Chemistry
Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 6, Problem 6.48QP

(a)

Interpretation Introduction

Interpretation: The behavior of 485mL of an ideal gas in response to pressure is studied in a vessel of the gas. The final volume if the pressure of the sample is increased from 715mmHg   to 3.55atm , decreased from 1.15atm to 520mmHg , and increased by 26% is to be calculated.

Concept introduction: An Ideal gas is the theoretical gas whose atoms possess negligible space and no interactions, and which thus obeys the gas laws exactly. The gas laws deal with the behavior of gases with respect to pressure, temperature and volume.

According to Boyle’s law,

Pα1V

To determine: The final volume of the gas if pressure is increased from 715mmHg to 3.55atm at constant temperature.

(a)

Expert Solution
Check Mark

Answer to Problem 6.48QP

Solution

The final volume of the gas is 136mL_ when pressure is increased from 715mmHg to 3.55atm at constant temperature.

Explanation of Solution

Explanation

Given

The initial pressure is 715mmHg .

The final pressure is 3.55atm .

The initial volume is 485mL .

Conversion of 1mmHg into atm is done as,

1mmHg=1760atm

Therefore, conversion of 715mmHg into atm is,

715mmHg=1×715760atm=0.941atm

The gas laws deal with the behavior of gases with respect to pressure, temperature and volume.

According to Boyle’s law,

Pα1V

It shows that as the volume increases, pressure of gas decreases at constant temperature.

Therefore, the equation is written as,

P1V1=P2V2

Where,

  • P1 is the initial pressure.
  • V1 is the initial volume of gas.
  • V2 is the final volume.

Substitute the given value in above equation,

V2=P1×V1P2=0.941atm×485mL3.35atm=136mL_

Therefore, final volume of the gas is 136mL_ .

(b)

Interpretation Introduction

To determine: The final volume of the gas if pressure is decreased from 1.15atm to 529mmHg at constant temperature.

(b)

Expert Solution
Check Mark

Answer to Problem 6.48QP

Solution

The final volume of the gas is 815mL_ when pressure is decreased from 1.15atm to 529mmHg at constant temperature.

Explanation of Solution

Explanation

Given

The initial pressure is 1.15atm .

The final pressure is 529mmHg .

The initial volume is 485mL .

Conversion of 1mmHg into atm is done as,

1mmHg=1760atm

Therefore, conversion of 529mmHg into atm is,

529mmHg=1×529760atm=0.684atm

The gas laws deal with the behavior of gases with respect to pressure, temperature and volume.

According to Boyle’s law,

Pα1V

It shows that as the volume increases, pressure of gas decreases at constant temperature.

Therefore, the equation is written as,

P1V1=P2V2

Where,

  • P1 is the initial pressure.
  • V1 is the initial volume of gas.
  • V2 is the final volume.

Substitute the given value in above equation,

V2=P1×V1P2=1.15atm×485mL0.684atm=815mL_

Therefore, final volume of the gas is 815mL_ .

(c)

Interpretation Introduction

To determine: The final volume of the gas if pressure is increased by 26% at constant temperature.

(c)

Expert Solution
Check Mark

Answer to Problem 6.48QP

Solution

The final volume of the gas is 385mL_ when pressure is increased by 26% at constant temperature.

Explanation of Solution

Explanation

Given

The initial pressure is P1 .

The initial volume is 485mL .

The final pressure is increased by 26% .

The gas laws deal with the behavior of gases with respect to pressure, temperature and volume.

According to Boyle’s law,

Pα1V

It shows that as the volume increases, pressure of gas decreases at constant temperature.

Therefore, the equation is written as,

P1V1=P2V2

Where,

  • P1 is the initial pressure.
  • V1 is the initial volume of gas.
  • V2 is the final volume.

It is given that the pressure is increased by 26% at constant temperature which means,

P2=P1+(P1×26100)=P1+13P150=63P150

Substitute the given value in above equation,

V2=P1×V1P2=P1×48563P1/50=385mL_

Therefore, final volume of the gas is 385mL_ .

Conclusion

  1. a. The final volume of the gas is 136mL_ when pressure is increased from 715mmHg to 3.55atm at constant temperature.
  2. b. The final volume of the gas is 815mL_ when pressure is decreased from 1.15atm to 529mmHg at constant temperature.
  3. c. The final volume of the gas is 385mL_ when pressure is increased by 26% at constant temperature

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Chapter 6 Solutions

Chemistry

Ch. 6.6 - Prob. 11PECh. 6.7 - Prob. 12PECh. 6.7 - Prob. 13PECh. 6.7 - Prob. 14PECh. 6.8 - Prob. 15PECh. 6.8 - Prob. 16PECh. 6 - Prob. 6.1VPCh. 6 - Prob. 6.2VPCh. 6 - Prob. 6.3VPCh. 6 - Prob. 6.4VPCh. 6 - Prob. 6.5VPCh. 6 - Prob. 6.6VPCh. 6 - Prob. 6.7VPCh. 6 - Prob. 6.8VPCh. 6 - Prob. 6.9VPCh. 6 - Prob. 6.10VPCh. 6 - Prob. 6.11VPCh. 6 - Prob. 6.12VPCh. 6 - Prob. 6.13VPCh. 6 - Prob. 6.14VPCh. 6 - Prob. 6.15VPCh. 6 - Prob. 6.16VPCh. 6 - Prob. 6.17VPCh. 6 - Prob. 6.18VPCh. 6 - Prob. 6.19VPCh. 6 - Prob. 6.20VPCh. 6 - Prob. 6.21VPCh. 6 - Prob. 6.22VPCh. 6 - Prob. 6.23QPCh. 6 - Prob. 6.24QPCh. 6 - Prob. 6.25QPCh. 6 - Prob. 6.26QPCh. 6 - Prob. 6.27QPCh. 6 - Prob. 6.28QPCh. 6 - Prob. 6.29QPCh. 6 - Prob. 6.30QPCh. 6 - Prob. 6.31QPCh. 6 - Prob. 6.32QPCh. 6 - Prob. 6.33QPCh. 6 - Prob. 6.34QPCh. 6 - Prob. 6.35QPCh. 6 - Prob. 6.36QPCh. 6 - Prob. 6.37QPCh. 6 - Prob. 6.38QPCh. 6 - Prob. 6.39QPCh. 6 - Prob. 6.40QPCh. 6 - Prob. 6.41QPCh. 6 - Prob. 6.42QPCh. 6 - Prob. 6.43QPCh. 6 - Prob. 6.44QPCh. 6 - Prob. 6.45QPCh. 6 - Prob. 6.46QPCh. 6 - Prob. 6.47QPCh. 6 - Prob. 6.48QPCh. 6 - Prob. 6.49QPCh. 6 - Prob. 6.50QPCh. 6 - Prob. 6.51QPCh. 6 - Prob. 6.52QPCh. 6 - Prob. 6.53QPCh. 6 - Prob. 6.54QPCh. 6 - Prob. 6.55QPCh. 6 - Prob. 6.56QPCh. 6 - Prob. 6.57QPCh. 6 - Prob. 6.58QPCh. 6 - Prob. 6.59QPCh. 6 - Prob. 6.60QPCh. 6 - Prob. 6.61QPCh. 6 - Prob. 6.62QPCh. 6 - Prob. 6.63QPCh. 6 - Prob. 6.64QPCh. 6 - Prob. 6.65QPCh. 6 - Prob. 6.66QPCh. 6 - Prob. 6.67QPCh. 6 - Prob. 6.68QPCh. 6 - Prob. 6.69QPCh. 6 - Prob. 6.70QPCh. 6 - Prob. 6.71QPCh. 6 - Prob. 6.72QPCh. 6 - Prob. 6.73QPCh. 6 - Prob. 6.74QPCh. 6 - Prob. 6.75QPCh. 6 - Prob. 6.76QPCh. 6 - Prob. 6.77QPCh. 6 - Prob. 6.78QPCh. 6 - Prob. 6.79QPCh. 6 - Prob. 6.80QPCh. 6 - Prob. 6.81QPCh. 6 - Prob. 6.82QPCh. 6 - Prob. 6.83QPCh. 6 - Prob. 