World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 6, Problem 19A
Interpretation Introduction

Interpretation: The relation between molar mass of a substance and atomic masses of the component atoms needs to be explained.

Concept Introduction: Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The molar mass of a substance is the mass of 1 mole of substance. It is represented in g/mol. The relation between these values can be shown as:

  Moles = massmolar mass

Expert Solution & Answer
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Answer to Problem 19A

The molar mass of compound is the sum of atomic mass of the component.

Explanation of Solution

Given information:

The molar mass of a substance and atomic masses of the component atoms are related to each other.

The molar mass of compound is the sum of atomic mass of the component atoms present in the given chemical compound.

Since a molecule is composed of different atoms which are bonded with each other through chemical bonds, therefore molar mass (mass of 1 mole of substance) must be sum of atomic masses of these atoms.

Conclusion

The molar mass of compound is the sum of atomic mass of the component.

Chapter 6 Solutions

World of Chemistry, 3rd edition

Ch. 6.2 - Prob. 5RQCh. 6.2 - Prob. 6RQCh. 6.3 - Prob. 1RQCh. 6.3 - Prob. 2RQCh. 6.3 - Prob. 3RQCh. 6.3 - Prob. 4RQCh. 6.3 - Prob. 5RQCh. 6.3 - Prob. 6RQCh. 6 - Prob. 1ACh. 6 - Prob. 2ACh. 6 - Prob. 3ACh. 6 - Prob. 4ACh. 6 - Prob. 5ACh. 6 - Prob. 6ACh. 6 - Prob. 7ACh. 6 - Prob. 8ACh. 6 - Prob. 9ACh. 6 - Prob. 10ACh. 6 - Prob. 11ACh. 6 - Prob. 12ACh. 6 - Prob. 13ACh. 6 - Prob. 14ACh. 6 - Prob. 15ACh. 6 - Prob. 16ACh. 6 - Prob. 17ACh. 6 - Prob. 18ACh. 6 - Prob. 19ACh. 6 - Prob. 20ACh. 6 - Prob. 21ACh. 6 - Prob. 22ACh. 6 - Prob. 23ACh. 6 - Prob. 24ACh. 6 - Prob. 25ACh. 6 - Prob. 26ACh. 6 - Prob. 27ACh. 6 - Prob. 28ACh. 6 - Prob. 29ACh. 6 - Prob. 30ACh. 6 - Prob. 31ACh. 6 - Prob. 32ACh. 6 - Prob. 33ACh. 6 - Prob. 34ACh. 6 - Prob. 35ACh. 6 - Prob. 36ACh. 6 - Prob. 37ACh. 6 - Prob. 38ACh. 6 - Prob. 39ACh. 6 - Prob. 40ACh. 6 - Prob. 41ACh. 6 - Prob. 42ACh. 6 - Prob. 43ACh. 6 - Prob. 44ACh. 6 - Prob. 45ACh. 6 - Prob. 46ACh. 6 - Prob. 47ACh. 6 - Prob. 48ACh. 6 - Prob. 49ACh. 6 - Prob. 50ACh. 6 - Prob. 51ACh. 6 - Prob. 52ACh. 6 - Prob. 53ACh. 6 - Prob. 54ACh. 6 - Prob. 55ACh. 6 - Prob. 56ACh. 6 - Prob. 57ACh. 6 - Prob. 58ACh. 6 - Prob. 59ACh. 6 - Prob. 60ACh. 6 - Prob. 61ACh. 6 - Prob. 62ACh. 6 - Prob. 63ACh. 6 - Prob. 64ACh. 6 - Prob. 65ACh. 6 - Prob. 66ACh. 6 - Prob. 67ACh. 6 - Prob. 68ACh. 6 - Prob. 69ACh. 6 - Prob. 70ACh. 6 - Prob. 1STPCh. 6 - Prob. 2STPCh. 6 - Prob. 3STPCh. 6 - Prob. 4STPCh. 6 - Prob. 5STPCh. 6 - Prob. 6STPCh. 6 - Prob. 7STPCh. 6 - Prob. 8STPCh. 6 - Prob. 9STPCh. 6 - Prob. 10STPCh. 6 - Prob. 11STPCh. 6 - Prob. 12STP
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Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY