The radiation having the greater energy per photon from the given types of electromagnetic radiations is to be determined from the given option. Concept introduction: Electromagnetic radiations are a type of energy surrounding us. They are of different types like radio waves, IR, UV, X-ray etc. UV-B lies between 315 nm to 280 nm whereas microwave radiation is in between 30 cm and 1 mm . Planck’s equation, E = hν where, E = energy h = Planck's constant ν = frequency The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases. The frequency of the light is inversely proportional to its wavelength. ν = c λ where, c = speed of light ν = frequency λ = wavelength

BuyFind

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
BuyFind

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

Solutions

Chapter 6.2, Problem 2RC
Interpretation Introduction

Interpretation: The radiation having the greater energy per photon from the given types of electromagnetic radiations is to be determined from the given option.

Concept introduction:

  • Electromagnetic radiations are a type of energy surrounding us. They are of different types like radio waves, IR, UV, X-ray etc.
  • UV-B lies between 315nm to 280nm whereas microwave radiation is in between 30cm and 1mm .
  • Planck’s equation,

E=where, E=energyh=Planck'sconstantν=frequency

The energy increases as the wavelength of the light decrease. Also the energy increases as the frequency of the light increases.

  • The frequency of the light is inversely proportional to its wavelength.

ν=cλwhere, c=speedoflightν=frequencyλ=wavelength

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