Explanation Write the expression for angle corresponding to maxima. tan θ = y L Here, θ is the angle corresponding to maxima, y is the position of maxima and L is the distance of the grating from the disk. Write the expression for grating spacing. d = m λ sin θ Here, d is the grating spacing, m is the diffraction order and λ is the wavelength. From the two equations, the position of maxima is given by, y = L tan [ sin − 1 ( m λ d ) ] Therefore, the separation is given by, Δ y = L { tan [ sin − 1 ( m λ 2 d ) ] − tan [ sin − 1 ( m λ 1 d ) ] } Here, λ 1 and λ 2 are the wavelengths. The grating spacing is, d = 1 cm 4200 = 2.38 × 10 − 6 m Conclusion: For m = 1 , Substitute 2.38 × 10 − 6 m for d , 2.00 m for L , 589 nm for λ 1 and 589.6 nm for λ 2 to get d . Δ y = ( 2

Physics for Scientists and Engineers With Modern Physics

9th Edition

ISBN: 9781133953982

Author: SERWAY, Raymond A./

Publisher: Cengage Learning

See similar textbooks

Concept explainers

Diffraction of light

In physics, the term diffraction is defined as the bending of light around the corners of the obstacle. As a light ray passes by an aperture, it bends around the edges or through slits, it spreads out through a narrow opening. The diffracted light will p…

Videos

Question

Chapter 38, Problem 31P

To determine

The value of m.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 38, Problem 30P

Chapter 38, Problem 32P

Students have asked these similar questions

On a certain crystal, a first-order X-ray diffraction maximum is observed at an angle of 33.30 relative to its surface, using an x-ray source of unknown wavelength. Additionally, when illuminated with a different x-ray, this time of known.wavelength 0.205 nm, a second-order maximum is detected at 22.20. Determine the spacing between the reflecting planes.. Select one: O a. 0.19nm O b. 1.84nm O c. 0.27nm O d. 0.54nm

632.8 nm) is used to calibrate a diffraction grating. If the first-order maximum occurs at 21.0°, what is the spacing between adjacent grooves in the grating? (In this problem, assume that the light is incident normally on the grating.) μm A helium-neon laser (1 =

What angular separation is obtained after two spectral lines of 550.0 nm and 632.0 nm areobserved with a diffraction grating that is 4000 groves/mm?.

Chapter 38 Solutions

Physics for Scientists and Engineers With Modern Physics

Ch. 38.2 - Suppose the slit width in Figure 37.4 is made half...Ch. 38.2 - Prob. 38.2QQ Ch. 38.3 - Cats eyes have pupils that can be modeled as...Ch. 38.3 - Suppose you are observing a binary star with a...Ch. 38.4 - Ultraviolet light of wavelength 350 nm is incident...Ch. 38.6 - A polarizer for microwaves can be made as a grid...Ch. 38.6 - Prob. 38.7QQ Ch. 38 - Prob. 1OQ Ch. 38 - Prob. 2OQ Ch. 38 - Prob. 3OQ

Ch. 38 - Prob. 4OQ Ch. 38 - Prob. 5OQ Ch. 38 - Prob. 6OQ Ch. 38 - Prob. 7OQ Ch. 38 - Prob. 8OQ Ch. 38 - Prob. 9OQ Ch. 38 - Prob. 10OQ Ch. 38 - Prob. 11OQ Ch. 38 - Prob. 12OQ Ch. 38 - Prob. 1CQ Ch. 38 - Prob. 2CQ Ch. 38 - Prob. 3CQ Ch. 38 - Prob. 4CQ Ch. 38 - Prob. 5CQ Ch. 38 - Prob. 6CQ Ch. 38 - Prob. 7CQ Ch. 38 - Prob. 8CQ Ch. 38 - Prob. 9CQ Ch. 38 - Prob. 10CQ Ch. 38 - Prob. 11CQ Ch. 38 - Prob. 12CQ Ch. 38 - Prob. 1P Ch. 38 - Prob. 2P Ch. 38 - Prob. 3P Ch. 38 - Prob. 4P Ch. 38 - Prob. 5P Ch. 38 - Prob. 6P Ch. 38 - Prob. 7P Ch. 38 - Prob. 8P Ch. 38 - Prob. 9P Ch. 38 - Prob. 10P Ch. 38 - Prob. 11P Ch. 38 - Coherent light of wavelength 501.5 nm is sent...Ch. 38 - Prob. 13P Ch. 38 - Prob. 14P Ch. 38 - Prob. 15P Ch. 38 - Prob. 16P Ch. 38 - Prob. 17P Ch. 38 - Prob. 18P Ch. 38 - What is the approximate size of the smallest...Ch. 38 - Prob. 20P Ch. 38 - Prob. 21P Ch. 38 - Prob. 22P Ch. 38 - Prob. 23P Ch. 38 - Prob. 24P Ch. 38 - Prob. 25P Ch. 38 - Prob. 26P Ch. 38 - Consider an array of parallel wires with uniform...Ch. 38 - Prob. 28P Ch. 38 - Prob. 29P Ch. 38 - A grating with 250 grooves/mm is used with an...Ch. 38 - Prob. 31P Ch. 38 - Prob. 32P Ch. 38 - Light from an argon laser strikes a diffraction...Ch. 38 - Show that whenever white light is passed through a...Ch. 38 - Prob. 35P Ch. 38 - Prob. 36P Ch. 38 - Prob. 37P Ch. 38 - Prob. 38P Ch. 38 - Prob. 39P Ch. 38 - Prob. 40P Ch. 38 - Prob. 41P Ch. 38 - Prob. 42P Ch. 38 - Prob. 43P Ch. 38 - Prob. 44P Ch. 38 - Prob. 45P Ch. 38 - Prob. 46P Ch. 38 - Prob. 47P Ch. 38 - Prob. 48P Ch. 38 - Prob. 49P Ch. 38 - Prob. 50P Ch. 38 - Prob. 51P Ch. 38 - Prob. 52P Ch. 38 - Prob. 53AP Ch. 38 - Prob. 54AP Ch. 38 - Prob. 55AP Ch. 38 - Prob. 56AP Ch. 38 - Prob. 57AP Ch. 38 - Prob. 58AP Ch. 38 - Prob. 59AP Ch. 38 - Prob. 60AP Ch. 38 - Prob. 61AP Ch. 38 - Prob. 62AP Ch. 38 - Prob. 63AP Ch. 38 - Prob. 64AP Ch. 38 - Prob. 65AP Ch. 38 - Prob. 66AP Ch. 38 - Prob. 67AP Ch. 38 - Prob. 68AP Ch. 38 - Prob. 69AP Ch. 38 - Prob. 70AP Ch. 38 - Prob. 71AP Ch. 38 - Prob. 72AP Ch. 38 - Prob. 73AP Ch. 38 - Light of wavelength 632.8 nm illuminates a single...Ch. 38 - Prob. 75CP Ch. 38 - Prob. 76CP Ch. 38 - Prob. 77CP Ch. 38 - Prob. 78CP Ch. 38 - Prob. 79CP

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The value of m .

Solution Summary: The author explains the value of m, which is 2, and the expression for grating spacing.

Concept explainers

Videos

The value of m.

Want to see the full answer?

Chapter 38 Solutions