The simple beam ACE shown in the figure is subjected to a triangular load of maximum intensity q0= 200 lb/ft at a = 8 ft and a concentrated moment M = 400 Ib-ft at A.
- Draw the shear-force and bending-moment diagrams for this beam,
- Find the value of distanced that results in the maximum moment occurring at L/2. Draw the shear-force and bending-moment diagrams for this case.
- Find the value of distance a for which Mmaxis the largest possible value.
(a).
To draw: Shear force and bending moment diagrams for simply supported beam.
Answer to Problem 4.5.27P
The
Explanation of Solution
Given Information:
Max load
Distance
Moment
Length
Concept Used:
Shear forces and bending moments at various points shall be calculated.
Calculation:
Draw free body diagram
From equilibrium
Also,
From equation
Shear Force calculation
SFD
Bending Moment calculation
BMD
Conclusion:
The
(b).
To find: The value of
Answer to Problem 4.5.27P
The distance is
Explanation of Solution
Given Information:
Max load
Distance
Moment
Length
Concept Used:
Shear forces and bending moments at various points shall be calculated.
Calculation:
The free body diagram is as follows:
From equilibrium
Also,
From equation
Bending moment
On solving above equation, we get:
Shear Force calculation:
SFD
Bending Moment calculation:
BMD
Conclusion:
The distance is
(c).
To find: The value of
Answer to Problem 4.5.27P
The distance is
Explanation of Solution
Given Information:
Max load
Distance
Moment
Length
Concept Used:
Bending moment shall be calculated.
Calculation:
The free body diagram:
From part
Bending moment
And maximum bending moment is
Conclusion:
The distance is
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Chapter 4 Solutions
Mechanics of Materials - Text Only (Looseleaf)
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- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning