Chemistry
Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 6, Problem 6.159AP

(a)

Interpretation Introduction

Interpretation: One cotton ball soaked in ammonia and another soaked in hydrochloric acid is given to be placed at opposite ends of a 1m glass tube. The vapors are given to diffuse towards the middle of the tube and form a white ring of ammonium chloride at the point where they met. The stated questions based upon the above statement are to be answered.

Concept introduction: According to the Graham’s law of effusion,

r1M

To determine: The chemical equation for the reaction between ammonia and hydrochloric acid.

(a)

Expert Solution
Check Mark

Answer to Problem 6.159AP

Solution

The balance chemical equation for the reaction between ammonia and hydrochloric acid is stated as follows.

Explanation of Solution

Explanation

The chemical equation corresponding to the reaction between ammonia and hydrochloric acid is,

NH3(g)+HCl(g)NH4Cl(s)

The stated equation is already in its balanced form.

(b)

Interpretation Introduction

To determine: The location of the ammonium chloride ring.

(b)

Expert Solution
Check Mark

Answer to Problem 6.159AP

Solution

The ammonium chloride ring will be formed near the end of hydrochloric acid gas.

Explanation of Solution

Explanation

The tube contains air. Due to the presence of air, the ammonia and hydrochloric acid molecules undergo many collisions with the components present in the air, that is O2andN2 .

The molecular weight of HCl is,

MolecularweightofHCl=H+Cl=1.0079g/mol+35.453g/mol=36.4608g/mol

The molecular weight of NH3 is,

MolecularweightofNH3=N+3H=14.00g/mol+3×1.0079g/mol=17.0304g/mol

The molecular weight of NH3 is less than that of HCl . Therefore, NH3 is the lighter gas.

The ammonium gas molecules have high velocities due to a smaller mass than HCl .

Therefore, the ring of ammonium chloride will be formed near the end of HCl .

(c)

Interpretation Introduction

To determine: The distance from the ammonia end to the position of the ammonium chloride ring.

(c)

Expert Solution
Check Mark

Answer to Problem 6.159AP

Solution

The distance from the ammonia end is 0.5928m_

Explanation of Solution

Explanation

According to Graham’s law of effusion,

r1M (1)

Where,

  • r is the rate of diffusion.
  • M is the molar mass.

The molar masses of two gases are assumed to be MHClandMNH3 .

The time for diffusion of same amount of gas is assumed to be rHClandrNH3 .

For two different molar masses and temperatures the above expression is written as,

rNH3rHCl=MHClMNH3 (1)

Where,

  • rNH3 is the rate of diffusion of ammonia gas.
  • rHCl is the rate of diffusion of hydrochloric acid gas.
  • MHCl is the molar mass of hydrochloric acid gas.
  • MNH3 is the molar mass of ammonia gas is.

The molecular weight of HCl is,

MolecularweightofHCl=H+Cl=1.0079g/mol+35.453g/mol=36.4608g/mol

The molecular weight of NH3 is,

MolecularweightofNH3=N+3H=14.00g/mol+3×1.0079g/mol=17.0304g/mol

Substitute the required values in equation (1).

rNH3rHCl=MHClMNH3=36.460917.0304=1.465

The distance of the ring from HCl end is assumed to be Lcm .

The time taken by both gases to meet is assumed to be T .

Therefore, the distance from ammonia’s end will be (100L)cm .

(100LT)LT=1.465100LL=1.465100L=1.465L

Simplify the above equation,

L=1002.465L=40.72cm

So, L is the distance travelled from HCl end and the distance travelled from ammonia end is calculated by the formula,

Distance=100cm(DistancetravelledfromtheHClend)

Substitute the value of the distance travelled from the HCl end in the above formula.

Distance=100cm(DistancetravelledfromtheHClend)=100cm40.72cm=59.28cm=0.5928m_

Therefore, the distance travelled from ammonia end is 0.5928m_ .

Conclusion

  1. a) The balanced chemical equation for the reaction between ammonia and hydrochloric acid is

    NH3(g)+HCl(g)NH4Cl(s)

  2. b) The ammonium chloride ring will be formed near the end of hydrochloric acid gas.
  3. c) The distance from the ammonia end is 0.5928m_

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Chapter 6 Solutions

Chemistry

Ch. 6.6 - Prob. 11PECh. 6.7 - Prob. 12PECh. 6.7 - Prob. 13PECh. 6.7 - Prob. 14PECh. 6.8 - Prob. 15PECh. 6.8 - Prob. 16PECh. 6 - Prob. 6.1VPCh. 6 - Prob. 6.2VPCh. 6 - Prob. 6.3VPCh. 6 - Prob. 6.4VPCh. 6 - Prob. 6.5VPCh. 6 - Prob. 6.6VPCh. 6 - Prob. 6.7VPCh. 6 - Prob. 6.8VPCh. 6 - Prob. 6.9VPCh. 6 - Prob. 6.10VPCh. 6 - Prob. 6.11VPCh. 6 - Prob. 6.12VPCh. 6 - Prob. 6.13VPCh. 6 - Prob. 6.14VPCh. 6 - Prob. 6.15VPCh. 6 - Prob. 6.16VPCh. 6 - Prob. 6.17VPCh. 6 - Prob. 6.18VPCh. 6 - Prob. 6.19VPCh. 6 - Prob. 6.20VPCh. 6 - Prob. 6.21VPCh. 6 - Prob. 6.22VPCh. 6 - Prob. 6.23QPCh. 6 - Prob. 6.24QPCh. 6 - Prob. 6.25QPCh. 6 - Prob. 6.26QPCh. 6 - Prob. 6.27QPCh. 6 - Prob. 6.28QPCh. 6 - Prob. 6.29QPCh. 6 - Prob. 6.30QPCh. 6 - Prob. 6.31QPCh. 6 - Prob. 6.32QPCh. 6 - Prob. 6.33QPCh. 6 - Prob. 6.34QPCh. 6 - Prob. 6.35QPCh. 6 - Prob. 6.36QPCh. 6 - Prob. 6.37QPCh. 6 - Prob. 6.38QPCh. 6 - Prob. 6.39QPCh. 6 - Prob. 6.40QPCh. 6 - Prob. 6.41QPCh. 6 - Prob. 6.42QPCh. 6 - Prob. 6.43QPCh. 6 - Prob. 6.44QPCh. 6 - Prob. 6.45QPCh. 6 - Prob. 6.46QPCh. 6 - Prob. 6.47QPCh. 6 - Prob. 6.48QPCh. 6 - Prob. 6.49QPCh. 6 - Prob. 6.50QPCh. 6 - Prob. 6.51QPCh. 6 - Prob. 6.52QPCh. 6 - Prob. 6.53QPCh. 6 - Prob. 6.54QPCh. 6 - Prob. 6.55QPCh. 6 - Prob. 6.56QPCh. 6 - Prob. 6.57QPCh. 6 - Prob. 6.58QPCh. 6 - Prob. 6.59QPCh. 6 - Prob. 6.60QPCh. 6 - Prob. 6.61QPCh. 6 - Prob. 6.62QPCh. 6 - Prob. 6.63QPCh. 6 - Prob. 6.64QPCh. 6 - Prob. 6.65QPCh. 6 - Prob. 6.66QPCh. 6 - Prob. 6.67QPCh. 6 - Prob. 6.68QPCh. 6 - Prob. 6.69QPCh. 6 - Prob. 6.70QPCh. 6 - Prob. 6.71QPCh. 6 - Prob. 6.72QPCh. 6 - Prob. 6.73QPCh. 6 - Prob. 6.74QPCh. 6 - Prob. 6.75QPCh. 6 - Prob. 6.76QPCh. 6 - Prob. 6.77QPCh. 6 - Prob. 6.78QPCh. 6 - Prob. 6.79QPCh. 6 - Prob. 6.80QPCh. 6 - Prob. 6.81QPCh. 6 - Prob. 6.82QPCh. 6 - Prob. 6.83QPCh. 6 - Prob. 6.84QPCh. 6 - Prob. 6.85QPCh. 6 - Prob. 