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Chapter 4, Problem 4.60EP

(a)

Interpretation Introduction

Interpretation:

Completion of the following table of chemical formulas for ionic compounds.  For each compound, the negative ion present is listed on the left side of the table and the positive ion present is listed at the top.

  Na+Mg2+Al3+Si4+Br-

Concept Introduction:

Ions are formed by the loss or gain of electrons.  The formation of ion requires the presence of two elements, these two elements are: one is metal atom and another one is non-metal atom.  Metal atom loses electron and non-metal atom accepts electron.

The ratio in which positive and negative ions combine is the ratio which achieves charge neutrality for the resulting compound.

There are three rules to remember while writing the chemical formulas.  They are as follows:

  • First write the symbol for positive ion.
  • The charges of the ions are not shown in the formula.
  • The numbers in the formula give the combining ratio for the ions.

(a)

Expert Solution
Check Mark

Answer to Problem 4.60EP

The chemical formulas of a compound when combines with given ions are as follows:

  Na+Mg2+Al3+Si4+Br-NaBrMgBr2AlBr3SiBr4

Explanation of Solution

Br- ion combines with  Na+ ions combine in 1 to 1 ratio because this combination causes the resultant charges to zero.  One Br- ion give one unit of positive charge.  One Na+ ion results in one unit of negative charge.  Thus, the chemical formula for the compound is NaBr.

Br- ion combines with  Mg2+ ions combine in 2 to 1 ratio because this combination causes the resultant charges to add to zero.  Two Br- ion give two units of positive charges.  One Mg2+ ion results two units of negative charges.  Thus, the chemical formula for the compound is MgBr2.

Br- ion combines with  Al3+ ions combine in 3 to 1 ratio because this combination causes the resultant charges to zero.  Three Br- ion give three units of positive charges. One Al3+ ion result in three units of negative charges.  Thus, the chemical formula for the compound is AlBr3.

Br- ion combines with Si4+ ions combine in 4 to 1 ratio because this combination causes the resultant charges to zero.  Four Br- ions give four units of positive charges.  One Si4+ ion result in four units of negative charges.  Thus, the chemical formula for the compound is SiBr4.

(b)

Interpretation Introduction

Interpretation:

Completion of the following table of chemical formulas for ionic compounds.  For each compound, the negative ion present is listed on the left side of the table and the positive ion present is listed at the top.

  Na+Mg2+Al3+Si4+S2-

Concept Introduction:

Ions are formed by the loss or gain of electrons.  The formation of ion requires the presence of two elements, these two elements are: one is metal atom and another one is non-metal atom.  Metal atom loses electron and non-metal atom accepts electron.

The ratio in which positive and negative ions combine is the ratio which achieves charge neutrality for the resulting compound.

There are three rules to remember while writing the chemical formulas.  They are as follows:

  • First write the symbol for positive ion.
  • The charges of the ions are not shown in the formula.
  • The numbers in the formula give the combining ratio for the ions.

(b)

Expert Solution
Check Mark

Answer to Problem 4.60EP

The chemical formulas of a compound when combines given ions are as follows:

  Na+Mg2+Al3+Si4+S2-Na2SMgSAl2S3SiS2

Explanation of Solution

S2- ion combines with Na+ ions combine in 1 to 2 ratio because this combination causes the resultant charges to zero.  One S2- ion give two units of positive charges.  Two Na+ ions result in two units of negative charges.  Thus, the chemical formula for the compound is Na2S.

S2- ion combines with Mg2+ ions combine in 1 to 1 ratio because this combination causes the charges to add to zero.  One S2- ion gives two units of positive charges.  One Mg2+ ion results in two units of negative charges.  Thus, the chemical formula for the compound is MgS.

S2- ion combines with  Al3+ ions combine in 3 to 2 ratio because this combination causes the resultant charges to zero.  Three S2- ion give six units of positive charges.  Two Al3+ ions result in six units of negative charges.  Thus, the chemical formula for the compound is Al2S3.

S2- ion combines with  Si4+ ions combine SiS2 ratio because this combination causes the resultant charges to zero.  Two S2- ions give four units of positive charges.  One Si4+ ion result in four units of negative charges.  Thus, the chemical formula for the compound is SiS2.

