Concept explainers
(a)
The energy released when one atom of uranium undergoes the fission reaction,
(a)
Answer to Problem 23SP
Solution:
Explanation of Solution
Given data:
The
The atomic mass of uranium is
The atomic mass of barium is
The atomic mass of niobium is
The atomic mass of electron is
Formula used:
The expression for the mass loss is written as,
The expression for the energy released is written as,
Here,
Explanation:
Write the given reaction in the question.
Write the expression for the reactant mass.
Here,
Substitute
Write the expression for the product mass.
Here,
Substitute
Recall the expression for the mass loss.
Substitute
Recall the expression for the energy released.
Substitute
Conclusion:
Hence, the energy released when one atom of uranium undergoes the fission reaction is
(b)
The energy released when
(b)
Answer to Problem 23SP
Solution:
Explanation of Solution
Given data:
The atomic mass of neutron is
The atomic mass of uranium is
The atomic mass of barium is
The atomic mass of niobium is
The atomic mass of electron is
Formula used:
Molar mass of
The number of atoms in
Explanation:
Calculate the number of atoms present in
Substitute
Thus, there are
Write the expression for the energy released in
Substitute
Conclusion:
Hence, the energy released when
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Chapter 46 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
- (a) Calculate the energy released in the neutron- Induced fission reaction n+235U92Kr+142Ba+2n , given m(92Kr) = 91.926269 u and m(142Ba)= 141.916361 u. (b) Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forward(a) Calculate the energy released in the neutroninduced fission reaction n+239Pu96Sr+140Ba+4n, given m(96Sr)=95.921750u and m(140Ba)=139.910581u. (b) Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forward(a) Calculate the energy released in the neutron- induced fission n+238U96Sr+140Xe+3n , given m(96Sr)=95.921750uand m(140Xe)=139.92164 . This result is about 6 MeV greater than the result for spontaneous fission. Why? Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forward
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