EBK PHYSICS FOR SCIENTISTS & ENGINEERS
5th Edition
ISBN: 9780134296074
Author: GIANCOLI
Publisher: VST
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Chapter 39, Problem 40P
To determine
The proof that the cutoff wavelength
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(II) Show that the energy E (in electron volts) of a photon
whose wavelength is A (nm) is given by
1.240 x 10° eV·nm
E =
λ (nm)
Use at least 4 significant figures for values of h, c, e (see
inside front cover).
(b)
(i) Calculate the de Broglie wavelength of an electron having a mass
of 9.11 x 1031 kg and a charge of 1.602 x 10-19 J with a Kinetic
energy of 135 eV. The value of the Planck's constant is equal to
6.63 * 10-34 Js.
(ii) Assume that an electron is moving along the x-axis with a speed
of 3.66 x 106 m/s and with a precision of 0.50%. Calculate the
minimum uncertainty (as allowed by the uncertainty principle in
quantum theory) with which the position of the electron along the
X-axis simultaneously can be measured with the speed?
II) What is the maximum kinetic energy of electronsejected from barium(Wo = 2.48eV) when illuminated bywhite light,λ =400 to 750 nm?
Chapter 39 Solutions
EBK PHYSICS FOR SCIENTISTS & ENGINEERS
Ch. 39 - Prob. 2QCh. 39 - Prob. 3QCh. 39 - Prob. 4QCh. 39 - Prob. 5QCh. 39 - Prob. 6QCh. 39 - Prob. 7QCh. 39 - On what factors does the periodicity of the...Ch. 39 - Prob. 9PCh. 39 - Prob. 10PCh. 39 - Prob. 11P
Ch. 39 - Prob. 12PCh. 39 - Prob. 13PCh. 39 - Prob. 14PCh. 39 - Prob. 15PCh. 39 - Prob. 16PCh. 39 - Prob. 17PCh. 39 - Prob. 18PCh. 39 - Prob. 19PCh. 39 - Prob. 20PCh. 39 - Prob. 21PCh. 39 - Prob. 22PCh. 39 - Prob. 23PCh. 39 - Prob. 24PCh. 39 - Prob. 25PCh. 39 - Prob. 26PCh. 39 - Prob. 27PCh. 39 - Prob. 34PCh. 39 - Prob. 35PCh. 39 - Prob. 36PCh. 39 - Prob. 37PCh. 39 - Prob. 40PCh. 39 - Prob. 41PCh. 39 - Prob. 42PCh. 39 - Prob. 43PCh. 39 - Prob. 44PCh. 39 - Prob. 45PCh. 39 - Prob. 46P
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- (ii) A silicon detector contains a photoconductive layer of thickness 1 = 20mm. The refractive index of silicon is 4 and the absorption coefficient (a) of silicon in cm-1 is given by a = 10(7-6000) where I is wavelength in Å. Calculate the wavelength at which the quantum efficiency loss due to penetration through the device is equal to that due to re- flection at the surface.arrow_forward(b) Calculate the de Broglie wavelength of an electron having a mass of 9.11 x 10-31 kg and a charge of 1.602 x 10-19 J with a Kinetic energy of 110 eV. The value of the Planck’s constant is equal to 6.63 * 10-34 Js.arrow_forward(b) Evaluate the ratio of the de Broglie wavelength of electron to that of proton when (m₂=9.11 × 10-3¹ kg, mp=1.67 × 10-27 kg) (i) both have the same kinetic energy. (ii) The electron kinetic energy is 1000 eV, and the proton kineticarrow_forward
- (a) A simplified parabolic E-K diagram for an electron in the conduction band is given in Figure 3. Determine the relative effective mass, m'/m.. given the E – E. = C,k², value of a of 1 nm, Planck constant h = 6.625 × 10-34 J. s, free electron mass m, = 9.11 x 10-31 kg, electric charge q = 1.6 x 10-19 C and 1 eV = 1.6 x 10-19 J. E E = E,+0.32 eV Figure 3arrow_forward- (i) Calculate the Amin and Amax region of 70 kV X-ray tube. (ii) Calculate the maximum frequency of an X-ray caused by an electron travelling with 60000 eV of kinetic energy?arrow_forwardWhat is the shortest-wavelength x-ray radiation that can be generated in an x-ray tube with an applied voltage of 50.0 kV? (b) Calculate the photon energy in eV.arrow_forward
- (c) The energy of an ultraviolet light is 3.28 eV. (i) What is its wavelength? (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C). (ii) Based on the de Broglie's hypothesis, determine the velocity of the electron. (Given: h=6.63✕10-34 Js ; me=9.11✕10-31 kg).arrow_forward2) a) A monochromator is used as shown in the setup below to obtain a single wavelength 2 = 1.5 Å X-ray from X-rays emitted from an X-ray source. The monochromator is made of Germanium single crystal. The Miller index of the planes in this Germanium single crystal is (111) and the distance between the planes is d11 = 1.2 Å. What is the value of the monochromator angle (0)? (scottered X-ray) Saçılan X-ışını elincedent X-ray) s ) (scattering angle Sacılma Açısı Gelen X-Işını Geliş Açısı Eieliş Dogrultusu (andeofincidence) direction of arrival) Kristal Düzlemleri (crystal planes) b) Calculate the energy of the X-ray with wavelength 2 = 1.5 Å in eV.arrow_forward(4) (i) Light shining on a metal surface produces photoelectrons with a maximum kinetic energy of 2.0 eV. The light intensity is then doubled. Now what is the maximum kinetic energy of the photoelectrons, in eV? (ii) The detector in an ordinary digital camera is made of silicon. This detector works by the photoelectric effect. The longest wavelength of light that an ordinary digital camera can detect has a wavelength of 1 micron (where 1 micron = 10^-6 m). What is the work function of silicon, in eV? (iii) Infrared cameras don't use detectors made of silicon. For an infrared camera to detect infrared radiation with a wavelength of 22 microns, its detector must be made of a di erent material. What is the maximum possible work function of this material, in eV?arrow_forward
- (c) The energy of an ultraviolet light is 3.28 eV. Tenaga cahaya ultraviolet adalah 3.28 eV. (i) What is its wavelength? (Given: h=6.63×10-34 Js ; e=1.602×10-19 C). Berapakah panjang gelombangnya? (Diberi: h=6.63×10-34 Js ; e=1.602×10-19 C). nm (ii) Based on the de Broglie's hypothesis, determine the velocity of the electron. (Given: h=6.63x10 34 Js ; me=9.11x10 31 kg)arrow_forward(a) A vacuum photocell is sequentially illuminated with light of different wavelengths 2. A voltmeter is used to determine that there is a different voltage between the cathode and the anode. V (iii) Determine a relation for Planck's constant in terms of pairs of voltage measurements at different wavelengths such that W₁ cancels out. (iv) Evaluate Planck's constant for the following pair of measurements: measurement 1 finds = 447 nm and V=635 mV, and measurement 2 finds = : 502 nm and V=339 mV.arrow_forwardIf violet light of wavelength 375 nm illuminates a metal, what voltage will completely stop the flow of electrons from the surface?arrow_forward
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