BuyFind

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
BuyFind

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

Solutions

Chapter 6, Problem 57GQ

(a)

Interpretation Introduction

Interpretation: The wavelength of cell phone signal has to be calculated.

Concept introduction:

The frequency of the light is inversely proportional to its wavelength.

  ν=cλwhere, c=speedoflightν=frequencyλ=wavelength

(b)

Interpretation Introduction

Interpretation: The energy per mole of photons of cell phone signal has to be calculated.

Concept introduction:

Planck’s equation,

  E=where, E=energyh=Planck'sconstantν=frequency

The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

(c)

Interpretation Introduction

Interpretation: The energy of violet light is to be compared with 850MHz cell phone signal

Concept introduction:

  • Planck’s equation,

  E=where, E=energyh=Planck'sconstantν=frequency

The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

  • The frequency of the light is inversely proportional to its wavelength.

  ν=cλwhere, c=speedoflightν=frequencyλ=wavelength

(d)

Interpretation Introduction

Interpretation: The energy difference in violet light and cell phone signal with 850MHz has to be compared.

Concept introduction:

Planck’s equation,

  E=where, E=energyh=Planck'sconstantν=frequency

The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

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