Precalculus with Limits: A Graphing Approach
Precalculus with Limits: A Graphing Approach
7th Edition
ISBN: 9781305071711
Author: Ron Larson
Publisher: Brooks/Cole
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Chapter 5.3, Problem 86E
To determine

To solve: The given equation using inverse trigonometric functions.

Expert Solution & Answer
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Answer to Problem 86E

The solutions of the equation are:

  x=π6+2nπx=5π6+2nπ

Explanation of Solution

Given information:

The following equation:

  2cos2x+7sinx=5

Formula used:

The following identity:

  sin2x+cos2x=1

Calculation:

The equation is solved as follows:

  2cos2x+7sinx=52cos2x+7sinx5=0             [Subtract 5 from both sides]2(1sin2x)+7sinx5=0      [Pythagorean identity]22sin2x+7sinx5=0        [Multiply]    2sin2x+7sinx3=0           [Combine like terms]2sin2x7sinx+3=0             [Reverse signs to make first term positive](sinx3)(2sinx1)                [Factor]

Setting each factor equal to zero, solutions obtained in the interval [0,2π) are:

  sinx3=0sinx=3                 [Adding 3 to both sides]No solution

and

  2sinx1=02sinx=1            [Adding 1 to both sides]sinx=12             [Dividing both sides by 2]x=arcsin(12)      [Inverse trigonometric function]x=π6,5π6           [Values of arcsin(12)]

Finally, because sinx has a period of 2π ,

  x=π6+2nπ and x=5π6+2nπ [General solution]

Where n is an integer.

The solution is confirmed graphically as follows:

Graph:

Sketch the graph using graphing utility.

Step 1: Press WINDOW button to access the Window editor.

Step 2: Press Y= button.

Step 3: Enter the expression 2cos2x+7sinx5 which is required to graph.

Step 4: Press GRAPH button to graph the function.

The graph is obtained as:

