The time required for one complete revolution of very high energy proton in a Fermilab accelerator.

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Chapter 43, Problem 4P

To determine

The time required for one complete revolution of very high energy proton in a Fermilab accelerator.

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An antiproton p has the same rest energy as a proton. It is created inthe reaction p + p → p + p + p + p. In an experiment, protons at rest in the laboratory are bombarded with protons of kinetic energy Ek, which must be great enough so that kinetic energy equal to 2mc2 can be converted into the rest energy of the two particles. In the frame of the laboratory, the total kinetic energy cannot be converted into rest energy because of conservation of momentum. However, in the zero-momentumreference frame in which the two initial protons are moving toward each other with equal speed u, the total kinetic energy can be converted into rest energy. (a) Find the speed of each proton u such that the total kinetic energy in the zero-momentum frame is 2mc2. (b) Transform to the laboratory’s frame in which one proton is at rest, and find the speed u of the other proton. (c) Show that the kinetic energy of the moving proton in the laboratory’s frame is Ek = 6mc2 . Incidentally this tells you why…