EBK NUMERICAL METHODS FOR ENGINEERS
7th Edition
ISBN: 9780100254145
Author: Chapra
Publisher: YUZU
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Chapter 4, Problem 17P
If
Repeat Prob. 4.1 for this series for
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Find the value of a if
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1 3 0
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42 0
F1
F2
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F3
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Consider the following values: -
F5
a = 25 m; b = 5 m; c = 25 m; d = 5 m;
F1 = 4 kN; F2 = 2 kN; F3 -
a = 30° , 0 = 60°, B = 30°
5 kN; F4 =
7 kN; F5 = 3 kN;
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1] What is the resultant moment of the five forces acting on the rod about point A?
2.11 A point Q moves from A to B along link 3 while linke 2 rotates from 0 =
0' = 120 deg. Fine the absolute displacement of Q.
Where RAO, = RBO, = 3" and RBA = RO2O4 = 6" .
30 deg to
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Chapter 4 Solutions
EBK NUMERICAL METHODS FOR ENGINEERS
Ch. 4 - The following series can be used to approximate...Ch. 4 - 4.2 The Maclaurin series expansion for cos x...Ch. 4 - 4.3 Perform the same computation as in Prob. 4.2,...Ch. 4 - 4.4 The Maclaurin series expansion for the...Ch. 4 - 4.5 Use zero- through third-order Taylor series...Ch. 4 - 4.6 Use zero- through fourth-order Taylor series...Ch. 4 - Use forward and backward difference approximations...Ch. 4 - 4.8 Use a centered difference approximation of to...Ch. 4 - 4.9 The Stefan-Boltzmann law can be employed to...Ch. 4 - Repeat Prob. 4.9 but for a copper sphere with...
Ch. 4 - Recall that the velocity of the falling...Ch. 4 - 4.12 Repeat Prob. 4.11 with.
Ch. 4 - 4.13 Evaluate and interpret the condition numbers...Ch. 4 - Employing ideas from Sec. 4.2, derive the...Ch. 4 - Prove that Eq. (4.4) is exact for all values of x...Ch. 4 - Mannings formula for a rectangular channel can be...Ch. 4 - If |x|1, it is known that 11x=1+x+x2+x3+ Repeat...Ch. 4 - A missile leaves the ground with an initial...Ch. 4 - To calculate a planets space coordinates, we have...Ch. 4 - 4.20 Consider the function on the interval . Use...Ch. 4 - Derive Eq. (4.31).Ch. 4 - 4.22 Repeat Example 4.8, but for .
Ch. 4 - 4.23 Repeat Example 4.8, but for the forward...Ch. 4 - 4.24 Develop a well-structured program to compute...
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- A:01 IE 0 & F1 F2 F3 b a F4 D E B FS Consider the following values: - a - 25 m; b - 5 m; a - 25 m; d - 5 m; F1 - 3 kN; F2 - 1 kN; F3 - 4 kN; F4 - 6 kN; F5 - 8 kN; a = 30°, 0 = 60°, B= 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 85.8 kN.m b) - 21.1 kN.m c) - 13.5 kN.m d) 7.9 kN.m e) 24.1 kN.m f) - 57.8 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 188.8 kN.m b) - 153.5 kN.m c) 111.6 kN.m d) - 98.9 kN.m e) 85.4 kN.m f)- 244.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 186 kN.m b) - 171 kN.m c) 155 kN.m d) 279 kN.m e) 423 KN.m 0 353 KN.m 4] What is the resultant moment of the five forces acting on the rod about point D? b) - 184.2 kN.m )-211.9 KN.m d) 126.9 kN.m e) - 27.1 KN.m ) 125.1 kN.m a) 117.8 kN.m Activate 5] What is the moment of the force F2 about point E? Go to Setting 1) 32.3 kN.m a) 11.7 KN.m b) 19.8 kN.m c) 54.6 kN.m d) 9.1 kN.m e) 41.1…arrow_forward6 m! 1.0 m T3 2 m T2 3 m 2 m 2 m The magnitude of one of the forces is T1 = 100 kN. Find the rectangular representation of T1. * The magnitude of one of the forces is T¡ = 100kN. Find the rec tan gular representation of T1. O T = (15.62 i + 31.23 j – 93.70 k) N O T, = (15.62 i + 31.23 j + 93.70 k) N O T1 = (-15.62 i + 31.23 j + 93.70 k) N O T, = (-15.62 i – 31.23 j + 93.70 k) Narrow_forward6 m! 1.0 m TS 2 m 3 m 2m 2 m The magnitude of one of the forces is T2 = 80 kN. Find the rectangular representation of T2. * The magnitude of one of the forces is T2 = 80KN. Find the rec tan gular representation of T2. T2 = (-22.86 i + 34.29 / + 68.57 k) N T2 = (-22.86 i – 34.29 j + 68.57 k) N T2 = (22.86 i - 34.29 j + 68.57 k) N T2 = (22.86 i- 34.29 /-68.57 k) Narrow_forward
