Concept explainers
(a)
Interpretation: The orientation of
Concept introduction: Cis–trans isomers are geometrical isomers. Cis-isomer contains two groups on the same side of the ring. Trans-isomer contains two groups on the opposite side of the ring.
(b)
Interpretation: The location of substituent on
Concept introduction: Cis–trans isomers are geometrical isomers. Cis-isomer contains two groups on the same side of the ring. Trans-isomer contains two groups on the opposite side of the ring.
(c)
Interpretation: The orientation of an equatorial
Concept introduction: Cis–trans isomers are geometrical isomers. Cis-isomer contains two groups on the same side of the ring. Trans-isomer contains two groups on the opposite side of the ring.
(d)
Interpretation: The orientation of substituent
Concept introduction: Cis–trans isomers are geometrical isomers. Cis-isomer contains two groups on the same side of the ring. Trans-isomer contains two groups on the opposite side of the ring.
(e)
Interpretation: The location of substituent on
Concept introduction: Cis–trans isomers are geometrical isomers. Cis-isomer contains two groups on the same side of the ring. Trans-isomer contains two groups on the opposite side of the ring.
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- Draw the bond-line formula of 3,4-dimethylhexane. Is geometric isomerism observed in 3,4-dimethylhexane? What structural features must be present for stereoisomers to exist? (4 marks) (b) (1) Using Fischer projection, draw all the stereoisomers of 3-chloro-2-hydroxypentanoic acid. (4 marks) (ii) Assign the chiral centre(s) with R/S configurations in part (b)(i). Indicate which are enantiomers, diastereomers and meso compounds (if any).arrow_forwardOn the left is a stereorepresentation of glucose (we discuss the structure and chemistry of glucose in Chapter 25). (a) Convert the stereorepresentation on the left to a planar hexagon representation. (b) Convert the stereorepresentation on the left to a chair conformation. Which substituent groups in the chair conformation are equatorial? Which are axial?arrow_forwardFollowing is a chair conformation of cyclohexane with the carbon atoms numbered 1 through 6. (a) Draw hydrogen atoms that are above the plane of the ring on carbons 1 and 2 and below the plane of the ring on carbon 4. (b) Which of these hydrogens are equatorial? Which are axial? (c) Draw the alternative chair conformation. Which hydrogens are equatorial? Which are axial? Which are above the plane of the ring? Which are below it?arrow_forward
- Glucose is a simple sugar with five substituents bonded to a six-membered ring.a. Using a chair representation, draw the most stable arrangement of these substituents on the six-membered ring.b. Convert this representation into one that uses a hexagon with wedges and dashed wedges.c. Draw a constitutional isomer of glucose.d. Draw a stereoisomer that has an axial OH group on one carbon.arrow_forwardUse a Newman projection about the indicated bond to draw the most stable conformer for each compound. (a) 3-methylpentane about the C2¬C3 bondarrow_forwardUsing the cyclohexane with the C's numbered as shown, draw a chair form that fits each description. a.) The ring has an axial CH3 group at C1 and an equatorial OH on C2.b.) The ring has an equatorial CH3 group on C6 and an axial OH group on C4.c.) The ring has equatorial OH groups on C1, C2, and C5.arrow_forward
- Using the cyclohexane with the C’s numbered as shown, draw a chair form that fits each description. a. The ring has an axial CH3 group at C1 and an equatorial OH on C2. b. The ring has an equatorial CH3 group on C6 and an axial OH group on C4. c. The ring has equatorial OH groups on C1, C2, and C5.arrow_forwardRank the following groups in order of decreasing priority. −C≡CH, −CH(CH3)2, −CH2CH3, −CH=CH2arrow_forwardIs the reaction of 2-butene with HBr regioselective? a. Is it stereoselective? b. Is it stereospecific?arrow_forward
- Draw the planar (Haworth) structure for cis-1-ethyl-2- methylcyclohexane. (b) Draw the two ring - flipped chair conformations. (c) Circle the more stable chair conformation (circle both if they are equal in energy). Draw the Haworth structure and the two ring-flipped conformations of 1, 2, 4- trimethylcyclohexane (Compound D) on the frames below, b) Circle the more stable chair conformation (circle both if they are equal in energy). Haworth Structurearrow_forward1. Use a Newman projection about the indicated bond to draw the most stable conformer for each compound. (a) 3-methylpentane about the C2 ¬ C3 bond (b) 3,3-dimethylhexane about the C3 ¬ C4 bond2. refer to the questions below:arrow_forwardConsider the tricyclic structure B. (a) Label each substituent on the rings as axial or equatorial. (b) Draw B using chair conformations for each six-membered ring. (c) Label the atoms on the ring fusions (the carbons that join each set of two rings together) as cis or trans to each other.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningOrganic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning