PHYSICS FOR SCIEN & ENGNR W/MOD MAST
4th Edition
ISBN: 9780134112039
Author: GIANCOLI
Publisher: PEARSON
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Question
Chapter 38, Problem 47GP
To determine
The lowest possible energy of a neutron contained in a typical nucleus.
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Check out a sample textbook solutionStudents have asked these similar questions
The velocity of a neutron is measured to be
6.0 x 106 m s-1 with an
uncertainty of 1.0 × 103 m s-1.
(i) What is the minimum uncertainty of the
simultaneous
measurement of the position of the neutron?
(ii) State how the minimum
uncertainties of a measured energy and a
measured time are related
79.
a) Assume an electron in the ground state of the hydrogen atom moves at an average speed of 5.00×106 m/s.
If the speed is known to an uncertainty of 1 percent, what is the minimum uncertainty in its position?The radius of the hydrogen atom in the ground state is 5.29×10−11 m. The mass of an electron is 9.1094×10−31 kg.
(b) A 0.16−kg baseball thrown at 100 mph has a momentum of 7.2 kg·m/s. If the uncertainty in measuring the mass is 1.0×10^−7 of the mass, calculate the uncertainty in the baseball's position.
The uncertainty in the velocity V of a moving electron of mass
10−4010−40
kg is
2 x106m/s2 x106m/s
. Calculate the uncertainty of the simultaneous measurement of its position X. [Take
6.63 x10−346.63 x10−34
]
Chapter 38 Solutions
PHYSICS FOR SCIEN & ENGNR W/MOD MAST
Ch. 38.3 - Prob. 1AECh. 38.8 - Prob. 1BECh. 38.8 - Prob. 1CECh. 38.9 - Prob. 1DECh. 38 - Prob. 1QCh. 38 - Prob. 2QCh. 38 - Prob. 3QCh. 38 - Prob. 4QCh. 38 - Would it ever be possible to balance a very sharp...Ch. 38 - Prob. 6Q
Ch. 38 - Prob. 7QCh. 38 - Prob. 8QCh. 38 - Prob. 9QCh. 38 - Prob. 10QCh. 38 - Prob. 11QCh. 38 - Prob. 12QCh. 38 - Prob. 13QCh. 38 - Prob. 14QCh. 38 - Prob. 15QCh. 38 - Prob. 16QCh. 38 - Prob. 17QCh. 38 - Prob. 18QCh. 38 - Prob. 1PCh. 38 - Prob. 2PCh. 38 - Prob. 3PCh. 38 - Prob. 4PCh. 38 - Prob. 5PCh. 38 - Prob. 6PCh. 38 - Prob. 7PCh. 38 - Prob. 8PCh. 38 - Prob. 9PCh. 38 - Prob. 10PCh. 38 - Prob. 11PCh. 38 - Prob. 12PCh. 38 - Prob. 13PCh. 38 - Prob. 14PCh. 38 - Prob. 15PCh. 38 - Prob. 16PCh. 38 - Prob. 17PCh. 38 - Prob. 18PCh. 38 - Prob. 19PCh. 38 - Prob. 20PCh. 38 - Prob. 21PCh. 38 - Prob. 22PCh. 38 - Prob. 23PCh. 38 - Prob. 24PCh. 38 - Prob. 25PCh. 38 - Prob. 26PCh. 38 - Prob. 27PCh. 38 - Prob. 28PCh. 38 - Prob. 29PCh. 38 - Prob. 30PCh. 38 - Prob. 31PCh. 38 - Prob. 32PCh. 38 - Prob. 33PCh. 38 - Prob. 34PCh. 38 - Prob. 35PCh. 38 - Prob. 36PCh. 38 - Prob. 37PCh. 38 - Prob. 38PCh. 38 - Prob. 39PCh. 38 - Prob. 40PCh. 38 - Prob. 41PCh. 38 - Prob. 42PCh. 38 - Prob. 43PCh. 38 - Prob. 44PCh. 38 - Prob. 45PCh. 38 - Prob. 46GPCh. 38 - Prob. 47GPCh. 38 - Prob. 48GPCh. 38 - Prob. 49GPCh. 38 - Prob. 50GPCh. 38 - Prob. 51GPCh. 38 - Prob. 52GPCh. 38 - Prob. 53GPCh. 38 - Prob. 54GPCh. 38 - Prob. 55GPCh. 38 - Prob. 56GPCh. 38 - Prob. 57GPCh. 38 - Prob. 58GPCh. 38 - Prob. 59GP
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Similar questions
