Pearson eText Genetic Analysis: An Integrated Approach -- Instant Access (Pearson+)
3rd Edition
ISBN: 9780135564172
Author: Mark Sanders, John Bowman
Publisher: PEARSON+
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Chapter 4, Problem 25P
The following crosses are performed between morning glories whose flower color is determined as described in Problem
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Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54
cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three
genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype
A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth
conditions and that the alleles of the three genes are additive.
If the F1 plants are self crossed, what is the expected proportion of F2 plants with the
genotype A₁A₁B₁B₁C₁C₁
1/8
1/32
1/16
1/4
1/64
E. W. Lindstrom crossed two corn plants with green seedlings and obtained the following progeny: 3583 green seedlings, 853 virescentwhite seedlings, and 260 yellow seedlings .
Q. Give the genotypes for the green, virescent-white, and yellow progeny.
A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous wild type male.
The resulting progeny were allowed to mate with one another to produce the data set. Three repetitions of the experiment were conducted. The following data were produced from the crosses. Test these data to determine if they are significantly different from the expected phenotypic ratio. Use the 5% level of significance. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject for each experiment.
Wild eye Wild body – 112, Wild eye Ebony body – 40, Sepia eye Wild body – 35, Sepia eye Ebony body – 11
Chapter 4 Solutions
Pearson eText Genetic Analysis: An Integrated Approach -- Instant Access (Pearson+)
Ch. 4 - 1. Define and distinguish incomplete penetrance...Ch. 4 -
2. Define and distinguish epistasis and...Ch. 4 - When working on barley plants, two researchers...Ch. 4 - Fifteen bacterial colonies growing on a complete...Ch. 4 - 5. In a type of parakeet known as a “budgie,”...Ch. 4 - 6. The and blood groups are given below for four...Ch. 4 - The wild-type color of horned beetles is black,...Ch. 4 - 8. Two genes interact to produce various...Ch. 4 - Prob. 9PCh. 4 - 10. In rats, gene produces black coat color if the...
Ch. 4 - 11. In the rats identified in Problem, a third...Ch. 4 - Using the information provided in Problems 10 and...Ch. 4 - 13. Total cholesterol in blood is reported as the...Ch. 4 - 14. Flower color in snapdragons results from the...Ch. 4 - 5. A plant line with reduced fertility comes to...Ch. 4 - Prob. 16PCh. 4 - The coat color in mink is controlled by two...Ch. 4 - Prob. 18PCh. 4 - 19. Feather color in parakeets is produced by the...Ch. 4 - Brachydactyly type D is a human autosomal dominant...Ch. 4 - 21. A male and a female mouse are each from...Ch. 4 - Xerodermapigmentosum (XP) is an autosomal...Ch. 4 - 23. Three strains of green-seeded lentil plants...Ch. 4 - Blue flower color is produced in a species of...Ch. 4 - 25. The following crosses are performed between...Ch. 4 - Two pure-breeding strains of summer squash...Ch. 4 - Marfan syndrome is an autosomal dominant disorder...Ch. 4 - 28. Yeast are single-celled eukaryotic organisms...Ch. 4 - Prob. 29PCh. 4 - Dr. Ara B. Dopsis and Dr. C. Ellie Gans are...Ch. 4 - Human ABO blood type is determined by three...Ch. 4 - In rabbits, albinism is an autosomal recessive...Ch. 4 - Dr. O. Sophila, a close friend of Dr. Ara B....Ch. 4 - In a breed of domestic cattle, horns can appear on...Ch. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - 37. Epistatic gene interaction results in a...Ch. 4 - 38. Draw a pedigree containing two parents and...
