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In a diploid plant species, an
a. What is the order of these three linked genes?
b. Calculate the recombination fractions between eachpair of genes.
c. Why is the recombination fraction for the outside pair of genes not equal to the sum of recombination fractions between the adjacent gene pairs?
d. What is the interference value for this data set?
e. Explain the meaning of this
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Chapter 5 Solutions
GENETIC ANALYSIS: AN INTEG. APP. W/MAS
- In a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. What is the gene order of these linked genes?arrow_forwardIn this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…arrow_forwardFor each genotype, indicate whether it is heterozygous (HE) or homozygous (HO) AA Bb Cc Dd Ee ff GG HH PP Pp pp Round seeds are dominant to wrinkled RR Rr rr Ii Jj kk For each of the genotypes below, determine the phenotype. Purple flowers are dominan to white flowers L1 Mm nn straight straight curly 00 Pp Brown eyes are domin BB Bb bb to blue eyes Bobtails are recessive (long tails dominant) TT Tt tt For each phenotype, list the genotypes. (Remember to use the letter of the dominant trait) Straight hair is dominant to curly. Pointed heads are dominant to round heads. pointed pointed roundarrow_forward
- Here are the progeny of this cross: (Note that the categories are not in any particular order.)Fly type # of prog. Phenotype symbols Categorywt eyes black body wt wings 97 grn+ blk crv+Green eyes black body curved wings 709 ParentalGreen eyes wt body wt wings 9Green eyes black body wt wings 162wt eyes wt body wt wings 727wt eyes black body curved wings 12wt eyes wt body curved wings 179Green eyes wt body curved wings 105Total = 2000 9.) Write the phenotype symbols in the right-hand column. The first one has been done for you.10.) Next to that, label all fly categories as parental (NCOs), SCOs, and DCOs. One has been donefor you.11.) After each SCO/DCO label, write which gene got “unlinked” in these offspring.12.) Put these three genes into a genetic map in the proper order.13.) Calculate the genetic distance between the genes and label the map with these distances.14.) Calculate the cross-over interference15.) Return to questions #1-6 above. For question 6, you gave your opinion, but…arrow_forwardAn individual heterozygous for d e f (D/d E/e F/f) was crossed to a homozygous recessive individual (d/d e/e f/f). The following offspring were recovered.d e + 39+ e f 372d + f 7+ + f 47+ e + 5d + + 412What is the correct order of these genes? EDF DFE DEFarrow_forwardThe trihybrid e+f+g+/efg is test crossed to the triple recessive efg/efg and the following genotypes were obtained in the progeny: efg = 2; efg = 28; e'fg* = 9; e*rg 32; efg 73; e*fg* = 10; ef g* =10; e'fg 2; %3D "The odd gene is The gene order is The gene distance between e-f is The gene distance between f-g is The gene distance between e-g isarrow_forward
- three recessive genes a, b, and c in the model plant Arabidopsis are found to be linked on chromosome 4. A three point test cross is done with a homozygous recessive plant with a heterozygous for all three genes. Following is the number of progenies a b C 65 A B c 56 A B C 1267 a b c 1310 A b C 550 a B c 515 a B C 470 A b c 489 Total = 4,722 Determine the middle locus by your choice of method and after that calculate the map distance between the genes in map unit (m.u.).arrow_forwardWhich of the pedigree diagrams below is most likely to show a family with X-linked agammaglobulinemia? A KEY. C Horygon Hamocyga Hezexygess Hey Wild Type fursale Mek Parmak Mais Note: Completely red symbol denotes an individual exhibiting the phenotype of interest H INV V 1/4 1/2 1/2 1.0. 1/2 1/2 1/4 Typ female 1/2 B Affected Known carrier Normal Moral D O Toarrow_forwardAn individual is heterozygous for a reciprocal translocation, with the following chromosomes: A • B C D E F A • B C V W X R ST • U D E F R ST • U V W X Q. Explain why the fertility of this individual is likely to be less than the fertility of an individual without a translocation.arrow_forward
- In a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. What is the interference value for this data set?arrow_forwardA cross between the F1 individual in Figure 21.6 and a plant with genotype B-I B-I will produce progeny with what phenotype?arrow_forwardThe result of a test cross of a yeast cell that is heterozygous for three genes are summarized in the table (below), which shows the number of offspring that inherited each combination of alleles from the heterozygous parent. Use the data collected to make a genetic map of the three genes L, Q, and D. • D-Q: o D-L: | o Q-L: | - L L I L L cM CM Alleles CM Ơ Ơ o Q o d D D d d d # 104 27 78 Report your results by entering the genetic distance between each pair of genes in the blanks below. Round to the nearest 0.1 cm. 64 28 62 106 81arrow_forward
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