Connect 1-semester Access Card For Shigley's Mechanical Engineering Design
10th Edition
ISBN: 9780077591632
Author: Richard G Budynas; Keith J Nisbett
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 5, Problem 27P
5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut = 36 kpsi, Suc = 35 kpsi, and εf = 0.045. For the given state of plane stress, (a) using the Coulomb-Mohr theory, determine the factor of safely. (b) plot the failure locus and the load line, and estimate the factor of safety by graphical measurement.
Problem Number | σx (kpsi) | σy (kpsi) | τxy (kpSi) |
5–26 | 15 | −10 | 0 |
5–27 | −15 | 10 | 0 |
5–28 | 12 | 0 | −8 |
5–29 | −10 | −15 | 10 |
5–30 | 15 | 8 | −8 |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The rotating shaft running at n = 900 rpm, shown in the figure below, is machined from AISI 1045 CD steel. It is subjected to a force of F = 10.1 kN. The shaft is experiencing an operating temperature of 35 oC. With the specified loading and for the reliability of 99.9 %,
Determine the minimum factor of safety for fatigue based on infinite life*.
Determine the maximum safe load (Fmax) that can be applied for a factor of safety of 1.5 and a design life of 5x105 cycles, all other input values remaining the same.
Determine the factor of safety against yielding.
A rotating shaft of 25-mm diameter is simply supported by bearing reaction forces R1 and R2. The shaft is loaded with a transverse load of 13 kN as shown in the figure. The shaft is made from AISI 1045 hot-rolled steel. The surface has been machined. Determine
a) The minimum static factor of safety based on yielding
b) the endurance limit adjusted as necessary with Marin factors
c) the minimum fatigue factor of safety based on achieving infinite life
d) if the fatigue factor of safety is less than 1, then estimate the life of the part in number of rotations
A bracket is under a loading condition shown below. It's made from a steel with yield strength (Sy) of 42 ksi and ultimate tensile strength (Sut) of 76 ksi. The diameter is 0.42 in and b = 1.75 in, with the load P fluctuate between 15 lbs (tension) and -5 lbs (compression).
Using the modified Goodman or Gerber criterion, determine the fatigue factor of safety based on infinite life. If infinite life is not predicted, estimate the number of cycles to failure. Also check for yielding.
Chapter 5 Solutions
Connect 1-semester Access Card For Shigley's Mechanical Engineering Design
Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - Prob. 6PCh. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...
Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - A ductile material has the properties Syt = 60...Ch. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - A brittle material has the properties Sut = 30...Ch. 5 - Repeat Prob. 519 by first plotting the failure...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - Prob. 23PCh. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - 5-21 to 5-25 For an ASTM 30 cast iron, (a) find...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - This problem illustrates that the factor of safety...Ch. 5 - For the beam in Prob. 344, p. 147, determine the...Ch. 5 - A 1020 CD steel shaft is to transmit 20 hp while...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 42PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Prob. 45PCh. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 47PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Build upon the results of Probs. 384 and 387 to...Ch. 5 - Using F = 416 lbf, design the lever arm CD of Fig....Ch. 5 - A spherical pressure vessel is formed of 16-gauge...Ch. 5 - This problem illustrates that the strength of a...Ch. 5 - Prob. 60PCh. 5 - A cold-drawn AISI 1015 steel tube is 300 mm OD by...Ch. 5 - Prob. 62PCh. 5 - The figure shows a shaft mounted in bearings at A...Ch. 5 - By modern standards, the shaft design of Prob. 563...Ch. 5 - Build upon the results of Prob. 340, p. 146, to...Ch. 5 - For the clevis pin of Prob. 340, p. 146, redesign...Ch. 5 - A split-ring clamp-type shaft collar is shown in...Ch. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Two steel tubes have the specifications: Inner...Ch. 5 - Repeal Prob. 5-71 for maximum shrink-fit...Ch. 5 - Prob. 73PCh. 5 - Two steel lubes are shrink-filled together where...Ch. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 81PCh. 5 - For Eqs. (5-36) show that the principal stresses...Ch. 5 - Prob. 83PCh. 5 - A plate 100 mm wide, 200 mm long, and 12 mm thick...Ch. 5 - A cylinder subjected to internal pressure pi has...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Three round, copper alloy bars having the same length L but different shapes are shown, in the figure. The first bar has a diameter d over its entire length, the second has a diameter d over one-fifth of its length, and the third has a diameter d over one-fifteenth of its length. Elsewhere, the second and third bars have a diameter Id. All three bars are subjected to the same axial load P. Use the following numerical data: P = 1400 kN, L = 5m,d= 80 mm, E= 110 GPa. and v = 0.33. (a) Find the change in length of each bar. (b) Find the change in volume of each bar.arrow_forwardA crank arm consists of a solid segment of length bxand diameter rf, a segment of length bltand a segment of length byas shown in the figure. Two loads P act as shown: one parallel to — vand another parallel to —y. Each load P equals 1.2 kN. The crankshaft dimensions are A] = 75 mm, fr> = 125 mm, and b3= 35 mm. The diameter of the upper shaft isd = 22 mm, (a) Determine the maximum tensile, compressive, and shear stresses at point A, which is located on the surface of the shaft at the z axis. (b) Determine the maximum tensile, compressive, and shear stresses at point B, which is located on the surface of the shaft at the y axisarrow_forwardSolve the preceding problem if the internal pressure is 3,85 MPa, the diameter is 20 m, the yield stress is 590 MPa, and the factor of safety is 3.0. (a) Determine the required thickness to the nearest millimeter. (b) If the tank wall thickness is 85 mm, what is the maximum permissible internal pressure?arrow_forward
- Solve the preceding problem if the thickness of the steel plate is. t = 12 mm. the gage readings are x = 530 × 10-6 (elongation) and y = -210 -× l0-6 (shortening), the modulus is E = 200 GPa, and Poisson’s ratio is v = 0.30.arrow_forwardThe hollow drill pipe for an oil well (sec figure) is 6,2 in. in outer diameter and 0.75 in. in thickness. Just above the bit, the compressive force in the pipe (due to the weight of the pipe) is 62 kips and the torque (due to drilling) is 185 kip-in. Determine the maximum tensile, compressive, and shear stresses in the drill pipe.arrow_forwardAn ASTM cast iron, grade 30, has ultimate strength at tension Sut = 406 MPa, and at compression Suc = 996 MPa. it carries static loading resulting in the following principle stress σA = 138 MPa , σB = -241 MPa. Choose the appropriate failure theory and estimate the factor of safety.arrow_forward
- The cold-drawn AISI 1040 Q&T at 205 ◦C steel bar shown in the figure is subjected to a completely reversed axial load fluctuating between 28 kN in compression to 28 kN in tension. Estimate the fatigue factor of safety based on achieving infinite life, and the yielding factor of safety for the following cases. If infinite life is not predicted, estimate the number of cycles to failure.a) for the part given in Fig 2(a) and b) for the part given in Fig. 2 (b) using the same dimensions (W=25mm, r=3mm, the thickness of 10 mm)arrow_forwardA screw clamp shown in the figure has a handle with diameter 5 mm made of cold-drawn AISI 1006 steel (table E18 - page 1195). The overall length of the hand is 75 mm. The screw is M 12 coarse (table 8-1) and is 145 mm long, overall. Distance A is 50 mm. The clamp will accommodate parts up to 105 mm high.a) What is the value of screw torque that causes the handle to bend permanently?b) If the collar friction is neglected and if the thread friction is 0.075, what is the screw force value that causes the handle to bend permanently?c) What is the value of clamping force, which will cause the screw to buckle?d) Are there any other stresses or possible failures to be checked?e) If yes, calculate them.arrow_forwardIn the figure below the clamping force on the pipe is (331.7 lb), knowing that a single threaded screw Acme with major diameter (1 in) is used with coefficient of friction (0.2135). If booth screw and nut are made from 1030 - hot rolled Carbon Steel. Determine: 1- The tightening and loosening torques. 2- Thread screw and nut shear safety factors in case of double threads are in engagement. 3.3 in 2 7.2 in 32 3 in hingearrow_forward
- answer this ; The factors of safety predicted at point H by the maximum shear stress theory of failure (Tresca criterion)arrow_forwardThe stresses on the surface of a hard bronze component are shown in the figure below. The yield strength of the bronze is σY = 345 MPa.a) What is the factor of safety predicted by the maximum-shear-stress theory of failure for the stress state shown? Does the component fail according to this theory?b) What is the value of the Mises equivalent stress for the given state of plane stress?c) What is the factor of safety predicted by the failure criterion of the maximum-distortion energy theory of failure? Does the component fail according to this theory?arrow_forward4. The compression load of 120 kN acts on the steel pipe of Table B-14. Determine the minimum Nominal dimeter pipe when the safety factor is 1.5 with a yield strength of 240MPa.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Everything About COMBINED LOADING in 10 Minutes! Mechanics of Materials; Author: Less Boring Lectures;https://www.youtube.com/watch?v=N-PlI900hSg;License: Standard youtube license