Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
9th Edition
ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 44, Problem 71AP
(a)
To determine
Find the daughter nuclide.
(b)
To determine
Find allowed level for the electron capture and electron emission in
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
When a nucleus decays, the daughter nucleus can be in an excited state. The 93/43Tc nucleus (molar mass 92.910 2 g/mol) in the ground state decays by electron capture and e+ emission to energy levels of the daughter (molar mass 92.906 8 g/mol in the ground state) at 2.44 MeV, 2.03 MeV, 1.48 MeV, and 1.35 MeV. (a) Identify the daughter nuclide. (b) To which of the listed levels of the daughter are electron capture and e+ decay of 93/43Tc allowed?
How much energy in kJ is released to form one mole of 75As from protons, electrons, and neutrons if the nucleus has a mass of 74.921594 amu? The masses of the proton, electron and neutron are 1.00728 amu, 0.000549 amu and 1.00867 amu, respectively.
-3.15e10 kJ/mol
-6.31e10 kJ/mol
-6.31e13 kJ/mol
3.15e13 kJ/mol
Plutonium-239 is used as the energy source for heart pacemakers and space probes. It decays to
uranium-235 by alpha emission. How much energy (in kilojoules) is given off by the decay? (235U =
= 239.0522 amu; He = 4.0026 amu; 1 amu = 1.661x10-24 g.)
23⁹ Pu
235.0439 amu;
94
O
-1.5 x 10-13 kJ
-1.5 x 10-10 kJ
-1.5 x 10-16 kJ
Ⓒ -1.5 x 10-15 kJ
Chapter 44 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Ch. 44.1 - Prob. 44.1QQCh. 44.5 - Prob. 44.3QQCh. 44.5 - Which of the following is the correct daughter...Ch. 44 - Prob. 1OQCh. 44 - Prob. 2OQCh. 44 - Prob. 3OQCh. 44 - Prob. 4OQCh. 44 - Prob. 5OQCh. 44 - Prob. 6OQCh. 44 - Prob. 7OQ
Ch. 44 - Prob. 8OQCh. 44 - Prob. 9OQCh. 44 - Prob. 10OQCh. 44 - Prob. 11OQCh. 44 - Prob. 12OQCh. 44 - Prob. 13OQCh. 44 - Prob. 1CQCh. 44 - Prob. 2CQCh. 44 - Prob. 3CQCh. 44 - Prob. 4CQCh. 44 - Prob. 5CQCh. 44 - Prob. 6CQCh. 44 - Prob. 7CQCh. 44 - Prob. 8CQCh. 44 - Prob. 9CQCh. 44 - Prob. 10CQCh. 44 - Prob. 11CQCh. 44 - Prob. 12CQCh. 44 - Prob. 13CQCh. 44 - Prob. 14CQCh. 44 - Prob. 15CQCh. 44 - Prob. 16CQCh. 44 - Prob. 17CQCh. 44 - Prob. 1PCh. 44 - Prob. 2PCh. 44 - Prob. 3PCh. 44 - Prob. 4PCh. 44 - Prob. 5PCh. 44 - Prob. 6PCh. 44 - Prob. 7PCh. 44 - Prob. 8PCh. 44 - Prob. 9PCh. 44 - Prob. 10PCh. 44 - Prob. 11PCh. 44 - Prob. 12PCh. 44 - Prob. 13PCh. 44 - Prob. 14PCh. 44 - Prob. 15PCh. 44 - Prob. 16PCh. 44 - Prob. 17PCh. 44 - Prob. 18PCh. 44 - Prob. 19PCh. 44 - Prob. 20PCh. 44 - Prob. 21PCh. 44 - Prob. 22PCh. 44 - Prob. 23PCh. 44 - Prob. 24PCh. 44 - Prob. 25PCh. 44 - Prob. 26PCh. 44 - Prob. 27PCh. 44 - Prob. 28PCh. 44 - Prob. 29PCh. 44 - Prob. 31PCh. 44 - Prob. 32PCh. 44 - Prob. 33PCh. 44 - Prob. 34PCh. 44 - Prob. 35PCh. 44 - Prob. 36PCh. 44 - Prob. 37PCh. 44 - Prob. 38PCh. 44 - Prob. 39PCh. 44 - Prob. 40PCh. 44 - Prob. 41PCh. 44 - Prob. 42PCh. 44 - Prob. 43PCh. 44 - Prob. 44PCh. 44 - Prob. 45PCh. 44 - Prob. 46PCh. 44 - Prob. 47PCh. 44 - Prob. 48PCh. 44 - Prob. 49PCh. 44 - Prob. 50PCh. 44 - Prob. 51PCh. 44 - Prob. 52PCh. 44 - Prob. 53PCh. 44 - Prob. 54APCh. 44 - Prob. 55APCh. 44 - Prob. 56APCh. 44 - Prob. 57APCh. 44 - Prob. 58APCh. 44 - Prob. 59APCh. 44 - Prob. 60APCh. 44 - Prob. 61APCh. 44 - Prob. 62APCh. 44 - Prob. 63APCh. 44 - Prob. 64APCh. 44 - Prob. 65APCh. 44 - Prob. 66APCh. 44 - Prob. 67APCh. 44 - Prob. 68APCh. 44 - Prob. 69APCh. 44 - Prob. 70APCh. 44 - Prob. 71APCh. 44 - Prob. 72APCh. 44 - As part of his discovery of the neutron in 1932,...Ch. 44 - Prob. 74APCh. 44 - Prob. 75APCh. 44 - Prob. 76APCh. 44 - Prob. 77CPCh. 44 - Prob. 78CP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The electrical power output of a large nuclear reactor facility is 900 MW. It has a 35.0% efficiency in