- A ring is attached with 3 ropes. A force of P=250 lb is applied to the ring. The direction of the rope D is defined by 3 directions from each axis x, y and z: a = 80°, B = 45° and y = 30°. The direction of the rope C is defined by 2 directions from a plane and an axis: 0 70° and 8 = 20°. = X D B B d A 0 S What is the cartesian vector form of the tension Tp ?arrow_forwardrevinus (1548-1642 200 N -100 cos sin 017 F 2.sin 02+ F !. 00•-100sin 60 – 90 sin 43 (R.) +(R»} V(192.4) +(60.8) = 202N Ex ( 2): The 200 N force is a resultant of two forces, one of the forces "P" has the direction along the tine AB and the other force "Q" is on the horizontal direction, determine em. 60° ços OF F2.cos 0 2 Fi.cos 0F F2.cos 02 $ 60+Qcos(0) 1------- ------ 02arrow_forwardF1 F2 a C F3 A d F4 D Consider the following values: - F5 a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 2 kN; F3 = 5 kN; F4 = 7 kN; F5 = 3 kN; a = 30° , 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A?arrow_forward
- F1 F2 F3 A B d b F4 D F5 Consider the following values: - a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 - 6 kN; F2 - 7 kN; F3 = 8 kN; F4 - 9 kN; F5 - 10 kN; a = 30°, 0 = 45° , B = 60° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 154.8 kN.m b) 111.9 KN.m c) - 174.6 kN.m d) 162.9 kN.m e) 214.1 kN.m 0-47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? | a) - 209.3 kN.m b) 215.7 kN.m c) 311.6 kN.m d) - 98.9 kN.m e) 125.4 kN.m f) - 124.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 204 kN.m b) 121 kN.m c) 146 kN.m d) - 279 kN.m e) 241 kN.m D- 353 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) – 212.7 kN.m b) 182.7 kN.m e) - 21.9 kN.m d) 36.9 kN.m e) - 27.1 kN.m ) 30.1 kN.m 5] What is the moment of the force F2 about point E? a) 100.3 kN.m b) 118.1 kN.m c) 224.6 kN.m d) 193.1 kN.m e) 151.1 kN.m ) 221.3 kN.m E.arrow_forwardA. Find the values of a such that vectors and are orthogonal. B. Find the domains of the vector-valued function 7(t) = e' i+ j+ In(t? – 4) karrow_forwardConsider the following vector: • J= 17 @ 195° What is the x component of J? 17 @ 195° 16.42 @ 90° 17 @ 15° O 17 @ 180° (10, 16.42) O -16.42 @ 180° (0,17) 16.42 @ 180° 16.42 @ 0° 16.42 @ 195° 16.42 @ 15° O (17,0)arrow_forward
- Cartesian coordinat system; A(0,0,0) B(3,4,0) C(3,4,4) A/ M АВ AB OM, F =-20i+10 j +15k N is applied to point C Moment of force F about point A; M, B/ M = AC ® F C/ M AB = AB O F Moment of force F about point B; M, D/ M, = BC ® F Moment of force F about line AB; MAB Which following one is WRONG? E/ M AB OM, ABarrow_forward5. F. nd the integrod Value of the function below by using trape zuidal Yule ; y =x°+ x*- 5 (a:1,b=5;Ne 8).arrow_forwardThe direction of the resultant approximately is * For the figure below, the resultant is.: * -42 CSumFy: * -20 20 N 75 N 35 165.22 N 45° -45 220.12 N 50 N 150 N 20 156.3 N 42 161.65 N 80 N -35 45 160 N 200 N Other: -134.45 N 242.17 N 300.15 N 170 N 325.25 N CSumFx= * 350,54 N 170. 56 N 150.32 N 210.76 N Other: -120.16 N 198.34 N -180.33 N -160.54 N O O OOOOarrow_forward
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