Concept explainers
(a)
Interpretation:
To use the
Concept introduction:
The ideal gas law states the relationship between the pressure, volume, number of moles and temperature of gas at ideal conditions and it is calculated using the following formula:
Here P is the pressure of the system, V is the volume, n is the number of moles, R is the universal gas constant and T is the temperature.
Mole is a ratio between mass and molar mass. It can be calculated as follows:
Answer to Problem 20QAP
The bank columns in each row are filled in bold. The completed table is as follows:
Sub part | Pressure | Volume | Temperature | Moles | Grams |
a | 18.9psi | 0.886L | 220C | 0.047 | 2.1 |
Explanation of Solution
As per the given table we have to find the moles and grams of propane gas. First let us calculate the molar mass of
We have to convert psi into atm using the following formula:
Let us use the ideal gas equation to calculate the number of moles of
Now let us substitute these values in number of moles formula to find the mass in grams:
(b)
Interpretation:
To use the ideal
Concept introduction:
The ideal gas law states the relationship between the pressure, volume, number of moles and temperature of gas at ideal conditions and it is calculated using the following formula:
Here P is the pressure of the system, V is the volume, n is the number of moles, R is the universal gas constant and T is the temperature. We know that mole is a ratio between mass and molar mass therefore let us substitute this in the ideal gas equation to obtain density:
Mole is a ratio between mass and molar mass. It can be calculated as follows:
Answer to Problem 20QAP
The bank columns in each row are filled in bold. The completed table is as follows:
Sub part | Pressure | Volume | Temperature | Moles | Grams |
b | 633mm Hg | 1.993L | -330C | 0.0844 | 3.72 |
Explanation of Solution
As per the given table, we have to find the temperature and grams of propane gas. In sub part a, we have found that the MM is 44g/mol and as given, the number of moles is 0.0844mol therefore let us substitute these values in number of moles formula:
Now we must convert mmHg into atm using the following formula:
Let us use the ideal gas equation to calculate the temperature of
(c)
Interpretation:
To use the ideal gas law to complete the blank columns of the given table for propane gas.
Concept introduction:
The ideal gas law states the relationship between the pressure, volume, number of moles and temperature of gas at ideal conditions and it is calculated using the following formula:
Here P is the pressure of the system, V is the volume, n is the number of moles, R is the universal gas constant and T is the temperature. We know that mole is a ratio between mass and molar mass therefore let us substitute this in the ideal gas equation to obtain density:
Mole is a ratio between mass and molar mass. It can be calculated as follows:
Answer to Problem 20QAP
The bank columns in each row are filled in bold. The completed table is as follows:
Sub part | Pressure | Volume | Temperature | Moles | Grams |
c | 1.876atm | 47.3 L | 750C | 2.842 mol | 125.04 g |
Explanation of Solution
As per the given table, we have to find the volume and grams of propane gas. First we have to convert 0F into K using the following formula:
Let us use the ideal gas equation to calculate the volume of
Now let us substitute these values in number of moles formula to find the mass in grams:
(d)
Interpretation:
To use the ideal gas law to complete the blank columns of the given table for propane gas.
Concept introduction:
The ideal gas law states the relationship between the pressure, volume, number of moles and temperature of gas at ideal conditions and it is calculated using the following formula:
Here P is the pressure of the system, V is the volume, n is the number of moles, R is the universal gas constant and T is the temperature. We know that mole is a ratio between mass and molar mass therefore let us substitute this in the ideal gas equation to obtain density:
Mole is a ratio between mass and molar mass. It can be calculated as follows:
Answer to Problem 20QAP
The bank columns in each row are filled in bold. The completed table is as follows:
Sub part | Pressure | Volume | Temperature | Moles | Grams |
d | 11.2atm | 2244mL | 130C | 1.07 | 47.25 |
Explanation of Solution
The pressure and moles of propane gas needs to be calculated. As per the given information substitute 47.25 g/mol for mass and 44 g/mol for MM in the number of moles formula:
Let us use the ideal gas equation to calculate the pressure of
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Chapter 5 Solutions
EBK CHEMISTRY: PRINCIPLES AND REACTIONS
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