Chapter 6, Problem 43A

To determine

To Write:A real life physics problem using the given relations.

Explanation of Solution

Find the horizontal distance covered by a ball, when it is thrown horizontally with a velocity from a high tower, given that

The horizontal distance,

Given that height of the tower is horizontal velocity of the ball is

If one throws the ball horizontally with a velocity then vertical velocity of the ball is zero.

Consider the vertical motion of the ball as it is starting from rest.

And for horizontal motion it is moving with a uniform velocity v= 1.5 m/s

h , g , t are related as

Here, initial velocity for vertical motion is

So, the given relation,

Wheresolving this we get time t as:

Which gives

Here, the total time of flight is t seconds.

In t seconds, it comes vertically down a height of 8 m.

Also, in this time, it travels a horizontal distance x m with uniform velocity

We know that the relation between the time, uniform velocity and distance is,

Using the value of t in the above equation,

This is the required horizontal distance.