A cyclist goes around a level, circular track at constant speed. Do you agree or disagree with the following statement? “Since the cyclist’s speed is constant, her acceleration is zero.” Explain.
Answer to Problem 1CQ
Explanation of Solution
Consider any object moving in a circle at a constant speed. The motion obtained by that object is called as uniform circular motion. To obtain such a motion, acceleration must be given in the direction of the center of the circle.
This kind of acceleration is called as centripetal acceleration, which acts towards the center.
Conclusion:
Thus, there is an existence of acceleration in the given case.
Want to see more full solutions like this?
Chapter 6 Solutions
Modified Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (4th Edition)
Additional Science Textbook Solutions
University Physics Volume 1
An Introduction to Thermal Physics
College Physics
Introduction to Electrodynamics
University Physics (14th Edition)
Lecture- Tutorials for Introductory Astronomy
- In uniform circular motion, what are the average velocity and average acceleration for one revolution? Explain.arrow_forwardA hawk flies in a horizontal arc of radius 12.0 m at a constant speed of 7.1 m/s. It continues to fly along the same horizontal arc but increases its speed at the rate of 7.9m/s2. Find the acceleration magnitude under these conditions.arrow_forwardA man runs around a circular track of 800 meters radius for 30 seconds, starting at a point directly to the right of the center and goes in a counterclockwise manner. He goes 5 meters per second for the first 15 seconds, runs 90 meters for the next 6 seconds and then 180 meters for the rest of the course. What was his average speed, his displacement from the starting point, his average velocity, and his total displacement upon return to the starting point?arrow_forward
- A cyclist goes round a circular track, of radius 10 m, at a constant speed of 8.0 m s-1.What is the acceleration of the cyclist and what is its direction?arrow_forwardExplain Acceleration and velocity for a particle in uniform circular motion.arrow_forwardA car drives around a circular track of diameter 161 m at a constant speed of 47.4 m/s. During the time it takes the car to travel 256 degrees around, what is the magnitude of the car s average acceleration? Hint: Do not calculate instantenous accelleration. Instead calculte the average acceleration over the fraction of a complete lap. Average acceleration equals change in velocity divided by change in time, and that this is a two-dimensional situation so you'll have to calculate the x and y components of the average acceleration first and then figure out the magnitude. Remember also that ax = Δvx/Δt and ay = Δvy/Δt. 0 m/s^2 27.91 m/s^2 13.96 m/s^2 9.84 m/s^2arrow_forward
- A cyclist goes around a level circular track at a constant speed. Is the acceleration 0? Explainarrow_forward1. A ball is moving along a circular track. What can be said about the orientation of the velocity and acceleration vectors? Parallel Anti-parallel Perpendicular Out of phase by 180 degrees 2. All the following statements are false except: a. A body moving in a straight line at a constant speed can have acceleration. b. A body can still be accelerating even if its speed is constant. c. A body can have a constant velocity while turning a curve. d. A body can have a constant velocity while slowing down. 3. For bodies that are falling, to achieve terminal velocity, what must happen to the acceleration of the body? a. The acceleration of the body is remains the same through time. b. The acceleration of the body must decrease over time c. The acceleration of the body must equal to the acceleration due to gravity. d. The acceleration of the body must increase over time.arrow_forwardCan the total acceleration of an object undergoing circular motion be greater than the centripetal acceleration? Please explain.arrow_forward
- A car at a traffic signal starts from rest and makes a left turn in a circular trajectory of radius 6 m reaching a speed of 9 in 2 seconds. What is the magnitude of its total acceleration at t = 2 seconds? (You do not need to provide units, just the numerical value calculated in m/s2)arrow_forward2/99 A car is traveling around a circular track of 240 - m radius . If the magnitude of its total acceleration is 3 m / s2 at the instant when its speed is 75 km / h , determine the rate at which the car is changing its speed . Ans 0. = +239 m / s2arrow_forward
- An Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning