PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Chapter 4, Problem 19P
To determine
The change in design life of the rigid pavement when the modulus of rupture is changed.
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An agency uses the following formula to determine pavement condition rating,
PCR = 99.3 − 5.51 (5.0-ROUGH) − 1.59 LNALL − 0.221 AVGOUT − 0.0306 LONG − 0.531 TRAN,
where we have the following.
ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mile
And, present serviceability rating is determined as the following.
PSR = 5e−0.0051118 · IRI − 0.0016027
A pavement section has the following distress data.
IRI = 108 in./mi Alligator cracking = 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/mi
Determine the current PCR for this section.
PCR =
Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI…
Chapter 4 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10P
Ch. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32P
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- A rigid pavement is being designed with the same parameters as used in Problem 4.5. The modulus of subgrade reaction is 300 lb/in? and the slab thickness is determined to be 8.5 inches. The load transfer coefficient is 3.0, the drainage coefficient is 1.0, and the modulus of elasticity is 4 million 1b/in?. What is the design modulus of rupture? (Assume that any parameters not given in this problem are the same as those given in Problem 4.5.) 4.5 for reference: A flexible pavement was designed for the following daily traffic with a 12-year design life: 1300 single axles at 8000 Ib each, 900 tandem axles at 15,000 1b each, 20 single axles at 40,000 Ib each, and200 tandem axles at 40,000 lb each. The highway was designed with 4 inches of HMA wearing surface,arrow_forwardAn agency uses the following formula to determine pavement condition rating, PCR = 99.3 5.51 (5.0-ROUGH) 1.59 LNALL 0.221 AVGOUT 0.0306 LONG where we have the following. ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mile And, present serviceability rating is determined as the following. PSR = 5e-0.0051118 IRI-0.0016027 A pavement section has the following distress data. IRI = 106 in./mi Alligator cracking 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/mi Determine the current PCR for this section. PCR = 0.531 TRAN, Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi)…arrow_forwardQ3/Choose the correct answer 1. In general PSI for flexible pavement depend on............ Va. Cracking, Patching and Rutting b. Cracking and Patching c. Patching and Rutting d. Rutting 2. The Maximum contraction joint spacing for plain jointed concrete pavement is C. 3.5 m b. 4.5 m c. 5.5 m d. Depends on traffic load 3. The relationship between A psi and age of pavement is...... a. A psi co age Apsi ∞ (1/age) c. A psi 02(1/age) d. Non of the above 4. The surface of the pavement should be a. Smooth b. Rough 5. Which type of aggregates gives good workability? a. Round b. Flaky c. Angular 6. Rutting may be avoided by a. Good compaction . Sufficient enough to resist skid b. Good drainage 7. Bleeding may be avoided by a. Water voids b. Air voids c. Asphalt type 12. Tie bars in cement concrete pavements are at a. Expansion joints d. All the above acceptable c. High filler percent All the above 8. The good drainage in pavement can La Increase the pavement life b. Decrease the pavement life…arrow_forward
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