  Precalculus with Limits: A Graphing Approach, Chapter 5.3, Problem 86E

Chapter 5 Solutions

Precalculus with Limits: A Graphing Approach

Ch. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Prob. 16ECh. 5.1 - Prob. 17ECh. 5.1 - Prob. 18ECh. 5.1 - Prob. 19ECh. 5.1 - Prob. 20ECh. 5.1 - Prob. 21ECh. 5.1 - Prob. 22ECh. 5.1 - Prob. 23ECh. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.1 - Prob. 27ECh. 5.1 - Prob. 28ECh. 5.1 - Prob. 29ECh. 5.1 - Prob. 30ECh. 5.1 - Prob. 31ECh. 5.1 - Prob. 32ECh. 5.1 - Prob. 33ECh. 5.1 - Prob. 34ECh. 5.1 - Prob. 35ECh. 5.1 - Prob. 36ECh. 5.1 - Prob. 37ECh. 5.1 - Prob. 38ECh. 5.1 - Prob. 39ECh. 5.1 - Prob. 40ECh. 5.1 - Prob. 41ECh. 5.1 - Prob. 42ECh. 5.1 - Prob. 43ECh. 5.1 - Prob. 44ECh. 5.1 - Prob. 45ECh. 5.1 - Prob. 46ECh. 5.1 - Prob. 47ECh. 5.1 - Prob. 48ECh. 5.1 - Prob. 49ECh. 5.1 - Prob. 50ECh. 5.1 - Prob. 51ECh. 5.1 - Prob. 52ECh. 5.1 - Prob. 53ECh. 5.1 - Prob. 54ECh. 5.1 - Prob. 55ECh. 5.1 - Prob. 56ECh. 5.1 - Prob. 57ECh. 5.1 - Prob. 58ECh. 5.1 - Prob. 59ECh. 5.1 - Prob. 60ECh. 5.1 - Prob. 61ECh. 5.1 - Prob. 62ECh. 5.1 - Prob. 63ECh. 5.1 - 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Prob. 116ECh. 5.1 - Prob. 117ECh. 5.1 - Prob. 118ECh. 5.1 - Prob. 119ECh. 5.1 - Prob. 120ECh. 5.1 - Prob. 121ECh. 5.1 - Prob. 122ECh. 5.1 - Prob. 123ECh. 5.1 - Prob. 124ECh. 5.1 - Prob. 125ECh. 5.1 - Prob. 126ECh. 5.2 - Prob. 1ECh. 5.2 - Prob. 2ECh. 5.2 - Prob. 3ECh. 5.2 - Prob. 4ECh. 5.2 - Prob. 5ECh. 5.2 - Prob. 6ECh. 5.2 - Prob. 7ECh. 5.2 - Prob. 8ECh. 5.2 - Prob. 9ECh. 5.2 - Prob. 10ECh. 5.2 - Prob. 11ECh. 5.2 - Prob. 12ECh. 5.2 - Prob. 13ECh. 5.2 - Prob. 14ECh. 5.2 - Prob. 15ECh. 5.2 - Prob. 16ECh. 5.2 - Prob. 17ECh. 5.2 - Prob. 18ECh. 5.2 - Prob. 19ECh. 5.2 - Prob. 20ECh. 5.2 - Prob. 21ECh. 5.2 - Prob. 22ECh. 5.2 - Prob. 23ECh. 5.2 - Prob. 24ECh. 5.2 - Prob. 25ECh. 5.2 - Prob. 26ECh. 5.2 - Prob. 27ECh. 5.2 - Prob. 28ECh. 5.2 - Prob. 29ECh. 5.2 - Prob. 30ECh. 5.2 - Prob. 31ECh. 5.2 - Prob. 32ECh. 5.2 - Prob. 33ECh. 5.2 - Prob. 34ECh. 5.2 - Prob. 35ECh. 5.2 - Prob. 36ECh. 5.2 - Prob. 37ECh. 5.2 - Prob. 38ECh. 5.2 - Prob. 39ECh. 5.2 - Prob. 40ECh. 5.2 - Prob. 41ECh. 5.2 - Prob. 42ECh. 5.2 - 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Prob. 122RECh. 5 - Prob. 123RECh. 5 - Prob. 124RECh. 5 - Prob. 125RECh. 5 - Prob. 126RECh. 5 - Prob. 127RECh. 5 - Prob. 128RECh. 5 - Prob. 129RECh. 5 - Prob. 130RECh. 5 - Prob. 131RECh. 5 - Prob. 132RECh. 5 - Prob. 133RECh. 5 - Prob. 134RECh. 5 - Prob. 135RECh. 5 - Prob. 136RECh. 5 - Prob. 137RECh. 5 - Prob. 138RECh. 5 - Prob. 139RECh. 5 - Prob. 140RECh. 5 - Prob. 1CTCh. 5 - Prob. 2CTCh. 5 - Prob. 3CTCh. 5 - Prob. 4CTCh. 5 - Prob. 5CTCh. 5 - Prob. 6CTCh. 5 - Prob. 7CTCh. 5 - Prob. 8CTCh. 5 - Prob. 9CTCh. 5 - Prob. 10CTCh. 5 - Prob. 11CTCh. 5 - Prob. 12CTCh. 5 - Prob. 13CTCh. 5 - Prob. 14CTCh. 5 - Prob. 15CTCh. 5 - Prob. 16CTCh. 5 - Prob. 17CTCh. 5 - Prob. 18CTCh. 5 - Prob. 19CTCh. 5 - Prob. 20CTCh. 5 - Prob. 21CTCh. 5 - Prob. 22CTCh. 5 - Prob. 23CTCh. 5 - Prob. 24CT
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Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
Inverse Trigonometric Functions; Author: Professor Dave Explains;https://www.youtube.com/watch?v=YXWKpgmLgHk;License: Standard YouTube License, CC-BY