(c)

Interpretation Introduction

Interpretation:

Completion of the following table of chemical formulas for ionic compounds.  For each compound, the negative ion present is listed on the left side of the table and the positive ion present is listed at the top.

  Na+Mg2+Al3+Si4+P3-

Concept Introduction:

Ions are formed by the loss or gain of electrons.  The formation of ion requires the presence of two elements, these two elements are: one is metal atom and another one is non-metal atom.  Metal atom loses electron and non-metal atom accepts electron.

The ratio in which positive and negative ions combine is the ratio which achieves charge neutrality for the resulting compound.

There are three rules to remember while writing the chemical formulas.  They are as follows:

  • First write the symbol for positive ion.
  • The charges of the ions are not shown in the formula.
  • The numbers in the formula give the combining ratio for the ions.

(c)

Expert Solution
Check Mark

Answer to Problem 4.60EP

The chemical formulas of a compound when combines given ions are as follows:

  Na+Mg2+Al3+Si4+P3-Na3PMg3P2AlPSi3P4

Explanation of Solution

P3- ion combines with  Na+ ions combine in 1 to 3 ratio because this combination causes the resultant charges to add to zero.  One P3- ion give three units of positive charges.  Three Na+ ions result in three units of negative charges.  Thus, the chemical formula for the compound is Na3P.

P3- ion combines with  Mg2+ ions combine in 2 to 3 ratio because this combination causes the resultant charges to zero.  Two P3- ions give six units of positive charges.  Three Mg2+ ions result in six units of negative charges.  Thus, the chemical formula for the compound is Mg3P2.

P3- ions combine with  Al3+ ions combine in 1 to 1 ratio because this combination causes the resultant charges to zero.  One P3- ion gives three units of positive charges.  One Al3+ ion results in three units of negative charges.  Thus, the chemical formula for the compound is AlP.

P3- ion combines with  Si4+ ions combine in 4 to 3 ratio because this combination causes the resultant charges to zero.  Four P3- ions give twelve units of positive charges.  Three Si4+ ions result in twelve units of negative charges. Thus, the chemical formula for the compound is Si3P4.

(d)

Interpretation Introduction

Interpretation:

Completion of the following table of chemical formulas for ionic compounds.  For each compound, the negative ion present is listed on the left side of the table and the positive ion present is listed at the top.

  Na+Mg2+Al3+Si4+N3-

Concept Introduction:

Ions are formed by the loss or gain of electrons.  The formation of ion requires the presence of two elements, these two elements are: one is metal atom and another one is non-metal atom.  Metal atom loses electron and non-metal atom accepts electron.

The ratio in which positive and negative ions combine is the ratio which achieves charge neutrality for the resulting compound.

There are three rules to remember while writing the chemical formulas.  They are as follows:

  • First write the symbol for positive ion.
  • The charges of the ions are not shown in the formula.
  • The numbers in the formula give the combining ratio for the ions.

(d)

Expert Solution
Check Mark

Answer to Problem 4.60EP

The chemical formulas of a compound when combines given ions are as follows:

  Na+Mg2+Al3+Si4+N3-Na3NMg3N2AlNSi3N4

Explanation of Solution

N3- ion combines with  Na+ ions combine in 1 to 3 ratio because this combination causes the resultant charges to zero.  One N3- ion gives three units of positive charges.  Three Na+ ions result in three units of negative charges.  Thus, the chemical formula for the compound is Na3N.

N3- ions combine with  Mg2+ ions combine in 2 to 3 ratio because this combination causes the resultant charges to add to zero.  Two N3- ion give six units of positive charges.  Three Mg2+ ions result in six units of negative charges.  Thus, the chemical formula for the compound is Mg3N2.

N3- ion combines with  Al3+ ions combine in 1 to 1 ratio because this combination causes the resultant charges to zero.  One N3- ion give three units of positive charges.  One Al3+ ion results in three units of negative charges.  Thus, the chemical formula for the compound is AlN.

