Fundamentals of Physics, Volume 1, Chapter 1-20
10th Edition
ISBN: 9781118233764
Author: David Halliday
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 43, Problem 53P
To determine
To verify:
that neutrons in equilibrium with matter at 300 K have an average kinetic energy of about 0.04 eV.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Verify that, as stated in Module 43-1, neutrons in equilibrium with matter at room temperature, 300 K, have an average kinetic energy of about 0.04 eV.
Prove that the difference in population numbers (N₁, N₂) between two energy levels E, and E₁
is given by:
Nr-N=N*(1-exp (-hv/kT).
v=V₂ -v₁₁ is the frequency which corresponds to the energy difference between the two
levels E₂ and E₁.
d) Using the SEMF show that the neutron separation energy S, is given approximately by
1-2A + 4Z
A
2as
3A¹/3
ac Z²
+
3 A4/3
Snav
You may use the approximations Z(Z − 1) ≈ Z², A(A − 1) ≈ A² and (A − 1)" ≈ An — nA¹-1,
and ignore the pairing term.
+ as
Chapter 43 Solutions
Fundamentals of Physics, Volume 1, Chapter 1-20
Ch. 43 - Prob. 1QCh. 43 - Prob. 2QCh. 43 - Prob. 3QCh. 43 - Prob. 4QCh. 43 - Prob. 5QCh. 43 - Prob. 6QCh. 43 - Prob. 7QCh. 43 - Which of these elements is not cooked up by...Ch. 43 - Prob. 9QCh. 43 - Prob. 10Q
Ch. 43 - Prob. 11QCh. 43 - Prob. 12QCh. 43 - Prob. 1PCh. 43 - Prob. 2PCh. 43 - Prob. 3PCh. 43 - Prob. 4PCh. 43 - Prob. 5PCh. 43 - Prob. 6PCh. 43 - Prob. 7PCh. 43 - Prob. 8PCh. 43 - Prob. 9PCh. 43 - Prob. 10PCh. 43 - Prob. 11PCh. 43 - Prob. 12PCh. 43 - Prob. 13PCh. 43 - Prob. 14PCh. 43 - Prob. 15PCh. 43 - Prob. 16PCh. 43 - Prob. 17PCh. 43 - Prob. 18PCh. 43 - Prob. 19PCh. 43 - Prob. 20PCh. 43 - Prob. 21PCh. 43 - Prob. 22PCh. 43 - Prob. 23PCh. 43 - Prob. 24PCh. 43 - SSM a A neutron of mass mn and kinetic energy K...Ch. 43 - Prob. 26PCh. 43 - Prob. 27PCh. 43 - Prob. 28PCh. 43 - Prob. 29PCh. 43 - Prob. 30PCh. 43 - Prob. 31PCh. 43 - Prob. 32PCh. 43 - Prob. 33PCh. 43 - Prob. 34PCh. 43 - Prob. 35PCh. 43 - Prob. 36PCh. 43 - Prob. 37PCh. 43 - Prob. 38PCh. 43 - Prob. 39PCh. 43 - Prob. 40PCh. 43 - Prob. 41PCh. 43 - Prob. 42PCh. 43 - Prob. 43PCh. 43 - Prob. 44PCh. 43 - Prob. 45PCh. 43 - Prob. 46PCh. 43 - SSM WWW Coal burns according to the reaction...Ch. 43 - Prob. 48PCh. 43 - Prob. 49PCh. 43 - Prob. 50PCh. 43 - Prob. 51PCh. 43 - Prob. 52PCh. 43 - Prob. 53PCh. 43 - Prob. 54PCh. 43 - Prob. 55PCh. 43 - Prob. 56PCh. 43 - Prob. 57PCh. 43 - Prob. 58P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A particle of ionizing radiation creates 4,600 ion pairs in the gas inside a Geiger tube as it passes through. What minimum energy (in J) was deposited, if 21.0 eV is required to create each ion pair? If all of this energy is converted to thermal energy in the gas, what is its temperature increase (in K), assuming 55.0 cm3 of ideal gas at 0.300 atm pressure? (The small answer is consistent with the fact that the energy is large on a quantum mechanical scale but small on a macroscopic scale. Assume the initial temperature of the gas is 293 K.)arrow_forwardIn class I derived the ordinary nuclear density to be about 0.138 u/fm3. A neutron star is a collapsed star that contains neutrons in a highly compactified state, so its average density is higher. Assume a neutron star is spherical and has an average density which is about twice the ordinary nuclear density. If it is 50% heavier than the Sun, what would be its radius? (Given: mass of sun = 2*1030 kg, 1 u = 1.66*10-27 kg.) A) 14.6 km B) 11.6 km C) 10.1 km D) none of these.arrow_forwardThe cross section for neutrons of energy 10 eV being captured by silver (p = 10.5 g/cm3) is 17 barns. What is the probability of a neutron being captured as it passes through a layer of silver 2 mm thick?arrow_forward
- In a neutron-activation experiment, a flux of 108 neutrons/cm2sec is incident normally on a foil of area 1 cm?, density 1022 atoms/cm3 , and thickness 10-2 cm. The target nuclei have a total cross section for neutron capture of 1 barn (10-24 cm2), Find the number of b ( the light particle) per second ? 104 particle/sec 102 particle/sec 106 particle/sec 108 particle/sec Clear my choicearrow_forward: Evaluate the electron Debye length and number of particles for A laser fusion , electron beam fusion , with T = 1K eV , n = 1020 cm−3.arrow_forwardTable 1 lists the systematic uncertainties on a matter-antimatter asymmetry, also known as charge-paritv (CP) asvmmetrv, measured for the decay of a Dº meson into a K+K¯a+n¯ final state. Given that the CP asymmetry is defined by NA- NB A NA + NB where NA = 10974± 117 and NB = 10749±116, compute the value and uncertainty on A, writing statistical and systematic uncertainties separately. You may assume that NA and Ng are uncorrelated and that the systematic uncertainties are uncorrelated. Table 1: Systematic uncertainty contributions on A for Dº → K+K¯ata¯ data. Source of systematic uncertainty Magnitude of contribution mis-reconstructed signal shape Charged particle identification momentum (p*(D°)) cut Detector asymmetry 0.001 0.004 0.002 0.001 A. Compute the total systematic uncertainty on this asymmetry.arrow_forward
- An alpha particle with kinetic energy 11.0 Me V makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L%=pob, where po is the magnitude of the initial momentum of the alpha particle and b=1.50x10-12m (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.) Repeat for b=1. 10×10-13 m. Express your answer in meters. ΑΣφ Submit Request Answer Part C Repeat for b=1.50×10-14 m. Express your answer in meters.arrow_forwardIn a Rutherford scattering experiment, alpha particles having kinetic energy of 7.70 MeV are fired toward a gold nucleus that remains at rest during the collision. The alpha particles come as close as 29.5 fm to the gold nucleus before turning around. (a) Calculate the de Broglie wavelength for the 7.70-MeV alpha particle and compare it with the distance of closest approach, 29.5 fm. (b) Based on this comparison, why is it proper to treat the alpha particle as a particle and not as a wave in the Rutherford scattering experiment?arrow_forwardUse the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m,= 1.67493x1027 kg= 1.008665 u = 939.57 MeVIC H: my = 1.67353x10 27 kg = 1.007825 u = 938.78 MeVic 1u= 1.6605x10-27 kg = 931.5 MeVic? Consider the following decay: 211 At 207 Bi + a. 211 At has a mass of 210.9874963 u, 207 Bi has a mass of 206.981593 u, and a has a mass of 4.002603 u. 85 83 85 83 Determine the disintegration energy (Q-value) in MeV. Determine the binding energy (in MeV) for 211 At. 85 EB =arrow_forward
- In a Rutherford scattering experiment, an a - particle (charge = 12e) heads directly toward a gold nucleus (charge = +79e). The alpha - particle had a kinetic energy of 5.0 MeV when very far (r -> infinity`) from the nucleus. Assuming the gold nucleus to be fixed in space, determine the distance of closest approach. Hint: Use conservation of energy with PE = ke q1q2/r.arrow_forwardHow many scattering collisions in graphite are required to reduce the energy of 2.5 MeV neutrons to a) 0.1% of the initial energy, b) 0.025 eV?arrow_forwardAlpha particles are projected toward a gold foil from a distance that is sufficiently large to consider the Coulomb force negligible. The gold nuclei have 118 neutrons and 79 protons. If a 3.45 MeV alpha particle has a scattering angle of 180° and the gold nucleus does not recoil, determine the distance of closest approach of the alpha particle.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Classical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning