Part (a)
Maximum height of lunar module to shut off the engine if the velocity of the lander relative to the surface at that moment is 0 m/s.
Part (a)
Answer to Problem 55P
Solution:2.8 m
Explanation of Solution
Given:Acceleration due to gravity at moon
Velocity of the lander relative to the surface at that moment is 0 m/s.
Formula Used:
During landing, only gravitational force due moon is acting conservation of energy.
Calculation:
Initial kinetic energy:
Initial potential energy:
Final kinetic energy:
Final potential energy:
Apply conservation of energy
Conclusion:Maximum height of lunar module to shut off the engine if the velocity of the lander relative to the surface at that moment is 0 m/s is 2.8 m.
Part (b)
Maximum height of lunar module to shut off the engine if the velocity of the lander relative to the surface at that moment is
Part (b)
Answer to Problem 55P
Solution: 1.5 m
Explanation of Solution
Given: Acceleration due to gravity at moon
Velocity of the lander relative to the surface at that moment is 2 m/s downwards
Formula Used:
During landing, only gravitational force due moon is acting conservation of energy.
Calculation:
Initial kinetic energy:
Initial potential energy:
Final kinetic energy:
Final potential energy:
Apply conservation of energy
Conclusion:Maximum height of shut off the engine
Part (c)
Maximum height of lunar module to shut off the engine if the velocity of the lander relative to the surface at that moment is
Part (c)
Answer to Problem 55P
Solution: 1.5 m
Explanation of Solution
Given: Acceleration due to gravity at moon
velocity of the lander relative to the surface at that moment is 2 m/s upwards.
Formula Used:
During landing, only gravitational force due moon is acting conservation of energy.
Calculation:
Initial kinetic energy:
Initial potential energy:
Final kinetic energy:
Final potential energy:
Apply conservation of energy
Conclusion:Maximum height of shut off the engine
Chapter 6 Solutions
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