Precalculus with Limits: A Graphing Approach
Precalculus with Limits: A Graphing Approach
7th Edition
ISBN: 9781305071711
Author: Ron Larson
Publisher: Brooks/Cole
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Chapter 5.5, Problem 38E
To determine

To write:The expression cos8x in first power of cosine and verify both the expressions by graphing utility.

Expert Solution & Answer
Check Mark

Answer to Problem 38E

The expression cos8x can be written as 1128(35+28cos4x+cos8x+48cos2x+16cos2xcos4x) as a single power of cosine.

Explanation of Solution

Given information:

The expression is given as cos8x .

Formula used:

Use the power reducing formula cos2x=1+cos2x2 .

Calculation:

As per power reducing formula.

  cos2x=1+cos2x2

Substitute the value in the above expression.

  cos8x=(cos2x)4=(1+cos2x2)4=116(1+cos2x)2(1+cos2x)2=116(1+2cos2x+cos22x)(1+2cos2x+cos22x)

Further simplify.

  cos8x=116(1+2cos2x+1+cos4x2)(1+2cos2x+1+cos4x2)=116(1+2cos2x+1+cos2x2)(1+2cos2x+1+cos2x2)=116(3+4cos2x+cos4x2)(3+4cos2x+cos4x2)

Simplify further,

  cos8x=164(9+16cos22x+cos24x+24cos2x+8cos2xcos4x+6cos4x)=164(9+16(1+cos4x2)+(1+cos8x2)+24cos2x+8cos2xcos4x+6cos4x)=1128(35+28cos4x+cos8x+48cos2x+16cos2xcos4x)

Therefore the expression cos8x can be written as 1128(35+28cos4x+cos8x+48cos2x+16cos2xcos4x) as a single power of cosine.

Verify both the expressions using graphical utility:

Draw the graph for the expression cos8x as shown in the Figure (1).

  Precalculus with Limits: A Graphing Approach, Chapter 5.5, Problem 38E , additional homework tip  1

Figure (1)

Draw the graph for the expression 1128(35+28cos4x+cos8x+48cos2x+16cos2xcos4x) as shown in the Figure (2).

  Precalculus with Limits: A Graphing Approach, Chapter 5.5, Problem 38E , additional homework tip  2

Figure (2)

As both the expressions shows same values in Figure (1) and Figure (2) at each point.

Therefore both the expressions cos8x and 1128(35+28cos4x+cos8x+48cos2x+16cos2xcos4x) are same.

Chapter 5 Solutions

Precalculus with Limits: A Graphing Approach

Ch. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Prob. 16ECh. 5.1 - Prob. 17ECh. 5.1 - Prob. 18ECh. 5.1 - Prob. 19ECh. 5.1 - Prob. 20ECh. 5.1 - Prob. 21ECh. 5.1 - Prob. 22ECh. 5.1 - Prob. 23ECh. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.1 - Prob. 27ECh. 5.1 - Prob. 28ECh. 5.1 - Prob. 29ECh. 5.1 - Prob. 30ECh. 5.1 - Prob. 31ECh. 5.1 - Prob. 32ECh. 5.1 - Prob. 33ECh. 5.1 - Prob. 34ECh. 5.1 - Prob. 35ECh. 5.1 - Prob. 36ECh. 5.1 - Prob. 37ECh. 5.1 - Prob. 38ECh. 5.1 - Prob. 39ECh. 5.1 - Prob. 40ECh. 5.1 - Prob. 41ECh. 5.1 - Prob. 42ECh. 5.1 - Prob. 43ECh. 5.1 - Prob. 44ECh. 5.1 - Prob. 45ECh. 5.1 - Prob. 46ECh. 5.1 - Prob. 47ECh. 5.1 - Prob. 48ECh. 5.1 - Prob. 49ECh. 5.1 - Prob. 50ECh. 5.1 - Prob. 51ECh. 5.1 - Prob. 52ECh. 5.1 - Prob. 53ECh. 5.1 - Prob. 54ECh. 5.1 - Prob. 55ECh. 5.1 - Prob. 56ECh. 5.1 - Prob. 57ECh. 5.1 - Prob. 58ECh. 5.1 - Prob. 59ECh. 5.1 - Prob. 60ECh. 5.1 - Prob. 61ECh. 5.1 - Prob. 62ECh. 5.1 - Prob. 63ECh. 5.1 - 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Author:Michael Sullivan
Publisher:PEARSON
Text book image
Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
Inverse Trigonometric Functions; Author: Professor Dave Explains;https://www.youtube.com/watch?v=YXWKpgmLgHk;License: Standard YouTube License, CC-BY