Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN: 9781337798310
Author: Peterson, John.
Publisher: Cengage Learning,
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Chapter 40, Problem 30A
To determine

(a)

Compute the given signed number (2)5

Expert Solution
Check Mark

Answer to Problem 30A

Value of the given number is, -32

Explanation of Solution

Given:

  (2)5 is given as a signed number

Calculation:

Here digit (-2) is indicated as power of 5 i.e. fifth power of (-2)

  (2)5=(2)×(2)×(2)×(2)×(2)

Now count the number of negative signs in the given number:

1. If the sum is a even number then the product is positive.

2. if the sum is a odd number then the product is negative.

In this given number, the sum of negative signs is 5 which is an odd number. Therefore the product will be a negative number.

  =(2)×(2)×(2)×(2)×(2)=(2×2×2×2×2)=32

Hence the value of the given number is, -32

To determine

(b)

Compute the given signed number (6)2

Expert Solution
Check Mark

Answer to Problem 30A

Value of the given number is, 36

Explanation of Solution

Given:

  (6)2 is given as a signed number

Calculation:

Here digit (-6) is indicated as power of 2 i.e. square of (-6)

  (6)2=(6)×(6)

Now count the number of negative signs in the given number, if the sum is a even number then the product is positive and if the sum is a odd number then the product is negative.

In this given number, the sum of negative signs is 2 which is a even number. Therefore the product will be a positive number.

  =(6)×(6)=(6×6)=36

Hence the value of the given number is, 36

To determine

(c)

Compute the given signed number (5)3

Expert Solution
Check Mark

Answer to Problem 30A

Value of the given number is, -125

Explanation of Solution

Given:

  (2)3 is given as a signed number

Calculation:

Here digit (-5) is indicated as power of 3 i.e. cubic power of (-5)

   (5) 3 =(5)×(5)×(5)

Now count the number of negative signs in the given number:

1. If the sum is a even number then the product is positive.

2. if the sum is a odd number then the product is negative.

In this given number, the sum of negative signs is 3 which is a odd number. Therefore the product will be a negative number.

  =(5)×(5)×(5)=(5×5×5)=125

Hence the value of the given number is, -125

To determine

(d)

Compute the given signed number (2)6

Expert Solution
Check Mark

Answer to Problem 30A

Value of the given number is, 64

Explanation of Solution

Given:

  (2)6 is given as a signed number

Calculation:

Here digit (-2) is indicated as power of 6 i.e. sixth power of (-2)

  (2)6=(2)×(2)×(2)×(2)×(2)×(2)

Now count the number of negative signs in the given number:

1. If the sum is a even number then the product is positive.

2. if the sum is a odd number then the product is negative.

In this given number, the sum of negative signs is 6 which is a even number. Therefore the product will be a positive number.

  =(2)×(2)×(2)×(2)×(2)×(2)=(2×2×2×2×2×2)=64

Hence the value of the given number is, 64

To determine

(e)

Compute the given signed number (1.6)2

Expert Solution
Check Mark

Answer to Problem 30A

Value of the given number is, 2.56

Explanation of Solution

Given:

  (1.6)2 is given as a signed number

Calculation:

Here digit (-1.6) is indicated as power of 2 i.e. square of (-1.6)

  (1.6)2=(1.6)×(1.6)

Now count the number of negative signs in the given number, if the sum is a even number then the product is positive and if the sum is a odd number then the product is negative.

In this given number, the sum of negative signs is 2 which is a even number. Therefore the product will be a positive number.

  =(1.6)×(1.6)=(1.6×1.6)=2.56

Hence the value of the given number is, 2.56

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Chapter 40 Solutions

Mathematics For Machine Technology

Ch. 40 - List the following signed numbers in order of...Ch. 40 - Express each of the following pairs of signed...Ch. 40 - Note: For Exercises 13 through 62 that follow,...Ch. 40 - Note: For Exercises 13 through 62 that follow,...Ch. 40 - Note: For Exercises 13 through 62 that follow,...Ch. 40 - Note: For Exercises 13 through 62 that follow,...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 17 through 20, subtract the following...Ch. 40 - In Exercises 21 through 24, multiply the following...Ch. 40 - In Exercises 21 through 24, multiply the following...Ch. 40 - Prob. 24ACh. 40 - In Exercises 25 through 28, divide the following...Ch. 40 - In Exercises 25 through 28, divide the following...Ch. 40 - In Exercises 25 through 28, divide the following...Ch. 40 - In Exercises 25 through 28, divide the following...Ch. 40 - In Exercises 29 through 32, raise the following...Ch. 40 - Prob. 30ACh. 40 - In Exercises 29 through 32, raise the following...Ch. 40 - Prob. 32ACh. 40 - Prob. 33ACh. 40 - In Exercises 33 through 36, determine the...Ch. 40 - Prob. 35ACh. 40 - Prob. 36ACh. 40 - Prob. 37ACh. 40 - Prob. 38ACh. 40 - Prob. 39ACh. 40 - Solve each of the following problems using the...Ch. 40 - Prob. 41ACh. 40 - Prob. 42ACh. 40 - Solve each of the following problems using the...Ch. 40 - Solve each of the following problems using the...Ch. 40 - Prob. 45ACh. 40 - Solve each of the following problems using the...Ch. 40 - Prob. 47ACh. 40 - Solve each of the following problems using the...Ch. 40 - Prob. 49ACh. 40 - Prob. 50ACh. 40 - Prob. 51ACh. 40 - Prob. 52ACh. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...Ch. 40 - Substitute the given numbers for letters in the...
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