EBK PHYSICS FUNDAMENTALS
2nd Edition
ISBN: 9780100265493
Author: Coletta
Publisher: YUZU
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Chapter 6, Problem 26P
(a)
To determine
To Find: The mass of the Milky Way.
(b)
To determine
To Find: The number of stars in the Milky Way.
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It is found that when a particular object with a mass of 0.41 kg is released from rest while immersed within a certain substance, the coefficient of proportionality regarding the resistive force is 0.621 kg/s. What is the magnitude of the resistive force that acts on this mass 1.49 s after being released?
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In this problem, you are going to explore three different ways to determine the gravitational constant G.
a) By observing that the centripetal acceleration of the Moon around the Earth is ac = 2.66 × 10-3 m/s2, what is the gravitatonal constant G, in cubic meters per kilogram per square second? Assume the Earth has a mass of ME = 5.96 × 1024 kg, and the mean distance between the centers of the Earth and Moon is rm = 3.81 × 108 m.
b) Measuring the centripetal acceleration of an orbiting object is rather difficult, so an alternative approach is to use the period of the orbiting object. Find an expression for the gravitational constant in terms of the distance between the gravitating objects rm, the mass of the larger body (the earth) ME, and the period of the orbiting body T.
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Given the fact that water has less mass per cubic meter than soil and rock , would you expect the value of g to be smaller or larger than average over a lake?
Chapter 6 Solutions
EBK PHYSICS FUNDAMENTALS
Ch. 6 - Prob. 1QCh. 6 - Prob. 2QCh. 6 - Prob. 3QCh. 6 - Prob. 4QCh. 6 - Prob. 5QCh. 6 - Prob. 6QCh. 6 - Prob. 7QCh. 6 - Prob. 8QCh. 6 - Prob. 9QCh. 6 - Prob. 10Q
Ch. 6 - Prob. 11QCh. 6 - Prob. 12QCh. 6 - Prob. 13QCh. 6 - Prob. 14QCh. 6 - Prob. 15QCh. 6 - Prob. 1PCh. 6 - Prob. 2PCh. 6 - Prob. 3PCh. 6 - Prob. 4PCh. 6 - Prob. 5PCh. 6 - Prob. 6PCh. 6 - Prob. 7PCh. 6 - Prob. 8PCh. 6 - Prob. 9PCh. 6 - Prob. 10PCh. 6 - Prob. 11PCh. 6 - Prob. 12PCh. 6 - Prob. 13PCh. 6 - Prob. 14PCh. 6 - Prob. 15PCh. 6 - Prob. 16PCh. 6 - Prob. 17PCh. 6 - Prob. 18PCh. 6 - Prob. 19PCh. 6 - Prob. 20PCh. 6 - Prob. 21PCh. 6 - Prob. 22PCh. 6 - Prob. 23PCh. 6 - Prob. 24PCh. 6 - Prob. 25PCh. 6 - Prob. 26PCh. 6 - Prob. 27PCh. 6 - Prob. 28PCh. 6 - Prob. 29PCh. 6 - Prob. 30PCh. 6 - Prob. 31PCh. 6 - Prob. 32PCh. 6 - Prob. 33PCh. 6 - Prob. 34PCh. 6 - Prob. 35PCh. 6 - Prob. 36PCh. 6 - Prob. 37PCh. 6 - Prob. 38PCh. 6 - Prob. 39PCh. 6 - Prob. 40PCh. 6 - Prob. 41PCh. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - Prob. 44PCh. 6 - Prob. 45P
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- The gravitational force exerted by the earth on a unit massat a distance r from the center of the planet is where M is the mass of the earth,R is its radius, and G isthe gravitational constant. Is F a continuous function of r ?arrow_forwardA satellite encircles Mars at a distance above its surface equal to 3 times the radius of Mars. If gm is the acceleration due to gravity at the surface of Mars, what is the acceleration due to gravity at the location of the satellite?arrow_forwardThe gravitational acceleration constant gx on Planet X can be approximated by determining the acceleration of an object assuming Newton's Law of Universal Gravitation. If gx = 3.8 m/s^2 , G = 6.7 x 10^-11 Nm^2/kg^2, and Planet X's radius is 4000 km, what is the approximate mass of planet X? Give answer in kg.arrow_forward
- Assume a planet is a uniform sphere of radius R that(somehow) has a narrow radial tunnel through its center. Also assume we can position an apple anywherealong the tunnel or outside the sphere. Let FR be the magnitudeof the gravitational force on the apple when it is located atthe planet’s surface. How farfrom the surface is there a pointwhere the magnitude is FR ifwe move the apple (a) awayfrom the planet and (b) intothe tunnel?arrow_forwardWhat must the separation be between a 5.2 kg particle and a 2.4 kg particle for their gravitational attraction to have a magnitude of 2.3 * 10-12 N?arrow_forwardAstronomical observations of our Milky Way galaxy indicate that it has a mass of about 8.0 ✕ 1011 solar masses. A star orbiting near the galaxy's periphery is 6.0 ✕ 104 light-years from its center. If its period is 5.3 ✕ 107 years instead, what is the mass (in solar masses) of the galaxy? Such calculations are used to imply the existence of other matter, such as a very massive black hole at the center of the Milky Way. solar masses *answer for b*arrow_forward
- Suppose that, while lying on a beach near the equator watching the Sun set over a calm ocean, you start a stopwatch just as the top of the Sun disappears. You then stand, elevating your eyes by a height H = 1.70 m, and stop the watch when the top of the Sun again disappears. If the elapsed time is t = 11.1 s, what is the radius r of Earth?arrow_forwardWhile standing on the surface of a spherical asteriod of mass M and radius R., and astronaut thows a small rock straight upward away from the center. What is the minimum speed she must give to the rock to reach a height h above the surface. Assume that h is not small compared to R. The asteriod has no atmosphere and take the rock's mass to be small compared to M.arrow_forwardChapter 11 67. A nonuniform thin rod of length L lies on the x axis. One end of the rod is at the origin, and the other end is at x=L. the rod's mass per unit length λ varies as λ=Cx, where C is a constant.(Thus, an element of the rod has mass dm=λ dx.) (a) Determine the total mass of the rod. (b)Determine the gravitational field due to the rod on the x axis at x=x0, there x0 >L.arrow_forward
- The “mean” orbital radius listed for astronomical objects orbiting the Sun is typically not an integrated average but is calculated such that it gives the correct period when applied to the equation for circular orbits. Given that, what is the mean orbital radius in terms of aphelion and perihelion?arrow_forwardShow that for small changes in height h, such that hRE , Equation 13.4 reduces to the expression U=mgh .arrow_forwardLet gM represent the difference in the gravitational fields produced by the Moon at the points on the Earths surface nearest to and farthest from the Moon. Find the fraction gM/g, where g is the Earths gravitational field. (This difference is responsible for the occurrence of the lunar tides on the Earth.)arrow_forward
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