Concept explainers
(a)
Calculate
(a)
Answer to Problem 54P
The orbital frequency is
Explanation of Solution
Write the expresion for
Here,
Conclusion:
Substitute
Thus, the orbital frequency is
(b)
Calculate
(b)
Answer to Problem 54P
The frequency
Explanation of Solution
If an electron rotates around the nucleus then the expression for speed is given below:
Here,
Multiply by
Value of
Write the expression for
Here,
Write the expression for frequency.
Here,
Conclusion:
Substitute
Substitute
Substitute
Thus, the frequency
(c)
Show that the mean value
(c)
Answer to Problem 54P
The mean value
Explanation of Solution
Write the expression for
Here,
Substitute
Write the expression for kinetic energy.
Here,
From above equations it can be concluded that mean value
Write the expression for kinetic energy.
Rearrange above equation for
Conclusion:
Substitute
Thus, the mean value
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Chapter 4 Solutions
MODERN PHYSICS F/SCIENTISTS+ENGR-EBK>I<
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- Why is the following situation impossible? An experiment is performed on an atom. Measurements of the atom when it is in a particular excited state show five possible values of the z component of orbital angular momentum, ranging between 3.16 x 10-34 kg ⋅ m2/s and -3.16 x 10-34 kg ⋅ m2/s.arrow_forwardwhat is the shortest wavelength of light that can be emitted by a hydrogen atom with initial configuration of 7d^1?arrow_forwardWhat is the probability of finding a hydrogen electron (n=2, l=1, ml =-1) within three bohr radii of the nucleus?arrow_forward
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