6.84QPCh. 6 - Prob. 6.85QPCh. 6 - Prob. 6.86QPCh. 6 - Prob. 6.87QPCh. 6 - Prob. 6.88QPCh. 6 - Prob. 6.89QPCh. 6 - Prob. 6.90QPCh. 6 - Prob. 6.91QPCh. 6 - Prob. 6.92QPCh. 6 - Prob. 6.93QPCh. 6 - Prob. 6.94QPCh. 6 - Prob. 6.95QPCh. 6 - Prob. 6.96QPCh. 6 - Prob. 6.97QPCh. 6 - Prob. 6.98QPCh. 6 - Prob. 6.99QPCh. 6 - Prob. 6.100QPCh. 6 - Prob. 6.101QPCh. 6 - Prob. 6.102QPCh. 6 - Prob. 6.103QPCh. 6 - Prob. 6.104QPCh. 6 - Prob. 6.105QPCh. 6 - Prob. 6.106QPCh. 6 - Prob. 6.107QPCh. 6 - Prob. 6.108QPCh. 6 - Prob. 6.109QPCh. 6 - Prob. 6.110QPCh. 6 - Prob. 6.111QPCh. 6 - Prob. 6.112QPCh. 6 - Prob. 6.113QPCh. 6 - Prob. 6.114QPCh. 6 - Prob. 6.115QPCh. 6 - Prob. 6.116QPCh. 6 - Prob. 6.117QPCh. 6 - Prob. 6.118QPCh. 6 - Prob. 6.119QPCh. 6 - Prob. 6.120QPCh. 6 - Prob. 6.121QPCh. 6 - Prob. 6.122QPCh. 6 - Prob. 6.123QPCh. 6 - Prob. 6.124QPCh. 6 - Prob. 6.125QPCh. 6 - Prob. 6.126QPCh. 6 - Prob. 6.127QPCh. 6 - Prob. 6.128QPCh. 6 - Prob. 6.129QPCh. 6 - Prob. 6.130QPCh. 6 - Prob. 6.131QPCh. 6 - Prob. 6.132QPCh. 6 - Prob. 6.133QPCh. 6 - Prob. 6.134QPCh. 6 - Prob. 6.135QPCh. 6 - Prob. 6.136QPCh. 6 - Prob. 6.137QPCh. 6 - Prob. 6.138QPCh. 6 - Prob. 6.139QPCh. 6 - Prob. 6.140QPCh. 6 - Prob. 6.141QPCh. 6 - Prob. 6.142QPCh. 6 - Prob. 6.143QPCh. 6 - Prob. 6.144QPCh. 6 - Prob. 6.145APCh. 6 - Prob. 6.146APCh. 6 - Prob. 6.147APCh. 6 - Prob. 6.148APCh. 6 - Prob. 6.149APCh. 6 - Prob. 6.150APCh. 6 - Prob. 6.151APCh. 6 - Prob. 6.152APCh. 6 - Prob. 6.153APCh. 6 - Prob. 6.154APCh. 6 - Prob. 6.155APCh. 6 - Prob. 6.156APCh. 6 - Prob. 6.157APCh. 6 - Prob. 6.158APCh. 6 - Prob. 6.159APCh. 6 - Prob. 6.160APCh. 6 - Prob. 6.161APCh. 6 - Prob. 6.162APCh. 6 - Prob. 6.163APCh. 6 - Prob. 6.164APCh. 6 - Prob. 6.165APCh. 6 - Prob. 6.166APCh. 6 - Prob. 6.167APCh. 6 - Prob. 6.168APCh. 6 - Prob. 6.169APCh. 6 - Prob. 6.170APCh. 6 - Prob. 6.171APCh. 6 - Prob. 6.172APCh. 6 - Prob. 6.173APCh. 6 - Prob. 6.174APCh. 6 - Prob. 6.175APCh. 6 - Prob. 6.176APCh. 6 - Prob. 6.177APCh. 6 - Prob. 6.178APCh. 6 - Prob. 6.179APCh. 6 - Prob. 6.180APCh. 6 - Prob. 6.181APCh. 6 - Prob. 6.182APCh. 6 - Prob. 6.183APCh. 6 - Prob. 6.184APCh. 6 - Prob. 6.185APCh. 6 - Prob. 6.186APCh. 6 - Prob. 6.187APCh. 6 - Prob. 6.188AP
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