6.86QPCh. 6 - Prob. 6.87QPCh. 6 - Prob. 6.88QPCh. 6 - Prob. 6.89QPCh. 6 - Prob. 6.90QPCh. 6 - Prob. 6.91QPCh. 6 - Prob. 6.92QPCh. 6 - Prob. 6.93QPCh. 6 - Prob. 6.94QPCh. 6 - Prob. 6.95QPCh. 6 - Prob. 6.96QPCh. 6 - Prob. 6.97QPCh. 6 - Prob. 6.98QPCh. 6 - Prob. 6.99QPCh. 6 - Prob. 6.100QPCh. 6 - Prob. 6.101QPCh. 6 - Prob. 6.102QPCh. 6 - Prob. 6.103QPCh. 6 - Prob. 6.104QPCh. 6 - Prob. 6.105QPCh. 6 - Prob. 6.106QPCh. 6 - Prob. 6.107QPCh. 6 - Prob. 6.108QPCh. 6 - Prob. 6.109QPCh. 6 - Prob. 6.110QPCh. 6 - Prob. 6.111QPCh. 6 - Prob. 6.112QPCh. 6 - Prob. 6.113QPCh. 6 - Prob. 6.114QPCh. 6 - Prob. 6.115QPCh. 6 - Prob. 6.116QPCh. 6 - Prob. 6.117QPCh. 6 - Prob. 6.118QPCh. 6 - Prob. 6.119QPCh. 6 - Prob. 6.120QPCh. 6 - Prob. 6.121QPCh. 6 - Prob. 6.122QPCh. 6 - Prob. 6.123QPCh. 6 - Prob. 6.124QPCh. 6 - Prob. 6.125QPCh. 6 - Prob. 6.126QPCh. 6 - Prob. 6.127QPCh. 6 - Prob. 6.128QPCh. 6 - Prob. 6.129QPCh. 6 - Prob. 6.130QPCh. 6 - Prob. 6.131QPCh. 6 - Prob. 6.132QPCh. 6 - Prob. 6.133QPCh. 6 - Prob. 6.134QPCh. 6 - Prob. 6.135QPCh. 6 - Prob. 6.136QPCh. 6 - Prob. 6.137QPCh. 6 - Prob. 6.138QPCh. 6 - Prob. 6.139QPCh. 6 - Prob. 6.140QPCh. 6 - Prob. 6.141QPCh. 6 - Prob. 6.142QPCh. 6 - Prob. 6.143QPCh. 6 - Prob. 6.144QPCh. 6 - Prob. 6.145APCh. 6 - Prob. 6.146APCh. 6 - Prob. 6.147APCh. 6 - Prob. 6.148APCh. 6 - Prob. 6.149APCh. 6 - Prob. 6.150APCh. 6 - Prob. 6.151APCh. 6 - Prob. 6.152APCh. 6 - Prob. 6.153APCh. 6 - Prob. 6.154APCh. 6 - Prob. 6.155APCh. 6 - Prob. 6.156APCh. 6 - Prob. 6.157APCh. 6 - Prob. 6.158APCh. 6 - Prob. 6.159APCh. 6 - Prob. 6.160APCh. 6 - Prob. 6.161APCh. 6 - Prob. 6.162APCh. 6 - Prob. 6.163APCh. 6 - Prob. 6.164APCh. 6 - Prob. 6.165APCh. 6 - Prob. 6.166APCh. 6 - Prob. 6.167APCh. 6 - Prob. 6.168APCh. 6 - Prob. 6.169APCh. 6 - Prob. 6.170APCh. 6 - Prob. 6.171APCh. 6 - Prob. 6.172APCh. 6 - Prob. 6.173APCh. 6 - Prob. 6.174APCh. 6 - Prob. 6.175APCh. 6 - Prob. 6.176APCh. 6 - Prob. 6.177APCh. 6 - Prob. 6.178APCh. 6 - Prob. 6.179APCh. 6 - Prob. 6.180APCh. 6 - Prob. 6.181APCh. 6 - Prob. 6.182APCh. 6 - Prob. 6.183APCh. 6 - Prob. 6.184APCh. 6 - Prob. 6.185APCh. 6 - Prob. 6.186APCh. 6 - Prob. 6.187APCh. 6 - Prob. 6.188AP
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