N3- ion combines with  Si4+ ions combine in 4 to 3 ratio because this combination causes the resultant charges to zero.  Four N3- ions give twelve units of positive charges.  Three Si4+ ions result in twelve units of negative charges.  Thus, the chemical formula for the compound is Si3N4.

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Chapter 4 Solutions

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card

Ch. 4.3 - Prob. 3QQCh. 4.4 - In terms of subatomic particles, a Ca2+ ion...Ch. 4.4 - Prob. 2QQCh. 4.4 - Prob. 3QQCh. 4.4 - Prob. 4QQCh. 4.5 - An atom with a 1s22s22p4 electron configuration...Ch. 4.5 - Prob. 2QQCh. 4.5 - Prob. 3QQCh. 4.5 - Prob. 4QQCh. 4.5 - Prob. 5QQCh. 4.6 - Prob. 1QQCh. 4.6 - Prob. 2QQCh. 4.6 - Prob. 3QQCh. 4.7 - What is the chemical formula of the ionic compound...Ch. 4.7 - What is the chemical formula of the ionic compound...Ch. 4.7 - Given that Z2 ions are present in the ionic...Ch. 4.7 - Prob. 4QQCh. 4.8 - Prob. 1QQCh. 4.8 - Which of the following is a correct description of...Ch. 4.9 - Prob. 1QQCh. 4.9 - Prob. 2QQCh. 4.9 - Prob. 3QQCh. 4.9 - Prob. 4QQCh. 4.9 - Prob. 5QQCh. 4.9 - Prob. 6QQCh. 4.9 - The correct name for the binary ionic compound...Ch. 4.9 - Prob. 8QQCh. 4.10 - Prob. 1QQCh. 4.10 - Which of the following statements about polyatomic...Ch. 4.10 - The nitrate, sulfate, and phosphate ions have,...Ch. 4.10 - Prob. 4QQCh. 4.11 - Prob. 1QQCh. 4.11 - Prob. 2QQCh. 4.11 - Prob. 3QQCh. 4.11 - Prob. 4QQCh. 4.11 - Prob. 5QQCh. 4.11 - What is the chemical formula for the compound...Ch. 4 - Contrast the two general types of chemical bonds...Ch. 4 - Contrast the two general types of chemical...Ch. 4 - How many valence electrons do atoms with the...Ch. 4 - How many valence electrons do atoms with the...Ch. 4 - Prob. 4.5EPCh. 4 - Prob. 4.6EPCh. 4 - Write the complete electron configuration for each...Ch. 4 - Write the complete electron configuration for each...Ch. 4 - Prob. 4.9EPCh. 4 - For each of the following pairs of representative...Ch. 4 - How many of the highlighted elements in the...Ch. 4 - How many of the highlighted elements in the...Ch. 4 - Draw Lewis symbols for atoms of each of the...Ch. 4 - Draw Lewis symbols for atoms of each of the...Ch. 4 - Each of the following Lewis symbols represents a...Ch. 4 - Each of the following Lewis symbols represents a...Ch. 4 - Prob. 4.17EPCh. 4 - Prob. 4.18EPCh. 4 - What is the chemical property of the noble gases...Ch. 4 - Prob. 4.20EPCh. 4 - Prob. 4.21EPCh. 4 - Prob. 4.22EPCh. 4 - Give the chemical symbol for each of the following...Ch. 4 - Give the chemical symbol for each of the following...Ch. 4 - What would be the chemical symbol for an ion with...Ch. 4 - What would be the chemical symbol for an ion with...Ch. 4 - Fill in the blanks in each line in the following...Ch. 4 - Fill in the blanks in each line in the following...Ch. 4 - Fill in the blanks in each line of the following...Ch. 4 - Fill in the blanks in each line of the following...Ch. 4 - Identify element X by giving its chemical symbol,...Ch. 4 - Prob. 4.32EPCh. 4 - Prob. 4.33EPCh. 4 - Prob. 4.34EPCh. 4 - Prob. 4.35EPCh. 4 - Draw Lewis symbols for the following ions. a. O2...Ch. 4 - What is the charge on the monatomic ion formed