Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN: 9781337798310
Author: Peterson, John.
Publisher: Cengage Learning,
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Chapter 40, Problem 24A
To determine

(a)

The product of the given signed number (3.86)(2.1)(27.85)(32.56)

Expert Solution
Check Mark

Answer to Problem 24A

Value of the given number is -7350.49.

Explanation of Solution

Given:

  (3.86)(2.1)(27.85)(32.56) is given as a signed number

Calculation:

  (3.86)(2.1)(27.85)(32.56)

Now, count the number of negative signs in the given number, if their sum is an even number then, the product is positive and if the sum is an odd number then, the product is negative.

In this given number, there are 3 negative signs. Therefore, the product will be a negative number.

  =(3.86)(2.1)(27.85)(32.56)=(3.86)×(2.1)×(27.85)×(32.56)=7350.49

Hence, the value of the given number is -7350.49.

To determine

(b)

The product of the given signed number (8)(2.65)(0.5)(1).

Expert Solution
Check Mark

Answer to Problem 24A

Value of the given number is, 10.6

Explanation of Solution

Given:

  (8)(2.65)(0.5)(1) is given as a signed number

Calculation:

  (8)(2.65)(0.5)(1)

Now, count the number of negative signs in the given number, if their sum is an even number then, the product is positive and if the sum is an odd number then, the product is negative.

In this given number, there are two negative signs. Therefore, the product will be a positive number.

  =(8)(2.65)(0.5)(1)=(8)×(2.65)×(0.5)×(1)=10.6

Hence, the value of the given number is, 10.6

To determine

(c)

The product of the given signed number (6.3)(0.35)(2)(1)(0.05).

Expert Solution
Check Mark

Answer to Problem 24A

Value of the given number is -0.2205.

Explanation of Solution

Given:

  (6.3)(0.35)(2)(1)(0.05) is given as a signed number

Calculation:

  (6.3)(0.35)(2)(1)(0.05)

Now count the number of negative signs in the given number, if their sum is an even number then the product is positive and if the sum is an odd number then the product is negative.

In this given number, there are 3 negative sign which is an odd number. Therefore, the product will be a negative number.

  =(6.3)(0.35)(2)(1)(0.05)=(6.3)×(0.35)×(2)×(1)×(0.05)=0.2205

Hence, the value of the given number is -0.2205.

To determine

(d)

The product of the given signed number (4.03)(0.25)(3)(0.127).

Expert Solution
Check Mark

Answer to Problem 24A

Value of the given number is, 0.383

Explanation of Solution

Given:

  (4.03)(0.25)(3)(0.127) is given as a signed number

Calculation:

  (4.03)(0.25)(3)(0.127)

Now, count the number of negative signs in the given number, if their sum is an even number then, the product is positive and if the sum is an odd number then, the product is negative.

In this given number, there are four negative signs. Therefore, the product will be a positive number.

  =(4.03)(0.25)(3)(0.127)=(4.03)×(0.25)×(3)×(0.127)=0.383

Hence, the value of the given number is 0.383.

To determine

(e)

The product of the given signed number (0.03)(100)(0.10).

Expert Solution
Check Mark

Answer to Problem 24A

Value of the given number is, -0.3

Explanation of Solution

Given:

  (0.03)(100)(0.10) is given as a signed number.

Calculation:

  (0.03)(100)(0.10)

Now, count the number of negative signs in the given number, if their sum is an even number then, product is positive and if the sum is an odd number then, the product is negative.

In this given number, there are 3 negative signs. Therefore, the product will be a negative. number.

  =(0.03)(100)(0.10)=(0.03)×(100)×(0.10)=0.3

Hence, the value of the given number is, -0.3

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Chapter 40 Solutions

Mathematics For Machine Technology

Ch. 40 - List the following signed numbers in order of...Ch. 40 - Express each of the following pairs of signed...Ch. 40 - Note: For Exercises 13 through 62 that follow,...Ch. 40 - Note: For Exercises 13 through 62 that follow,...Ch. 40 - Note: For Exercises 13 through 62 that follow,...Ch. 40 - Note: For Exercises 13 through 62 that follow,...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 21 through 24, multiply the following...Ch. 40 - In Exercises 21 through 24, multiply the following...Ch. 40 - Prob. 24ACh. 40 - In Exercises 25 through 28, divide the following...Ch. 40 - In Exercises 25 through 28, divide the following...Ch. 40 - In Exercises 25 through 28, divide the following...Ch. 40 - In Exercises 25 through 28, divide the following...Ch. 40 - In Exercises 29 through 32, raise the following...Ch. 40 - Prob. 30ACh. 40 - In Exercises 29 through 32, raise the following...Ch. 40 - Prob. 32ACh. 40 - Prob. 33ACh. 40 - In Exercises 33 through 36, determine the...Ch. 40 - Prob. 35ACh. 40 - Prob. 36ACh. 40 - Prob. 37ACh. 40 - Prob. 38ACh. 40 - Prob. 39ACh. 40 - Solve each of the following problems using the...Ch. 40 - Prob. 41ACh. 40 - Prob. 42ACh. 40 - Solve each of the following problems using the...Ch. 40 - Solve each of the following problems using the...Ch. 40 - Prob. 45ACh. 40 - Solve each of the following problems using the...Ch. 40 - Prob. 47ACh. 40 - Solve each of the following problems using the...Ch. 40 - Prob. 49ACh. 40 - Prob. 50ACh. 40 - Prob. 51ACh. 40 - Prob. 52ACh. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...
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