Brock Biology of Microorganisms (14th Edition)
14th Edition
ISBN: 9780321897398
Author: Michael T. Madigan, John M. Martinko, Kelly S. Bender, Daniel H. Buckley, David A. Stahl, Thomas Brock
Publisher: PEARSON
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Chapter 6, Problem 4RQ
Summary Introduction
The entire amount of DNA sustains within one copy of an individual genome is called as genome size. The genome size is estimated in the terms of pictograms. In the molecular genetics, the section of reading frame that has the possibility to translate are referred as an open reading frame. The open reading frame consists of a frequent stretch of the codons includes stop codons (UAA, UGA or UAG) and start codon (AUG).
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Chapter 6 Solutions
Brock Biology of Microorganisms (14th Edition)
Ch. 6.1 - Prob. 1MQCh. 6.1 - Prob. 2MQCh. 6.2 - Prob. 1MQCh. 6.2 - Prob. 2MQCh. 6.2 - Prob. 3MQCh. 6.3 - Prob. 1MQCh. 6.3 - Prob. 2MQCh. 6.3 - What is the major problem in identifying genes...Ch. 6.4 - Prob. 1MQCh. 6.4 - Prob. 2MQ
Ch. 6.4 - Prob. 3MQCh. 6.4 - Prob. 4MQCh. 6.5 - Prob. 1MQCh. 6.5 - Prob. 2MQCh. 6.5 - Prob. 3MQCh. 6.6 - Prob. 1MQCh. 6.6 - Prob. 2MQCh. 6.6 - Prob. 3MQCh. 6.6 - Prob. 4MQCh. 6.7 - Prob. 1MQCh. 6.7 - Prob. 2MQCh. 6.7 - Prob. 3MQCh. 6.8 - Why is the term proteome ambiguous, whereas the...Ch. 6.8 - Prob. 2MQCh. 6.8 - Prob. 3MQCh. 6.9 - Prob. 1MQCh. 6.9 - What is a secondary metabolite?Ch. 6.9 - Prob. 3MQCh. 6.10 - Prob. 1MQCh. 6.10 - How is a metagenome analyzed?Ch. 6.10 - How do the human microbiome and mycobiome differ?
Ch. 6.11 - Prob. 1MQCh. 6.11 - Prob. 2MQCh. 6.11 - Prob. 3MQCh. 6.12 - Which class of genes is rarely transferred...Ch. 6.12 - List the major mechanisms by which horizontal gene...Ch. 6.12 - How might transposons be especially important in...Ch. 6.13 - Prob. 1MQCh. 6.13 - Prob. 2MQCh. 6.13 - Prob. 3MQCh. 6 - Prob. 1RQCh. 6 - Prob. 2RQCh. 6 - Prob. 3RQCh. 6 - Prob. 4RQCh. 6 - As a proportion of the total genome, which class...Ch. 6 - Prob. 6RQCh. 6 - Prob. 7RQCh. 6 - Prob. 8RQCh. 6 - Prob. 9RQCh. 6 - Prob. 10RQCh. 6 - Prob. 11RQCh. 6 - Prob. 12RQCh. 6 - Prob. 13RQCh. 6 - What is the major difference in how duplications...Ch. 6 - Explain how horizontally transferred genes can be...Ch. 6 - Prob. 16RQCh. 6 - Explain how chromosomal islands might move between...Ch. 6 - Prob. 18RQCh. 6 - Apart from genome size, what factors make complete...Ch. 6 - Describe how one might determine which proteins In...Ch. 6 - The gene encoding the beta subunit of RNA...
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- What is the principle of Sanger sequencing?arrow_forwardWhy do geneticists studying eukaryotic organisms often construct cDNA libraries, whereas geneticistsstudying bacteria almost never do? Why might bacterial geneticists have difficulties constructing cDNA libraries even if they wanted to?arrow_forwardWhat is the mechanism by which the Alu sequence has become dispersed to many sites in the genome?arrow_forward
- What is the significance of digesting the 16S rRNA product in 16s gene sequencing?arrow_forwardWhat is a repetitive element in genomics? What are the types of repetitive elements? What is their effect on the ease of determining and analyzing a genome sequence?arrow_forwardWhat is the primary disadvantage of Sanger sequencing?arrow_forward
- Apart from genome size, what factors make completeassembly of a eukaryotic genome more difficult than assemblyof a genome from a species of Bacteria or Archaea?arrow_forwardWhy are closure and completeness important in genome sequencing?arrow_forwardWhat proportion of exons are repeated sequences in the human genome? Is 38% surprising?arrow_forward
- Considering that prokaryote genomes do not have large introns, how is it possible to move a eukaryotic gene into a transformed bacterium, since they lack a spliceosome?arrow_forwardIf the bandicoot genome is 3.62 x 109 base pairs, and the "highly repetitive DNA" fraction is composed entirely of copies of sequence 5'TGCGTGTGTGC3' and its complement, how many copies of this sequence are present in the bandicoot genome?arrow_forwardIn reversible terminator sequencing, how would the sequencing process be affected if the 3′-end-blocking group of each nucleotide were replaced with the 3′-H present in the dideoxynucleotides used in Sanger sequencing?arrow_forward
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