converting nuclear power to electrical. (a) What is the thermal nuclear power output in megawatts? (b) How many 235U nuclei fission each second, assuming the average fission produces 200 MeV? (c) What mass of 235U is fissioned in one year of fullpower operation?arrow_forward(a) How many 239Pu nuclei must fission to produce a 20.0kT yield, assuming 200 MeV per fission? (b) What is the mass of this much 239Pu?arrow_forward(a) Write the decay equation for the decay of 235U. (b) What energy is released in this decay? The mass of the daughter nuclide is 231.036298 u. (c) Assuming the residual nucleus is formed in its ground state, how much energy goes to the particle?arrow_forward
- (a) Calculate the energy released in the a decay of 238U. (b) What fraction of the mass at a single 238U is destroyed in the decay? The mass of 234Th is 234.043593 u. (c) Although the fractional mass loss is laws for a single nucleus, it is difficult to observe for an entire macroscopic sample of uranium. Why is this?arrow_forwardTaking into account the recoil (kinetic energy) of the daughter nucleus, calculate the kinetic energy Ka of the alpha particle in 238- the following decay of a 238 U Ka = 234 4.270 Incorrect Th + a U nucleus at rest. MeVarrow_forwardThe final step of hydrogen "burning" in stars consists of combining two 3,He nuclei to form a stable 4,He nucleus plus two protons. How much energy is released in this final step? The mass energy of the 3,He nucleus (without atomic electrons) is 2809.41 MeV, the mass energy of the 4,He nucleus (without electrons) is 3728.40 MeV and the mass energy of a proton is 938.27 Mev. ,Не + 3, Не — 4, Не + р + p O 1857 MeV O 27.8 MeV O 1890 MeV O 13.9 MeV O 139 MeV O 952.2 Mev O No energy is released. O 1.39 MeVarrow_forward
- Some nucleus of ¹90X (atomic mass = 189.96182 u) undergoes - decay to become ¹9X1 (atomic mass = 189.95844 u). What is the energy (in MeV) released in this process? Number i Parent nucleus N Z+ Units Daughter nucleus N-1 Z+1+ B particle (electron) +arrow_forwardWhat is the energy of the antineutrino, if a phosphorus-32 atom ( 31.97390u) beta-decays into a sulphur-32 atom ( 31.97207u), and the kinetic energy of the accompanying electron is 0.90 Mev? Hint: difference in mass ( mass defect) is converted into the kinetic energy of the electron and the energy of the antineutrino.arrow_forwardWhen Fermium (253.085174u) decays into Californium (249.074844u), it emits an alpha particle (4.002602u). If 1 u = 931.5 MeV, what is the energy released in the decay? MeVarrow_forward
- 1.a. A 14-gram ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the radioative phosphorus-32 isotope with a half-life of 14.3 days and which decays via beta emision (RBE=1) with an energy of 1.71 MeV. Half of the sodium phosphate is absorbed by the tumor and deposits 9.0 J energy into it. The other half of the solution is absorbed throughout the patient's tissues, also depositing 9.0 J of energy into the 50.0 kg of body tissues. i. What is the dose ( in gray and rem) that the tumor receives? ii. What is the dose ( in milligray and rem) that the rest of the tissues receives? b. Photoelectrons from a material with a binding energy of 2.71 eV are ejected by 420-nm photons. Once ejected, how long does it take these electrons to travel 2.50cm to a detected device? c.The heating element in an electric kettle is rated as 2.0kW. If the waterin the kettle is at 1000.0 oC, what volume of water will be converted in to steam in…arrow_forwardWhat minimum energy E(min) is needed to remove a neutron from K40 and so convert it to K39? The atomic masses of the two isotopes are 39.964000 and 38.963708 u, respectively. E(min) = ? eVarrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax