Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Question
Chapter 38, Problem 69P
To determine
Proof that the distribution function of electrons in the
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For a certain semiconductor, the Fermi energy is in the middle of its band gap. If the temperature of the semiconductor is 285 K, find the probability that a state at the bottom of the conduction band is occupied if the band gap is 0.005eV.
the carrier distribution in the conduction band is:nc(E) = gc(E) . f(E)
a) For a non-degenerate semiconductor, show that nc(E) has a maximum at E = Ec + ½ kT
b) What is the ratio of carrier distribution at E = Ec + kT to that of the max value ?
If the energy gap for an insulating material is 4.5 eV, what is the probability that an electron will be promoted to the conduction band when the temperature is 100 °C? You may assume that the Fermi energy is in the middle of the energy gap.
Chapter 38 Solutions
Physics for Scientists and Engineers
Ch. 38 - Prob. 1PCh. 38 - Prob. 2PCh. 38 - Prob. 3PCh. 38 - Prob. 4PCh. 38 - Prob. 5PCh. 38 - Prob. 6PCh. 38 - Prob. 7PCh. 38 - Prob. 8PCh. 38 - Prob. 9PCh. 38 - Prob. 10P
Ch. 38 - Prob. 11PCh. 38 - Prob. 12PCh. 38 - Prob. 13PCh. 38 - Prob. 14PCh. 38 - Prob. 15PCh. 38 - Prob. 16PCh. 38 - Prob. 17PCh. 38 - Prob. 18PCh. 38 - Prob. 19PCh. 38 - Prob. 20PCh. 38 - Prob. 21PCh. 38 - Prob. 22PCh. 38 - Prob. 23PCh. 38 - Prob. 24PCh. 38 - Prob. 25PCh. 38 - Prob. 26PCh. 38 - Prob. 27PCh. 38 - Prob. 28PCh. 38 - Prob. 29PCh. 38 - Prob. 30PCh. 38 - Prob. 31PCh. 38 - Prob. 32PCh. 38 - Prob. 33PCh. 38 - Prob. 34PCh. 38 - Prob. 35PCh. 38 - Prob. 36PCh. 38 - Prob. 37PCh. 38 - Prob. 38PCh. 38 - Prob. 39PCh. 38 - Prob. 40PCh. 38 - Prob. 41PCh. 38 - Prob. 42PCh. 38 - Prob. 43PCh. 38 - Prob. 44PCh. 38 - Prob. 45PCh. 38 - Prob. 46PCh. 38 - Prob. 47PCh. 38 - Prob. 48PCh. 38 - Prob. 49PCh. 38 - Prob. 50PCh. 38 - Prob. 51PCh. 38 - Prob. 52PCh. 38 - Prob. 53PCh. 38 - Prob. 54PCh. 38 - Prob. 55PCh. 38 - Prob. 56PCh. 38 - Prob. 57PCh. 38 - Prob. 58PCh. 38 - Prob. 59PCh. 38 - Prob. 60PCh. 38 - Prob. 61PCh. 38 - Prob. 62PCh. 38 - Prob. 63PCh. 38 - Prob. 64PCh. 38 - Prob. 65PCh. 38 - Prob. 66PCh. 38 - Prob. 67PCh. 38 - Prob. 68PCh. 38 - Prob. 69PCh. 38 - Prob. 70PCh. 38 - Prob. 71PCh. 38 - Prob. 72PCh. 38 - Prob. 73PCh. 38 - Prob. 74PCh. 38 - Prob. 75PCh. 38 - Prob. 76P
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- In a solid, consider the energy level lying 0.4eV below Fermi level.What is Probability of this level not being occupied by an electron at the room temperature?arrow_forwardConsider a n-type Si crystal at room temperature (300K) doped with 6 x1016 cm-3 arsenic impurity atoms and with certain number of shallowholes. Find out the equilibrium electron concentration, hole concentrationand Fermi level EF with respect to Ei, and the conduction band edge EC.For Si at 300K, the value of ni is 1.45 x 1010 cm-3 and k = 1.38 x 10-23 J/K,1eV = 1.60 x 10-19J. The band gap energy, Eg, of Si is 1.2eV.Solution:n @ Nd = 6 x 1016 cm-3.In equilibrium condition, hole concentration = 3.5 x 103 cm-3.EF – EI = 0.396eVEC – EF = 0.164eV.arrow_forwardAn unknown semiconductor has a band gap, Eg =1.1 eV and NC = NV where NC and NV are effective density of states in the conduction and valence band respectively. It is doped with 1015 cm-3 donors, where the donor level is 0.2 eV below conduction band minimum EC. Given that EF is 0.25 eV below EC, calculate intrinsic carrier density (ni), and the concentration of electrons and holes in the semiconductor at 300 Karrow_forward
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