Concept explainers
(a)
Interpretation:
The configurational isomer of the compound containing
Concept Introduction :
The compounds are named as E-Z based on analysis of the groups at the end of double bond. The naming is done as per the CIP rules wherein the highest priority gets its preference meaning the highest
Configurational isomers are stereoisomers that have same molecular formula but cannot be converted through rotation about the single bond into another form.
(b)
Interpretation:
The nature of the molecule that falls out of the cis/trans naming scheme and comes under the E/Z naming scheme needs to be described.
Concept Introduction :
The compounds are named as E-Z based on analysis of the groups at the end of double bond. The naming is done as per the CIP rules wherein the highest priority.
Compounds are named cis or trans based on the position of the identical group about the double bond.
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Chapter 6 Solutions
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- Consider 1,2-dimethylcyclohexane. a.Draw structures for the cis and trans isomers using a hexagon for the sixmembered ring. b. Draw the two possible chair conformations for the cis isomer. Which conformation, if either, is more stable? c. Draw the two possible chair conformations for the trans isomer. Which conformation, if either, is more stable? d.Which isomer, cis or trans, is more stable and why?arrow_forwardHow many stereoisomers estuary for this molecule? Show how you know. A. 8 B. 3 C. 4 D. 6arrow_forward. Consider the hash/wedge structure below. a. Draw the Newman projection of the bond indicated, keeping the conformation the same. НО b. Draw the Newman projection for the most stable conformation CI c. In the Newman projection for part b, label all gauche interactions.arrow_forward
- Draw the stereoisomer with all trans double bonds. Draw the Lewis structures with the formal charges minimized. Do not include formal charges or electron pairs. You do not need to draw hydrogen atoms that are connected to carbon atoms. TIP: For hydrogen atoms, you only need to draw H atoms that are not bonded to carbons (i.e. O-H and N-H). Draw the other optical isomer.arrow_forwardH3C H. NHCH3 NHCH3 H Harrow_forward4. For the following structures, draw both possible chair conformations, using a ring flip to go from one to the other, and circle the one that is most stable/lowest energy. (Hint: Use Table 4.8 in Klein.) Show all groups, including hydrogen atoms, attached to the cyclohexane ring. А. Me Me Et В. Et t-Bu Etarrow_forward
- \Br A. Redraw the bond-line structure of the molecule above on a separate sheet of paper. B. Draw a chair conformation for the molecule. C. Draw the new chair conformation after ring inversion (ring flip). D. Circle the most stable (lowest energy) chair conformation.arrow_forward3)- Determine the total number of conformers and draw the Chair Structures of the conformers for the Tri-substituted cyclohexane structure given below (i.e., "A"). Draw the relative energy diagram for the possible conformers for the cyclohexane structure below. Note, draw only the required structures for the conformers of A. Also, include hydrogen atoms wherever there are substituents on all of your chair conformers. Answer (Total #of Conformers): Chair Structures: Relative Energy Diagram 8 bas roll 3arrow_forward2. In aqueous solution d-glucose (or dextrose) exists in equilibrium between a linear and cyclic form shown below. A. Mark all the stereocenters in the linear form of the molecule. Number them 1,2,3, etc. B. Draw out the reaction that converts the linear form to the 6-membered ring using the arrow formalism. C. Identify the stereocenters in the 6-member ring that correspond to the stereocenters in the linear form marking them as 1,2,3, etc. The reaction also created a new stereocenter. Mark it as H -OH HO--H H--OH нон Ho но HO HO H он H-OH H но.arrow_forward
- Ethane spends all its time in the staggered conformation because it has the lowest potential energy. a. True b. False c. Neitherarrow_forwardDraw all the isomers of C,H0. Clearly show stereochemistry if stereoisomers are possible. Step 1: Start by drawing all the isomers with double bonds. • Consider constitutional isomers, then stereoisomers. Step 2: Draw all isomers containing a ring. • Consider constitutional isomers, then stereoisomers. The longest chain does not have to contain all five carbon atoms. Draw the alkene isomers that have a 4-carbon main chain.arrow_forwardDraw a resonance structure, complete with all formal charges and lone (unshared) electron pairs, that shows the resonance interaction of the chloro with the para position in chlorobenzene. 0 chlorobenzene • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. In cases where there is more than one answer, just draw one. . 99-85 On [F ChemDoodleⓇarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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