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- Flower color in petunias is determined by the biochemical pathway shown below: A_ B_ C_ Yellow Orange > Green Blue aa bb Plants of genotype AAbbcc were mated to plants of genotype AaBbCc. Determine the phenotypic ratio expected from this cross and fill in the spaces in the ratio below with whole numbers in lowest form. lf none are expected in a class, then type the number 0 in the space. Yellow: Orange : Green: Bluearrow_forwardThe oval shaped pollen is dominant to round shape pollen. However, the oval shape character has only 35% penetrance. When a heterozygous oval shaped pollen plant is crossed with a homozygous round shape pollen plant, what is the probability that the first pollen produced will be round shape?arrow_forwardIn corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of corn plants (i.e. the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male-fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines. Using the following color-coded circles, simulate the crosses indicated below. Put the illustrations of crosses in the spaces provided. Be sure to include in the labels the genotypes and phenotypes of the offspring in each cross. Big light green circle - male-sterile cytoplasm Big orange circle - male-fertile cytoplasm Small orange circle - FF nucleus Small half-light green-half-orange circle - Ff nucleus Small light-green circle - ff nucleusarrow_forward
- A) Describe the data you collect from the Purple 1 x Purple 2 cross. Predict the genotype of each of the parent plants. Explain your predictions using data from the experiment. (Again, you may need to use data from other crosses!) B) Consider the offspring, the next generation (F1), from the Purple 1 x Purple 2 cross. What is the probability of a green stem plant? How do you know this? C) What is the probability in the F2 generation of a green stem offspring? Use a Punnett square(s) and quantitative data to explain your thinking. Upload your Punnett square(s).arrow_forwardIn corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (ie the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines Using the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm of each individual in the cross Legend male sterile cytoplasm Male fertile cytoplasm FF nucleus Ff nucleus ff nucleus A. Male sterile female x FF male Explain the phenotype of the offspring B. Male sterile female x Ff male Explain the phenotype of the offspringarrow_forwardA horticulturist runs a test cross with an offspring (F1 generation) purple plant from Question 8. The phenotypic frequencies of the resulting offspring are 50% white and 50% purple. What is the true genotype of this offspring (F1 generation) purple plant?arrow_forward
- Table 1: F1 ebony flies - 0 F1 non-ebony flies - 560 F1 stubble flies - 560 F1 non-stubble flies - 0 The researcher collects and crosses male and female flies from the F1 generation. In the resulting offspring, F2, there are both stubble and ebony flies. Draw a Punnett Square to illustrate the F1 cross for the stubbly phenotype showing the individual gametes of each parent and the combination in the resulting offspring.arrow_forwardNicotiana glutinosa (2 n = 24) and N. tabacum (2 n = 48) are two closely related plants that can be intercrossed, but the F1 hybrid plants that result are usually sterile. In 1925, Roy Clausen and Thomas Goodspeed crossed N. glutinosa and N. tabacum and obtained one fertile F1 plant . They were able to self-pollinate the flowers of this plant to produce an F2 generation. Surprisingly, the F2 plants were fully fertile and produced viable seeds. When Clausen and Goodspeed examined the chromosomes of the F2 plants, they observed 36 pairs of chromosomes in metaphase I and 36 individual chromosomes in metaphase II. Explain the origin of the F2 plants obtained by Clausen and Goodspeed and the numbers of chromosomes observed.arrow_forwardWhat are the expected phenotypic ratios from the following cross:Tt Rr yy Aa × Tt rr YY Aa, where T = tall, t = dwarf, R = round,r = wrinkled, Y = yellow, y = green, A = axial, a = terminal; T, R,Y, and A are dominant alleles. Note: Consider using the multiplication method in answering this problemarrow_forward
- A snapdragon with pink petals, black anthers, and longstems was allowed to self-fertilize. From the resultingseeds, 650 adult plants were obtained. The phenotypesof these offspring are listed here.78 red long tan26 red short tan44 red long black15 red short black39 pink long tan13 pink short tan204 pink long black68 pink short black5 white long tan2 white short tan117 white long black39 white short blacka. Using P for one allele and p for the other, indicatehow flower color is inherited.b. What numbers of red : pink : white would havebeen expected among these 650 plants?c. How are anther color and stem length inherited?d. What was the genotype of the original plant?e. Do any of the three genes show independentassortment?f. For any genes that are linked, indicate the arrangements of the alleles on the homologous chromosomes in the original snapdragon, and estimate thedistance between the genesarrow_forwardKernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of each offspring with the following genotypes: (Note: 4 alleles – red; 3 – medium red; 2 – intermediate red; 1 – light red; 0 – white). CAPITAL letters only and with spaces when applicable. AABb - AaBb - AABB - aaBb - aabb -arrow_forwardTwo genes in chromosome 7 of corn are identified by the recessive alleles gl (glossy), determining glossy leaves, and ra (ramosa), determining branching of ears. When a plant heterozygous for each of these alleles was crossed with a homozygous recessive plant, the progeny consisted of the following genotypes with the numbers of each indicated: Calculate the frequency of recombination (as a decimal) between these genes. Gl ra / gl ra Gl Ra/gl ra 98 7 gl Ra/gl ra gl ra / gl ra 91 4arrow_forward
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