by...Ch. 4 - What is the charge on the monatomic ion formed by...Ch. 4 - Indicate the number of electrons lost or gained...Ch. 4 - Indicate the number of electrons lost or gained...Ch. 4 - Which noble gas has an electron configuration...Ch. 4 - Prob. 4.42EPCh. 4 - Which noble gas is isoelectronic with each of the...Ch. 4 - Which noble gas is isoelectronic with each of the...Ch. 4 - Prob. 4.45EPCh. 4 - Indicate whether or not each of the following...Ch. 4 - Prob. 4.47EPCh. 4 - Prob. 4.48EPCh. 4 - Prob. 4.49EPCh. 4 - Write the electron configuration of the following....Ch. 4 - How many valence electrons are present in each of...Ch. 4 - Prob. 4.52EPCh. 4 - Using Lewis structures, show how ionic compounds...Ch. 4 - Using Lewis structures, show how ionic compounds...Ch. 4 - The following Lewis symbols for ions have the...Ch. 4 - Prob. 4.56EPCh. 4 - Prob. 4.57EPCh. 4 - Prob. 4.58EPCh. 4 - Prob. 4.59EPCh. 4 - Prob. 4.60EPCh. 4 - The component elements for four binary ionic...Ch. 4 - Prob. 4.62EPCh. 4 - Write the complete chemical formula (symbol and...Ch. 4 - Write the complete chemical formula (symbol and...Ch. 4 - Write the chemical formula for the ionic compound...Ch. 4 - Prob. 4.66EPCh. 4 - Prob. 4.67EPCh. 4 - What is the chemical formula of the ionic compound...Ch. 4 - A representative element (X) forms an ion with a 2...Ch. 4 - A representative element (Z) forms an ion with a...Ch. 4 - Prob. 4.71EPCh. 4 - The following questions pertain to the ionic...Ch. 4 - Prob. 4.73EPCh. 4 - Prob. 4.74EPCh. 4 - Prob. 4.75EPCh. 4 - Prob. 4.76EPCh. 4 - Prob. 4.77EPCh. 4 - Prob. 4.78EPCh. 4 - Prob. 4.79EPCh. 4 - Which of the following binary compounds would be...Ch. 4 - Name the following binary ionic compounds, each of...Ch. 4 - Name the following binary ionic compounds, each of...Ch. 4 - Calculate the charge on the metal ion in the...Ch. 4 - Calculate the charge on the metal ion in the...Ch. 4 - Prob. 4.85EPCh. 4 - Prob. 4.86EPCh. 4 - Prob. 4.87EPCh. 4 - Prob. 4.88EPCh. 4 - Name each of the following binary ionic compounds....Ch. 4 - Name each of the following binary ionic compounds....Ch. 4 - Prob. 4.91EPCh. 4 - Name each compound in the following pairs of...Ch. 4 - Prob. 4.93EPCh. 4 - Write chemical formulas for the following binary...Ch. 4 - Prob. 4.95EPCh. 4 - Write chemical formulas for the following binary...Ch. 4 - Prob. 4.97EPCh. 4 - Prob. 4.98EPCh. 4 - Fill in the blanks in each line of the following...Ch. 4 - Prob. 4.100EPCh. 4 - Prob. 4.101EPCh. 4 - Prob. 4.102EPCh. 4 - Prob. 4.103EPCh. 4 - How many oxygen atoms are present in each of the...Ch. 4 - Prob. 4.105EPCh. 4 - Prob. 4.106EPCh. 4 - Prob. 4.107EPCh. 4 - Prob. 4.108EPCh. 4 - Prob. 4.109EPCh. 4 - Prob. 4.110EPCh. 4 - How many ions are present per formula unit in each...Ch. 4 - Prob. 4.112EPCh. 4 - Name the following compounds, all of which contain...Ch. 4 - Prob. 4.114EPCh. 4 - Prob. 4.115EPCh. 4 - Prob. 4.116EPCh. 4 - Prob. 4.117EPCh. 4 - Write formulas for the following compounds, all of...Ch. 4 - Write chemical formulas for the following...Ch. 4 - Write chemical formulas for the following...Ch. 4 - Prob. 4.121EPCh. 4 - Prob. 4.122EPCh. 4 - Prob. 4.123EPCh. 4 - Prob. 4.124EP
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