Explanation Given: The given function is y = ln x x . Calculation: The given interval is [ 1 , 3 ] . Use quotient rule : ( f g ) ' = f ' ⋅ g − g ' ⋅ f g 2 y = ln x x y ' = d d x ( ln x ) ⋅ x − d d x ( x ) ⋅ ( ln x ) x 2 y ' = 1 x ⋅ x − ln x x 2 y ' = 1 − ln x x 2 For critical point y ' = 0

Loose-Leaf Version for Calculus: Early Transcendentals Single Variable

4th Edition

ISBN: 9781319312886

Author: Rogawski, Jon, Adams, Colin, FRANZOSA, Robert

Publisher: W. H. Freeman

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Question

Chapter 4.2, Problem 57E

To determine

The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 56E

Chapter 4.2, Problem 58E

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Chapter 4 Solutions

Loose-Leaf Version for Calculus: Early Transcendentals Single Variable

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The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

Solution Summary: The author calculates the minimum and maximum values of a given function in the given interval by comparing with critical and end points.

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The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4 Solutions