(a)
To show: that the point P is on the unit circle.
(a)
Answer to Problem 2RE
The point P lies the unit circle.
Explanation of Solution
Given:
Concept used:
The Equation of unit circle:
Calculation:
Here the point
Using Equation of unit circle:
Taking L.H.S
Hence, L.H.S is equal to R.H.S
Therefore, the point P lies the unit circle.
(b)
To find:The
(b)
Answer to Problem 2RE
Explanation of Solution
Given:
Concept used:
By Pythagoras theorem:
Trigonometric ratio:
Calculation:
The point
By Pythagoras theorem:
Here
Chapter 5 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning