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Manning's formula for a rectangular channel can be written as
where
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- 2. Four reservoirs connection is shown below. Determine the discharges in each pipe using Manning's Equation withn = 0.012. Draw the final hydraulic gradient line (HGL). Diameter of pipe (m) Length of pipe (m) 1500 800 Pipe AX 0.30 BX 0.25 XY CY 400 0.30 500 0.20 DY 1600 0.20 WS ELEV. = 300 m wS ELEV. = 150 m WS ELEV. = 100 m ELEV. = 75 m WS D. Yarrow_forward1. Determine the depth (yo), bearing area (A), and wet circumference (P) of a trapezoidal shaped channel with the following known data mi = 2,5 m2 = 3,5 b = 5,5 m 1. mi Q = 24,5 m³/s m2 n= 0,014 So = 0,0003 %3Darrow_forwardWater flows steadily along a horizontal open channel of uniform width, over a broad-crested weir. The channel bed upstream from the weir (to the left) is d metres above the channel bed downstream from the weir (to the right), as shown in the figure below. The volume flow rate per unit width is Q = 6 m? s-1, and upstream the depth of the water is h1 = 3 m. Take the magnitude of the acceleration due to gravity as g = 10 ms 2. hi D p. h2 U2 (a) Find the upstream speed u1, and show that the flow is subcritical there. (b) Find the specific energy E (in m) for the flow upstream. (c) By applying Bernoulli's equation along a suitable streamline, show that the depth h2 in the downstream section of the channel satisfies the equation 5h – (16 + 5d)h+9 = 0.arrow_forward
- Consider the uniform flow of water in the triangular channel shown in the figure. The channel bed slope is 0.003 and the roughness coefficient is 0.025. The flow rate in the channel is 25 m³/s. What is the normal depth? a.3.48 m b.2.28 m c.4.70 m d. 1.98 m What is the critical depth? a. 1.98 m b.4.70 m c.3.48 m d.2.28 m If the flow depth at a certain section of the channel is 2 m, the flow is: a.subcritical b.critical c.supercritical d.can not be determined VAI 2 1arrow_forward1) The equation for finding the water head in an open channel flow is given below. is given. In this equation, the channel width (B=8 units) and the flow rate of the water in the channel (Q=5 units) Since the height of the water in the channel is estimated to be between x1-0 and x2=2 units, What is the actual height (H) of the water in the channel? (You can make your transactions less than 0.05% of the approximate error.) continue until it is lower than and take six digits after the comma) 0.471405 x ( BH)5/% f(H) = %3D (B + 2 x H)2/3arrow_forwardIn gradually varied flow, the channel bottom, water surface, and EGL are parallel. Select one: O True O Falsearrow_forward
- 2.Water flows through a rectangular channel with a width b = 2 m and a height (Pw) = 1 m, the flow rate ranges from Qmin = 0.02 m^3/s and Qmax = 0.60 m^3/s. This flow rate is measured using Rectangular sharp-crested weir Triangular sharp-crested with = 90^o Broad-crested weir Plot onto the graph Q = Q(H) for each type of weir and give your analysis which type of weir is most appropriate to applyarrow_forwardQ(3):A rectangular channel is to be dug in the rocky portion of a soil. Find its most economical cross-section if it is to convey 12 m3/s of water with an average velocity of 3 m/s. Take Chezy's constant C = 50.arrow_forward3. The daily streamflow data of a river for a drainage area of 5,810 km are given in table below. Determine the equivalent depth of the direct runoff by separating the baseflow. (Use recession curve method- N-0.8A) Time (days) Flow (m'/s) 1,600 1,550 5,000 11,300 8,600 6,500 5,000 3,800 Time (days) Flow (m/s) 2,800 2,200 1,850 1,600 1.330 1,300 1,280 9. 10 11 12 13 14 15 1234 n078arrow_forward
- 7.5 m -2.0 m 6.0 m h where b = weir width (m) 2 g = gravitational acceleration (m/s) h = height of water above the weir edge (m) 2.0 m 1.0 m wide weir water flows out through this opening The surge tank pictured (shown with clear sides for illustration purposes) is used to even out variable flows. During periods of high flow, excess water is diverted to the surge tank where it flows out more slowly over the weir. The volumetric flow over the weir is V = 0.011 * b* g¹/2h³/2 Assuming no excess flow is currently being diverted to the surge tank, determine the time required for the water level in the tank to become 6.25 m if the initial height is 7.5 marrow_forwardWater áows in a rectangular channel of width, w. In some cases, the water may suddenly increase in elevation as shown in the figure (from h1 to h2) through a highly disturbed region called a hydraulic jump. Assume the velocity is uniform at stations 1 and 2, and assume the pressures are distributed hydrostatically. Using the Bernoulli equation and whatever other necessary equation(s), finnd the equation (cubic) for the downstream depth, h2, in terms of h1, V1, and g.arrow_forwardEXERCISE 3: Water flows at a rate of q=3.13 m/s.m in a rectangular channel shown in the figure on the right. Ja0.00023 no0.015 • Determine the uniform flow depths and the types of flow in Ja 0.00762 Pe-0.015 different parts of the channel. Draw the water surface profile in the transition zone,arrow_forward
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