EP PHYSICS F/SCI.+ENGR.W/MOD..-MOD MAST
4th Edition
ISBN: 9780133899634
Author: GIANCOLI
Publisher: PEARSON CO
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Chapter 37, Problem 81GP
To determine
The closeness of
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In a Rutherford scattering experiment, an a-particle (charge = +2e) heads directly toward a gold nucleus (charge = +79e). The α-particle had a kinetic energy of 5.0 MeV when very far (r→ ∞) from the nucleus. Assuming the gold nucleus to be fixed in space, determine the distance of closest approach. Hint: Use conservation of energy with PE =kq1q2/r.
Use the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron).
Neutron: m,= 1.67493x1027 kg= 1.008665 u = 939.57 MeVIC
H: my = 1.67353x10 27 kg = 1.007825 u = 938.78 MeVic
1u= 1.6605x10-27 kg = 931.5 MeVic?
Consider the following decay: 211 At 207 Bi + a. 211 At has a mass of 210.9874963 u, 207 Bi has a mass of 206.981593 u, and a has a mass of 4.002603 u.
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Determine the disintegration energy (Q-value) in MeV.
Determine the binding energy (in MeV) for 211 At.
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Alpha particles are projected toward a gold foil from a distance that is sufficiently large to consider the Coulomb force negligible. The gold nuclei have 118 neutrons and 79 protons. If a 3.45 MeV alpha particle has a scattering angle of 180° and the gold nucleus does not recoil, determine the distance of closest approach of the alpha particle.
Chapter 37 Solutions
EP PHYSICS F/SCI.+ENGR.W/MOD..-MOD MAST
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- Explain how a hydrogen atom in the ground state (l = 0) can interact magnetically with an external magnetic field.arrow_forwardFrom far away a proton is fired directly toward the center of the nucleus of a mercury atom. Mercury is element number 80, and the diameter of the nucleus is 14.0 fm. Assume the mercury nucleus is fully-ionized, with no electrons bound to it. If the proton is fired at a speed of 3.8×107 m/s, what is its closest approach to the surface of the nucleus? Assume the nucleus remains at rest. Express your answer with the appropriate units. ► View Available Hint(s) 0 d = 2.7 Submit A fm Previous Answers ? X Incorrect; Try Again; 13 attempts remainingarrow_forwardUse the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m = 1.67493x10-27 kg = 1.008665 u = 939.57 MeV/c² . ¹H: mH = 1.67353x10-27 kg = 1.007825 u = 938.78 MeV/c² 1 1 u = 1.6605x10-27 kg = 931.5 MeV/c² . Consider the following decay: 239 Pu 235 U+ a. 239 Pu has a mass of 239.0521634 u, 235 U has a mass of 235.0439299 u, and a has a mass of 4.002603 u. 94 92 94 92 Determine the disintegration energy (Q-value) in MeV. Q = Determine the binding energy (in MeV) for 239 Pu. 94 EB =arrow_forward
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