Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
9th Edition
ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 37, Problem 65AP
(a)
To determine
The thickness of the air layer at the center of the interference pattern.
(b)
To determine
The radius of the outermost dark ring.
(c)
To determine
The focal length of the lens.
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A plano-concave lens having index of refraction 1.50 is placed on a flat glass plate as shown in Figure P36.39. Its curved surface, with radius of curvature 8.00 m, is on the bottom. The lens is illuminated from above with yellow sodium light of wavelength 589 nm, and a series of concentric bright and dark rings is observed by reflection. The interference pattern has a dark spot at the center that is surrounded by 50 dark rings, the largest of which is at the outer edge of the lens. (a) What is the thickness of the air layer at the center of the interference pattern? (b) Calculate the radius of the outermost dark ring. (c) Find the focal lengthof the lens.
A plano-convex lens rests with its curved side on a flat glass surface and is illuminated from above by light of wavelength 464 nm. A dark spot is observed at the center, surrounded by 19 concentric dark rings (with bright rings in between). How much thicker is the air wedge at the position of the 19th dark ring than at the center?
2.41 um
2.97 um
3.77 um
4.41 um
67. Interference fringes are produced using Lloyd's mirror
and a source S of wavelength A = 606 nm as shown in
Figure P37.67. Fringes separated by Ay = 1.20 mm are
formed on a screen a distance L = 2.00 m from the
source. Find the vertical distance h of the source above
the reflecting surface.
Viewing
screen
·L
P
S
Mirror
Figure P37.67
Chapter 37 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Ch. 37.2 - Which of the following causes the fringes in a...Ch. 37.3 - Using Figure 36.6 as a model, sketch the...Ch. 37.5 - One microscope slide is placed on top of another...Ch. 37 - Prob. 1OQCh. 37 - Four trials of Youngs double-slit experiment are...Ch. 37 - Suppose Youngs double-slit experiment is performed...Ch. 37 - Prob. 4OQCh. 37 - Prob. 5OQCh. 37 - Prob. 6OQCh. 37 - Prob. 7OQ
Ch. 37 - Prob. 8OQCh. 37 - Prob. 9OQCh. 37 - A film of oil on a puddle in a parking lot shows a...Ch. 37 - Prob. 1CQCh. 37 - Prob. 2CQCh. 37 - Prob. 3CQCh. 37 - Prob. 4CQCh. 37 - Prob. 5CQCh. 37 - Prob. 6CQCh. 37 - Prob. 7CQCh. 37 - Prob. 8CQCh. 37 - Prob. 9CQCh. 37 - Two slits are separated by 0.320 mm. A beam of...Ch. 37 - Prob. 2PCh. 37 - A laser beam is incident on two slits with a...Ch. 37 - Prob. 4PCh. 37 - Prob. 5PCh. 37 - Prob. 6PCh. 37 - Prob. 7PCh. 37 - Prob. 8PCh. 37 - Prob. 9PCh. 37 - Light with wavelength 442 nm passes through a...Ch. 37 - Prob. 11PCh. 37 - Prob. 12PCh. 37 - Prob. 13PCh. 37 - Prob. 14PCh. 37 - Prob. 15PCh. 37 - A student holds a laser that emits light of...Ch. 37 - Prob. 17PCh. 37 - Prob. 18PCh. 37 - Prob. 19PCh. 37 - Prob. 20PCh. 37 - Prob. 21PCh. 37 - Prob. 22PCh. 37 - Prob. 23PCh. 37 - Prob. 24PCh. 37 - Prob. 25PCh. 37 - Monochromatic coherent light of amplitude E0 and...Ch. 37 - Prob. 27PCh. 37 - Prob. 28PCh. 37 - Prob. 29PCh. 37 - Prob. 30PCh. 37 - Prob. 31PCh. 37 - Prob. 32PCh. 37 - Prob. 33PCh. 37 - Prob. 34PCh. 37 - Prob. 35PCh. 37 - Prob. 36PCh. 37 - Prob. 37PCh. 37 - Prob. 38PCh. 37 - When a liquid is introduced into the air space...Ch. 37 - Prob. 40PCh. 37 - Prob. 41PCh. 37 - Prob. 42PCh. 37 - Prob. 43PCh. 37 - Prob. 44PCh. 37 - Prob. 45APCh. 37 - Prob. 46APCh. 37 - Prob. 47APCh. 37 - Prob. 48APCh. 37 - Prob. 49APCh. 37 - Prob. 50APCh. 37 - Prob. 51APCh. 37 - In a Youngs interference experiment, the two slits...Ch. 37 - In a Youngs double-slit experiment using light of...Ch. 37 - Prob. 54APCh. 37 - Prob. 55APCh. 37 - Prob. 56APCh. 37 - Prob. 57APCh. 37 - Prob. 58APCh. 37 - Prob. 59APCh. 37 - Prob. 60APCh. 37 - Prob. 61APCh. 37 - Prob. 62APCh. 37 - Prob. 63APCh. 37 - Prob. 64APCh. 37 - Prob. 65APCh. 37 - Prob. 66APCh. 37 - Prob. 67APCh. 37 - Prob. 68APCh. 37 - Prob. 69APCh. 37 - Prob. 70APCh. 37 - Prob. 71CPCh. 37 - Prob. 72CPCh. 37 - Prob. 73CPCh. 37 - Prob. 74CPCh. 37 - Prob. 75CPCh. 37 - Prob. 76CP
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- A beam of 580-nm light passes through two closely spaced glass plates at close to normal incidence as shown in Figure P27.23. For what minimum nonzero value of the plate separation d is the transmitted light bright?arrow_forwardA plano-convex lens has index of refraction n. The curved side of the lens has radius of curvature R and rests on a flat glass surface of the same index of refraction, with a film of index nflim between them, as shown in Figure P36.42. The lens is illuminated from above by light of wavelength . Show that the dark Newtons rings have radii given approximately by r=mRnfilm where r R and m is an integer. Figure P36.42arrow_forwardIn the double-slit arrangement of Figure P36.13, d = 0.150 mm, L = 140 cm, = 643 nm. and y = 1.80 cm. (a) What is the path difference for the rays from the two slits arriving at P? (b) Express this path difference in terms of . (c) Does P correspond to a maximum, a minimum, or an intermediate condition? Give evidence for your answer. Figure P36.13arrow_forward
