, how fast is it moving? km/s (b) If the electron has a speed equal to 3.60 x 10° m/s, what is its wavelength?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College