Connect 1-semester Access Card For Shigley's Mechanical Engineering Design
10th Edition
ISBN: 9780077591632
Author: Richard G Budynas; Keith J Nisbett
Publisher: McGraw-Hill Education
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Chapter 5, Problem 85P
A cylinder subjected to internal pressure pi has an outer diameter of 14 in and a 1-in wall thickness. For the cylinder material, KIC= 72 kpsi ·
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What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 5.5 × 10-4 mm (2.165 × 10-5 in.) and a crack length of 3 × 10-2 mm (1.181 × 10-3 in.) when a tensile stress of 180 MPa (26110 psi) is applied?
A cylinder subjected to an internal pressure pi = 30 MPa has an outer diameter of 500 mm and a 25-mm wall thickness. For the cylinder material, KIC = 85 MPa.m0.5 , Sy = 700 MPa, and Sut = 850 MPa. If the cylinder contains a central crack in the longitudinal direction with a length of 20 mm, determine the factor safety against crack growth. Assume β = 1.
Select one:
a. NFM = 0.595
b. NFM = 1.273
c. NFM = 0.841
d. NFM = 0.900
What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 2.5 10^-4 mm (10^-5 in.) and a crack length of 2.5 10^-2 mm (10^-3 in.) when a tensile stress of 170 MPa (25,000 psi) is applied?
Chapter 5 Solutions
Connect 1-semester Access Card For Shigley's Mechanical Engineering Design
Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - Prob. 6PCh. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...
Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - A ductile material has the properties Syt = 60...Ch. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - A brittle material has the properties Sut = 30...Ch. 5 - Repeat Prob. 519 by first plotting the failure...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - Prob. 23PCh. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - 5-21 to 5-25 For an ASTM 30 cast iron, (a) find...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - This problem illustrates that the factor of safety...Ch. 5 - For the beam in Prob. 344, p. 147, determine the...Ch. 5 - A 1020 CD steel shaft is to transmit 20 hp while...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 42PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Prob. 45PCh. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 47PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Build upon the results of Probs. 384 and 387 to...Ch. 5 - Using F = 416 lbf, design the lever arm CD of Fig....Ch. 5 - A spherical pressure vessel is formed of 16-gauge...Ch. 5 - This problem illustrates that the strength of a...Ch. 5 - Prob. 60PCh. 5 - A cold-drawn AISI 1015 steel tube is 300 mm OD by...Ch. 5 - Prob. 62PCh. 5 - The figure shows a shaft mounted in bearings at A...Ch. 5 - By modern standards, the shaft design of Prob. 563...Ch. 5 - Build upon the results of Prob. 340, p. 146, to...Ch. 5 - For the clevis pin of Prob. 340, p. 146, redesign...Ch. 5 - A split-ring clamp-type shaft collar is shown in...Ch. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Two steel tubes have the specifications: Inner...Ch. 5 - Repeal Prob. 5-71 for maximum shrink-fit...Ch. 5 - Prob. 73PCh. 5 - Two steel lubes are shrink-filled together where...Ch. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 81PCh. 5 - For Eqs. (5-36) show that the principal stresses...Ch. 5 - Prob. 83PCh. 5 - A plate 100 mm wide, 200 mm long, and 12 mm thick...Ch. 5 - A cylinder subjected to internal pressure pi has...
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- A cylindrical steel pressure vessel D-575 mm in diameter with a wall thickness of 5 mm is subjected to an internal pressure of 3 MN/m². Calculatea- the tangential and longitudinal stresses in the steel.b- To what value may the internal pressure be increased if the stress in the steel is limited to 80 MN/ m²?c-If the internal pressure were increased until the vessel burst, sketch the type of fracture that would occurarrow_forwardThe fuselage of an airliner can be considered as a thin-walled tubeinternally pressurized with a diameter of 7 m and a thickness of 3 mm. It is made withAluminum sheets with K ic fracture toughness of 100 MPa m1/2. At cruising altitudeinternal pressure gauge shows 0.0.Mn/m2.. In a horizontal row rivets have beencaused many fatigue cracks and have joined together to form a longitudinal crack thatit goes through the thickness of the fuselage. Estimate the critical length for this crack to propagate,causing the fuselage to break. (The pressure in a tube is resolved into a tension in the wallfrom ? = p r / t, where p = pressure, r = radius, t = thicknessarrow_forwardBy what factor (e.g., 3X) has the remote stress been amplified at the crack tip/ Given Radius of curvature = 1.9 x 10-4 mm Crack length = 3.8 x 10-2 mm Tensile stress = 140 Mpa Maximum stress = 2800 Mpaarrow_forward
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