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Chemistry: Principles and Reactions

8th Edition
William L. Masterton + 1 other
Publisher: Cengage Learning
ISBN: 9781305079373

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Section
BuyFindarrow_forward

Chemistry: Principles and Reactions

8th Edition
William L. Masterton + 1 other
Publisher: Cengage Learning
ISBN: 9781305079373
Chapter 4, Problem 33QAP
Textbook Problem
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Sulfuric acid is needed in a lead storage battery. A 25.00-mL sample of "battery acid" taken from a functioning battery requires 53.7 mL of 4.552 M NaOH for complete neutralization. What is the molarity of the battery acid?

Interpretation Introduction

Interpretation:

The molarity of battery acid should be calculated.

Concept introduction:

Number of moles is equal to the ratio of given mass to the molar mass.

The mathematical expression is given by:

Number of moles = given massmolar mass

Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.

The mathematical expression is given by:

Molarity = moles of solute volume of solution in liters

A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:

M1V1=M2V2

Where, M1 and M2 are molarity of the solution

V1 and V2 are volume of the solution

Explanation of Solution

The reaction between sulfuric acid and sodium hydroxide is:

H2SO4+2NaOHNa2SO4+2H2O

Now, molarity of sodium hydroxide is 4.552 M

Volume of sodium hydroxide is 53.7 mL

Volume of battery acid is 25.00 mL

Therefore,

Molarity =moles of solute volume of solution in liters

Number of moles = Molarity × Volume of solution in liters

Convert given volume that is 53.7 mL in liters

Since, 1 mL = 0.001 L

Thus, 53.7 mL×1 L1000 mL=0.0537 L

Number of moles = 4.552 moles/L × 0.0537 L= 0.244 mole

Number of moles of sodium hydroxide = 0

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Chapter 4 Solutions

Chemistry: Principles and Reactions
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