- The Michelson interferometer can be used to measure the index of refraction of a gas by placing an evacuated transparent tube in the light path along one arm of the device. Fringe shifts occur as the gas is slowly added to the tube. Assume 580-nm light is used, the tube is 5.40 cm long, and 152 fringe shifts occur as the pressure of the gas in the tube increases to atmospheric pressure. What is the index of refraction of the gas? Hint: The fringe shifts occur because the wavelength of the light changes inside the gas-filled tube. (Give your answer to five decimal places.) 4.0arrow_forwardOne way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the glass container is a vacuum. When gas is slowly allowed into the container, a total of 6894 dark fringes move past the reference line. The laser has a wavelength of 635 nm (this is the wavelength when the light from the laser is moving through a vacuum). A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the light passes through the container twice, you need to determine how many wavelengths will fit into a glass container that has a length of 2L.number of wavelengths (vacuum) = B.) The number of dark fringes is the difference between the number of wavelengths that fit in the container (length of 2L) when it has gas and the number of wavelengths that fit in the container (length of 2L) when it is a vacuum. Use this knowledge to…arrow_forwardInterference effects are produced at point P on a screen as a result of direct rays from a 5.00 x 102 - nm source and reflected rays off a mirror, as shown in Figure P24.67. If the source is L = 1.00 x 102 m to the left of the screen and h = 1.00 cm above the mirror, find the distance y (in millimeters) to the first dark band above the mirror.arrow_forward
- The Michelson interferometer can be used to measure the index of refraction of a gas by placing an evacuated transparent tube in the light path along one arm of the device. Fringe shifts occur as the gas is slowly added to the tube. Assume 600.-nm light is used, the tube is 5.00 cm long, and 160 fringe shifts occur as the pressure of the gas in the tube increases to atmospheric pressure. What is the index of refraction of the gas? Hint: The fringe shifts occur because the wavelength of the light changes inside the gas-filled tube.arrow_forwardWe consider a Newton's rings experiment. It consists of a plano-convex glass lens of index of refractionn = 1.50 and radius r = 5.08 cm placed on a flat plate, as shown. When light of wavelength 636 nm is incident normally, 54 bright rings are observed, with the last one precisely on the edge of the lens. R a. What is the thickness t of the air layer at the edge of the lens? This corresponds to the maximum distance between the curved surface and the flat plate. um b. What is the radius of curvature R of the convex surface of the lens? m c. What is the focal length of the lens? Hint: use the lens maker equation. marrow_forwardA thin layer of oil floats on a puddle of water. When sunlight hits the film from directly above, the colors red (650 nm) and violet (390 nm) are reflected. What is the minimum thickness of the oil? Use n=1.5 for the oil, and n=1.33 for water.arrow_forward
- A thin layer of liquid methylene iodide (n = 1.76) is sandwiched between two flat, parallel plates of glass (n = 1.42). What is the minimum thickness of the liquid layer if normally incident light with λ= 550 nm in air is to be strongly reflected? 63.0 nm 99.2 nm 78.1 nm 126.0 nmarrow_forwardOne way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the glass container is a vacuum. When gas is slowly allowed into the container, a total of 7571 dark fringes move past the reference line. The laser has a wavelength of 687 nm (this is the wavelength when the light from the laser is moving through a vacuum). Laser Mirror Glass Container Beam Splitter Diffraction Pattern Mirror A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the light passes through the container twice, you need to determine how many wavelengths will fit into a glass container that has a length of 2L. number of wavelengths (vacuum) = B.) The number of dark fringes is the difference between the number of wavelengths that fit in the container (length of 2L) when it has gas and the number of wavelengths that fit in…arrow_forwardAn instructor places a fluid substance, with a refractive index of 1.61, between two horizontal panes of flat glass (each of which has n = 1.55). She then illuminates the assembly from above with monochromatic light (? = 700 nm). What is the minimum thickness (in nm) that the liquid layer must have, if the light is to be strongly reflected back toward its source? ??nmarrow_forward
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