Concept explainers
a.
Find the
a.
Answer to Problem 60CE
The sample space is,
Explanation of Solution
The given information is that the M&Ms were blended in the ratio of 13% brown, 14% yellow, 13% red, 24% blue, 20% orange and 16% green. Also, the selected random sample of M&M blended in the large bag is 2.
Sample space:
The set of all possible outcomes of the random experiment is said to be sample space of and it is denoted by S.
Consider, B represents brown, Y represents yellow, R represents red, BL represents blue, O represent orange and G represents green.
The all possible outcomes of the random experiment of any two of brown, yellow, red, blue, orange and green M&Ms is as follows.
b.
Find the probability that both are brown.
b.
Answer to Problem 60CE
The probability that both are brown is 0.0169.
Explanation of Solution
Calculation:
From the given information, it can be observed that the probability of brown M&M is 0.13
The probability that both are brown is obtained as follows:
Thus, the probability that both are brown is 0.0169.
c.
Find the probability that both are blue.
c.
Answer to Problem 60CE
The probability that both are blue is 0.0576.
Explanation of Solution
Calculation:
From the given information, it can be observed that the probability of blue M&M is 0.24
The probability that both are blue is obtained as follows:
Thus, the probability that both are blue is 0.0576.
d.
Find the probability that both are green.
d.
Answer to Problem 60CE
The probability that both are green is 0.0256.
Explanation of Solution
Calculation:
From the given information, it can be observed that the probability of green M&M is 0.16
The probability that both are green is obtained as follows:
Thus, the probability that both are green is 0.0256.
e.
Find the probability of one brown and one green M&M.
e.
Answer to Problem 60CE
The probability of one brown and one green M&M is 0.0208.
Explanation of Solution
Calculation:
The probability of one brown and one green M&M is obtained as follows:
Thus, the probability of one brown and one green M&M is 0.0208.
f.
Take 100 samples of two M&Ms (with replacement). Record the frequencies of each outcome listed in (b) and (c) and how close the empirical results come to the people prediction.
f.
Explanation of Solution
Calculation:
Answers may vary. One of the possible answers is as follows:
All 100 samples of two M&Ms (with replacement) is,
The number of frequencies for both are brown is 7 and the number of frequencies for both are blue is 9 and a total number frequency is 100.
For (b) probability that both are brown:
The probability that both are brown is obtained as follows:
Thus, the probability that both are brown is 0.07.
For (c) probability that both are blue:
The probability that both are blue is obtained as follows:
Thus, the probability that both are blue is 0.09.
From part (b) and (c), the probability that both are brown is 0.0169 and the probability that both are blue is 0.0576.
From the results, it is observed that the empirical results are greater than the results of part (b) and (c). That is,
g.
Identify which definition of probability applies in the given situation.
g.
Answer to Problem 60CE
The definition of probability applies in the given situation is empirical.
Explanation of Solution
Classical Probability:
If each outcome in a sample space is equally likely to occur then it is said to be classical probability.
Empirical Probability:
The observations which are found from probability experiment is termed as empirical probability.
Subjective Probability:
If the probabilities result from intuition, educated guesses and estimates, then the probability is said to be subjective probability.
Here, the situation is most likely based on an experiment. That is, the number of each outcome is noted and the corresponding probabilities are obtained.
Thus, the definition of probability applied in the given situation is empirical.
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