Concept explainers
Complete the blank cells in the following table of properties of steam. In the last column, describe the condition of steam as compressed liquid, saturated mixture, superheated vapor, or insufficient information, and, if applicable, give the quality.
The following table for
P, kPa | u, kJ/kg | x, quality | Phase description | ||
200 | 30 | ||||
270.3 | 130 | ||||
400 | 1.5493 | ||||
300 | 0.500 | ||||
500 | 3084 |
Explanation of Solution
State 1
Refer to Table A-5, “Saturated water-Pressure table”, obtain the value of saturated temperature at a pressure of 200 kPa as
The given temperature in state 1 is less than the saturated temperature at a pressure of 200 kPa.
Hence, state 1 is compressed liquid.
As wee see now there is no data for compressed liquid water in table A-7 for pressure 200 kPa, so calculate the specific internal energy and specific volume of a mixture at a saturated liquid at a temperature of
State 2
Refer to Table A-4, obtain the specific volume at saturated liquid and specific internal energy at saturated liquid at a temperature of
Thus, the state 2 condition is saturated liquid.
State 3
Refer to Table A-6, “Superheater water”, obtain the pressure and specific internal energy at a temperature and specific volume of
The given specific internal energy is greater than the specific internal energy at saturated vapour at a pressure of 200 kPa refer from Table A-5.
Thus, state 3 is a superheated steam.
State 4
Refer to Table A-4, “Saturated water-Pressure table”, obtain the specific volume and specific internal energy at saturated liquid
As we see now the given specific volume of the mixture
Hence, the state 4 is known as saturated mixture.
Refer to Table A-4, “Satuated water-pressure table”, obtain the temperature at a pressure of 200 kPa as
Calculate the quality at state 1.
Substitute
Calculate the specific internal state.
Here, specific internal energy at saturated liquid and saturated vapour is
Substitute
State 5
Since
Thus, the state 5 is superheated steam.
Convert the unit of pressure from kPa to MPa.
Refer to Table A-6, “Superheated water”, obtain the temperature and specific volume at a pressure of 0.50 MPa and specific intenal energy of 3084 kJ/kg as
From the above calculations and referred from the steam table, complete the table of
P, kPa | u, kJ/kg | x, quality | Phase description | ||
200 | 30 | -- | compressed liquid | ||
270.3 | 130 | -- | saturated liquid | ||
400 | 1.5493 | superheated steam | |||
300 | 0.500 | saturated mixture | |||
500 | 3084 | superheated steam |
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Chapter 3 Solutions
Thermodynamics: An Engineering Approach
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