Explanation The change in chemical potential is calculated by the following formula. ( Δ μ Δ p ) T = V m (1) Where, • ( Δ μ Δ p ) T is the change in chemical potential with respect to change in pressure at constant temperature. • V m is the molar volume. The molar volume is calculated by the following formula. V m = Mass Density (2) It is given that the density of copper is 8960 kg m -3 . It is given that the molar mass of copper is 63.546 g mol − 1 . The conversion of g mol − 1 to kg mol − 1 is done as, 1 g mol − 1 =10 − 3 kg mol − 1 Therefore, the conversion of 63.546 g mol − 1 in kg mol − 1 is done as, 63.546 g mol − 1 = 63 .546 × 10 − 3 kg mol − 1 Therefore, mass of copper is 63.546 × 10 − 3 kg mol − 1 . Substitute the value of mass and density in equation (2). V m = 63.546 × 10 − 3 kg mol − 1 8960 kg m -3 = 7.09 × 10 − 6 m 3 mol − 1 Therefore, the molar volume of copper is 7.09 × 10 − 6 m 3 mol − 1 . It is given that the exerted pressure increases from 100 kPa to 10 MPa . Therefore, the pressures p 1 and p 2 are 100 kPa and 10 MPa respectively

11th Edition

ISBN: 9780198769866

Author: ATKINS, P. W. (peter William), De Paula, Julio, Keeler, JAMES

Publisher: Oxford University Press

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Question

Chapter 4, Problem 4B.3AE

Interpretation Introduction

Interpretation:

The change in the chemical potential of copper has to be predicted.

Concept Introduction:

Chemical potential of a system is defined as the rate of change of free energy when 1 mol of a substance is added or removed from the system. Chemical potential of a system increases with increase in the number of molecules added in the thermodynamic system.

Expert Solution & Answer

Chapter 4 Solutions

Atkins' Physical Chemistry

Ch. 4 - Prob. 4B.1ST Ch. 4 - Prob. 4B.2ST Ch. 4 - Prob. 4A.1DQ Ch. 4 - Prob. 4A.2DQ Ch. 4 - Prob. 4A.3DQ Ch. 4 - Prob. 4A.1AE Ch. 4 - Prob. 4A.1BE Ch. 4 - Prob. 4A.2AE Ch. 4 - Prob. 4A.2BE Ch. 4 - Prob. 4A.3AE

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