Concept explainers
Interpretation:
The structural formulas for all the stereoisomers of
Concept introduction:
The moleculesthat are nonsuperimposable or not identical with their mirror images are known as chiral molecules.
A pair of two mirror images that are nonidentical is known as enantiomers, which are optically active.
The objects or moleculesthat are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.
The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds, but they are optically inactive.
The stereoisomers that are nonsuperimposable on each other and not mirror images of each other are known as diastereomers.
Stereoisomers that are mirror images of each other are enantiomers.
Achiral molecules that contains chiral centres and have a plane of symmetry are called meso compounds.
Meso compounds are optically inactive.
In double bond or cyclic compounds, if two same
If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.
Cis-trans isomerism exists in the compounds in which similar groups are present on the adjacent carbon atoms.
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ORGANIC CHEM LL W/WILEYPLUS BLCKBRD >I
- 5.76 2,3-Dibromoprop-1-ene (C3H4Br₂) has four H atoms. Suppose that any of these H atoms can be replaced by a Cl atom to yield a molecule with the formula C3H3Br₂Cl. (a) Identify two H atoms where this substitution would yield constitutional isomers of C3H3Br₂Cl; (b) enantiomers of C3H3Br₂Cl; (c) diastereomers of C3H3Br₂Cl. co 11 HHH Juods H Brugtrio 2 bas A 2,3-Dil so ontemme A chon Br 2,3-Dibromoprop-1-enearrow_forwardConsider 1-bromopropane, CH3CH2CH2Br. (a) Draw a Newman projection for the conformation in which CH3 and -Br are anti (dihedral angle 180°). (b) Draw Newman projections for the conformations in which - CH3 and -Br are gauche (dihedral angles 60° and 300°). (c) Which of these is the lowest energy conformation? (d) Which of these conformations, if any, are related by reflection?arrow_forwardConsider 1-bromo-2-methylpropane and draw the following. Q) The staggered conformation(s) of highest energyarrow_forward
- Compound X, C,4H12Br2, is optically inactive. On treatment with strong base, X gives hydrocarbon Y, C14H10: Compound Y absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst to give z (C14H14) and reacts with ozone to give one product, benzoic acid (C,Hg02). Draw the structure of compound Z. • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • Ignore alkene stereochemistry. • If more than one structure fits the description, draw them all. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate structures with + signs from the drop-down menu. ChemDoodlearrow_forward(a) which if the structure of trans-1,2-dimethylcyclopentane? (b) which is the most stable conformation of 1-bromo-2-ethylcyclohexane? (c) which is the least stable conformation of 1-bromo-2-ethylcyclohexane? (d) which is the more stable configuration of 1,3-dimethylcyclopentane? *Et = ethylarrow_forward(a) Arrange the following compounds in order of increasing melting point. Explain your answersfrom the aspect of compactness and rigidity.arrow_forward
- Consider 1-bromo-2-methylpropane and draw the following. (a) The staggered conformation(s) of lowest energy (b) The staggered conformation(s) of highest energyarrow_forwardFollowing is a planar hexagon representation of L-fucose, a sugar component of the determinants of the A, B, O blood group typing. For more on this system of blood typing, see Chemical Connections: A, B, AB, and O Blood Group Substances in Chapter 25. (a) Draw the alternative chair conformations of L-fucose. (b) Which of them is more stable? Explain.arrow_forwardWrite the two chair conformations of each of the following and in each part designate whichconformation would be the more stable: (a) cis-1-tert-butyl-3-methylcyclohexane, (b) trans-1-tert-butyl-3-methylcyclohexane, (c) trans-1-tert-butyl-4-methylcyclohexane, ( d) cis-1-tert-butyl-4-methylcyclohexane.arrow_forward
- Using what you know about the conformational energetics of substituted cyclohexanes, predict which of the two decalin isomers is more stable. Explain your reasoning.arrow_forwardjust problem 5.23 pleasearrow_forwardRefer the structure below: CH3 CH3 CH3 CH3 Compound I Compound II (i) Are the above cyclohexane derivatives cis- or trans-isomer? (ii) Redraw the structure in chair conformation and identity which of these the most and the least stable.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning