GENETIC ANALYSIS: AN INTEG. APP. W/MAS
GENETIC ANALYSIS: AN INTEG. APP. W/MAS
2nd Edition
ISBN: 9781323142790
Author: Sanders
Publisher: Pearson Custom Publishing
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Chapter 5, Problem 15P

Three dominant traits of corn seedlings, tunicate seed( T– ), glossy appearance ( G– ), and liguled stem ( L– ), arestudied along with their recessive counterparts, nontunicate ( tt ), nonglossy ( gg ), and liguleless( ll ). A trihybrid plantwith the three dominant traits is crossed to a nontunicate, nonglossy, liguleless plant. Kernels on ears of progenyplants are scored for the traits, with the following results:

P h e n o t y p e N u m b e r T u n i c a t e , g l o s s y , l i g u l e d 102 T u n i c a t e , g l o s s y , l i g u l e l e s s 106 T u n i c a t e , n o n g l o s s y , l i g u l e d 18 T u n i c a t e , n o n g l o s s y , l i g u l e l e s s 20 N o n t u n i c a t e , g l o s s y , l i g u l e d 22 N o n t u n i c a t e , g l o s s y , l i g u l e l e s s 23 N o n t u n i c a t e , n o n g l o s s y , l i g u l e d 99 N o n t u n i c a t e , n o n g l o s s y , l i g u l e l e s s 110 500

a. Is there evidence of genetic linkage among any of thesegene pairs? If so, identify the evidence.

b. Is there evidence of independent assortment among any of these gene pairs? If so, identify the evidence.

c. Using the gene symbols given above, write the genotypes of F1 and F2 plants.

d. If evidence of linkage is present, calculate the recombination fraction(s) from the data presented.

e. Could all three genes be carried on the same chromosome? Discuss why or why not.

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Height of the plant  if a homozygous tall pea plant is crossed with a homozygous short pea plant, what are the possible genotype and phenotypes of the offspring?  Legend:  T- tall pea plant  t- short pea plant  Genotypes of the parents TT x tt Question  1. what is the genotypic ratio 2. what are the possible phenotypes of the offspring? 3. What is the phenotypic ratio? 4. what is the probability of having a short trait?
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. In nature, the plant Plectritis congesta is dimorphic forfruit shape; that is, individual plants bear either winglessor winged fruits, as shown in the illustration.Wingless fruit Winged fruitPlants were collected from nature before floweringand were crossed or selfed with the following results:Number of progenyPollination Winged WinglessWinged (selfed) 91 1*Winged (selfed) 90 30Wingless (selfed) 4* 80Winged × wingless 161 0Winged × wingless 29 31Winged × wingless 46 0Winged × winged 44 0*Phenotype probably has a nongenetic explanation.Interpret these results, and derive the mode ofinheritance of these fruit-shaped phenotypes. Usesymbols. What do you think is the nongeneticexplanation for the phenotypes marked by asterisks inthe table?

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GENETIC ANALYSIS: AN INTEG. APP. W/MAS

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