Chapter 4, Problem 4.57QP

(a)

Interpretation Introduction

Interpretation:

The molarities of given solutions are should be determined.

Concept introduction:

Molarity

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole

Mole is given by the ratio between mass of the compound and molar mass of the compound.

$\text{Mole}\text{=}\frac{\text{Mass}\text{(g)}}{\text{Molar}\text{mass}\text{(g)}}$

(b)

Interpretation Introduction

Interpretation:

The molarities of given solutions are should be determined.

Concept introduction:

Molarity

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole

Mole is given by the ratio between mass of the compound and molar mass of the compound.

$\text{Mole}\text{=}\frac{\text{Mass}\text{(g)}}{\text{Molar}\text{mass}\text{(g)}}$

(c)

Interpretation Introduction

Interpretation:

The molarities of given solutions are should be determined.

Concept introduction:

Molarity

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole

Mole is given by the ratio between mass of the compound and molar mass of the compound.

$\text{Mole}\text{=}\frac{\text{Mass}\text{(g)}}{\text{Molar}\text{mass}\text{(g)}}$