- The total probability of finding an electron in the hydrogen atom is related to the integral ∫ r2 e-2r/ao dr Where r is the distance of the electron from the nucleus and ao is the Bohr radius. Evaluate thisintegral.arrow_forwardSuppose that the uncertainty in position of an electron is equal to the radius of the n=1n=1 Bohr orbit, about 0.529×10−10m0.529×10−10m. A) Calculate the minimum uncertainty in the corresponding momentum component. Express your answer in kilogram meters per second. B) Compare this with the magnitude of the momentum of the electron in the n=1n=1 Bohr orbit. Compare this with the magnitude of the momentum of the electron in the Bohr orbit. a) This is greater than the magnitude of the momentum of the electron in the n=1n=1 Bohr orbit. b) This is the same as the magnitude of the momentum of the electron in the n=1n=1 Bohr orbit. c) This is less than the magnitude of the momentum of the electron in the n=1n=1 Bohr orbit.arrow_forwardProblem 2: Line XY was measured by four parties a, b, c, d. Each party has two measurements as follows: Trial B 91.21 91.27 D 91.20 91.18 91.26 A 1 2 91.25 91.19 91.22 Find the precision of each party and find out which has the highest precision. b. What is the most probable length of XY? a.arrow_forward
- A nucleus emits a gamma ray of energy 1.2 MeV from a state that has a lifetime of 2.1 ns. What is the uncertainty in the energy of the gamma ray? The best gamma-ray detectors can measure gamma-ray energies to a precision of no better than a few eV. Will this uncertainty be directly measurable?arrow_forward(a) The lifetime of a highly unstable nucleus is 10-12 s. What is the smallest uncertainty (in ev) in its decay energy? ev (b) What is the ratio of this energy, AE, to the rest energy of an electron, Erest? ΔΕ Erestarrow_forward7.4. Four measurements are made of the wavelength of light emitted by certain atom. The results, in nanometers, are: 525 20, 570 t 40. 503 ± 10, 491 + 8, Find the weighted average and its uncertainty. Is the last measurement worth in- cluding?arrow_forward
- The "radius of the hydrogen atom" is often taken to be on the order of about 10-10m. If a measurement is made to determine the location of the electron for hydrogen in its ground state, what is the probability of finding the electron within 10-10m of the nucleus?arrow_forwardA) By what factor is the uncertainty of the electron's position(1.36×10-4 m) larger than the diameter of the hydrogen atom?(Assume the diameter of the hydrogen atom is 1.00×10-8 cm.) B) Use the Heisenberg uncertainty principle to calculate Δx for a ball (mass = 122 g, diameter = 8.50 cm) with Δv = 0.425 m/s. C) The uncertainty of the (above) ball's position is equal to what factor times the diameter of the ball?arrow_forwardThe decay energy of a short-lived nuclear excited state has an uncertainty of 2.1 eV due to its short lifetime. What is the smallest lifetime (in s) it can have? ____sarrow_forward
- An excited atom gives up its excited energy by emitting a photon. The average period that elapses between the excitation of an atom and the time it radiates is 5 x 10-9sec. Find the corresponding uncertainty in the frequency of the photon.arrow_forwardIf the speed of an electron is measured to within an uncertainty of 2.0x104 m/s, what would be the size of the smallest region of space in which the electron can be confined? me = 9.11 x 10-31 kg. 2.arrow_forwardThe speed of an electron is measured to within an uncertainty of 2.0 × 104 m/s. What is the size of the smallest region of space in which the electron can be confined?arrow_forward
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