Explanation Write the expression to obtain the kinetic energy of an electron. K = p 2 2 m Here, K is a kinetic energy of an electron, p is the momentum of an electron and m is the mass of an electron. Re-write the above equation. p 2 = 2 m K p = 2 m K Write the expression to obtain the momentum of an electron. p = h λ Here, p is the momentum of an electron, h is the Planck’s constant and λ is the wavelength. Substitute 2 m K for p in the above equation. 2 m K = h λ λ = h 2 m K Divide and multiply with the speed of the light c in the above equation. λ = h c c 2 m K = h c 2 m c 2 K Conclusion: Substitute 3.0 × 10 8 m / s for c , 6.63 × 10 − 34 J ⋅ s for h , 9.11 × 10 − 31 kg for m and 3450 eV for K in the above equation to calculate λ . λ = ( 6.63 × 10 − 34 J ⋅ s ) ( 3.0 × 10 8 m / s ) 2 ( 9

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Chapter 37, Problem 53P

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The maximum possible resolution of the microscope for the given conditions.

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Chapter 37, Problem 52P

Chapter 37, Problem 54P

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The size of atoms varies by only a factor of three or so,from largest to smallest, yet the number of electrons variesfrom one to over 100. Explain

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Chapter 37 Solutions

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