Chapter 5, Problem 5.19NP

(a)

Interpretation Introduction

Interpretation:

At the transition temperature of 95.4⁰C, the enthalpy of transition from rhombic to monoclinic sulfur is 0.38 kJ mol-1. The entropy of transition under these conditions, needs to be calculated.

Concept Introduction :

The entropy of transition is defined as below:

  $\Delta S_{Transition}=\frac{\Delta H_{Transition}}{T_{transition}}\mathrm{.......}(1)$

Here,

  $\Delta S_{Transition}$ =entropy of transition

  $\Delta H_{Transition}$ = enthalpy of transition, 0.38 X 10³ J. mol-1

  $T_{transition}$ = transition temperature

(b)

Interpretation Introduction

Interpretation:

At its melting point, 119⁰C, the enthalpy of fusion of monoclinic sulfur is 1.23 KJ mol-1. The enthalpy of fusion needs to be calculated.

Concept Introduction :

The entropy of transition is defined as below:

  $\Delta S_{Transition}=\frac{\Delta H_{Transition}}{T_{transition}}\mathrm{.......}(1)$

Here,

  $\Delta S_{Transition}$ =entropy of transition

  $\Delta H_{Transition}$ = enthalpy of transition, 0.38 X 10³ J. mol-1

  $T_{transition}$ = transition temperature

(c)

Interpretation Introduction

Interpretation:

The values of the enthalpy and entropy of fusion in parts (a) and (b) to those appropriate for S₈ needs to be converted.

Concept Introduction :

The entropy of transition is defined as below:

  $\Delta S_{Transition}=\frac{\Delta H_{Transition}}{T_{transition}}\mathrm{.......}(1)$

Here,

  $\Delta S_{Transition}$ =entropy of transition

  $\Delta H_{Transition}$ = enthalpy of transition, 0.38 X 10³ J. mol-1

  $T_{transition}$ = transition temperature